Problem 7
Question
Use the Monotonicity Theorem to find where the given function is increasing and where it is decreasing. $$ h(z)=\frac{z^{4}}{4}-\frac{4 z^{3}}{6} $$
Step-by-Step Solution
Verified Answer
Function is increasing for \( z > 2 \) and decreasing for \( z < 2 \).
1Step 1: Find the derivative of the function
The first step in applying the Monotonicity Theorem is to find the derivative of the function. Given \( h(z) = \frac{z^4}{4} - \frac{4z^3}{6} \), we need to calculate \( h'(z) \): \[ h'(z) = \frac{d}{dz} \left( \frac{z^4}{4} \right) - \frac{d}{dz} \left( \frac{4z^3}{6} \right) \] Using power rules for derivatives:\[ h'(z) = \frac{4z^3}{4} - \frac{12z^2}{6} = z^3 - 2z^2 \].
2Step 2: Identify the relevant trigonometric identities
Based on the given expression or equation, identify which trigonometric identities (Pythagorean, double-angle, sum/difference, etc.) are applicable.
3Step 3: Apply the identities and simplify
Apply the identified identities to transform the expression. Simplify step by step, combining like terms and reducing fractions where possible.
4Step 4: Solve or evaluate
If solving an equation, isolate the trigonometric function and find the angle(s). If evaluating, compute the final numerical value.
5Step 5: State the result
Express the final answer, including all solutions in the required domain if solving an equation.
6Step 6: Conclude with the answer
Function is increasing for \( z > 2 \) and decreasing for \( z < 2 \).
Key Concepts
DerivativeIncreasing and Decreasing FunctionsCalculus Problem-Solving
Derivative
In calculus, a derivative gives us important information about how a function changes. When finding the derivative of a function, we track how its output changes as the input changes. This is known as the rate of change. For a function like \( h(z) = \frac{z^4}{4} - \frac{4z^3}{6} \), finding the derivative \( h'(z) \) involves using the power rule. The power rule helps calculate derivatives of functions in the form of \( x^n \), resulting in \( nx^{n-1} \).
Let's break down the derivative of \( h(z) \):
When evaluating a derivative, you learn about the function's behavior at any point along its domain. These insights are crucial for determining increasing or decreasing trends, which lead us to understand thoroughly how the function behaves.
Let's break down the derivative of \( h(z) \):
- The derivative of \( \frac{z^4}{4} \) is \( \frac{4z^3}{4} = z^3 \).
- The derivative of \( -\frac{4z^3}{6} \) is \( -\frac{12z^2}{6} = -2z^2 \).
When evaluating a derivative, you learn about the function's behavior at any point along its domain. These insights are crucial for determining increasing or decreasing trends, which lead us to understand thoroughly how the function behaves.
Increasing and Decreasing Functions
Understanding when a function is increasing or decreasing is key to analyzing its behavior. A function is increasing on intervals where its derivative is positive, and decreasing where its derivative is negative.
The critical points of a function occur where its derivative \( h'(z) \) is zero or undefined. Solving \( h'(z) = z^3 - 2z^2 = 0 \) will pinpoint the function's critical points. We can factor it as \( z^2(z - 2) = 0 \), yielding solutions at \( z = 0 \) and \( z = 2 \).
We further analyze the intervals around these critical points to determine where the function is increasing or decreasing:
The critical points of a function occur where its derivative \( h'(z) \) is zero or undefined. Solving \( h'(z) = z^3 - 2z^2 = 0 \) will pinpoint the function's critical points. We can factor it as \( z^2(z - 2) = 0 \), yielding solutions at \( z = 0 \) and \( z = 2 \).
We further analyze the intervals around these critical points to determine where the function is increasing or decreasing:
- For \( z < 0 \), test \( h'(z) \) to check if it is positive or negative.
- For \( 0 < z < 2 \), test again to see function's behavior.
- For \( z > 2 \), another test to reveal increase or decrease.
Calculus Problem-Solving
Calculus problem-solving equips us with the tools needed to tackle various mathematical puzzles involving rates of change and accumulations. The Monotonicity Theorem is a powerful tool in this context, allowing us to identify where a function shifts from increasing to decreasing or vice versa.
The process often starts with differential calculus, which utilizes derivatives to analyze function behavior.
Let's recap how to solve problems like these:
The process often starts with differential calculus, which utilizes derivatives to analyze function behavior.
Let's recap how to solve problems like these:
- Take the derivative of the function using appropriate rules (like the power rule).
- Solve for critical points by setting the derivative equal to zero.
- Determine intervals of increase or decrease by evaluating the sign of the derivative around the critical points.
Other exercises in this chapter
Problem 7
What number exceeds its square by the maximum amount? Begin by convincing yourself that this number is on the interval \([0,1]\).
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Identify the critical points. Then use (a) the First Derivative Test and (if possible) (b) the Second Derivative Test to decide which of the critical points giv
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Identify the critical points and find the maximum value and minimum value on the given interval. $$ \Psi(x)=x^{2}+3 x ; I=[-2,1] $$
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The population of the United States was \(3.9\) million in 1790 and 178 million in 1960 . If the rate of growth is assumed proportional to the number present, w
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