Problem 7
Question
To ____ the polynomial \(x^{2}-2 x+1\) for \(x=6,\) we substitute 6 for \(x\) and follow the rules for the order of operations.
Step-by-Step Solution
Verified Answer
The polynomial evaluates to 25 when \(x = 6\).
1Step 1: Substitute 6 into the polynomial
Replace every instance of the variable \(x\) in the polynomial \(x^2 - 2x + 1\) with 6. This gives us the expression \(6^2 - 2 \times 6 + 1\).
2Step 2: Calculate the exponent
Evaluate \(6^2\), which means calculating \(6\times6\). This results in 36. So, the expression becomes \(36 - 2 \times 6 + 1\).
3Step 3: Multiply
Next, we need to multiply \(-2\) by 6. This results in \(-12\). Now the expression is \(36 - 12 + 1\).
4Step 4: Perform addition and subtraction
Now, perform the subtraction and then the addition from left to right: \(36 - 12 = 24\), and then \(24 + 1 = 25\).
Key Concepts
Substitution MethodOrder of OperationsPolynomial Expressions
Substitution Method
The substitution method is a handy technique for evaluating polynomial expressions. It involves replacing the variable in the expression with a given number. In our exercise, we are given the polynomial \(x^{2} - 2x + 1\) and need to evaluate it for \(x = 6\). By substituting, we replace every occurrence of \(x\) with the number 6. This transforms our polynomial into numerical form, making it simpler to calculate. Using the substitution method allows us to focus on numerical computation rather than manipulation of algebraic expressions. It's a straightforward process:
- Identify the variable to substitute.
- Replace the variable with the given number in the expression.
Order of Operations
After substitution, the key to correctly evaluating the expression \(6^2 - 2 \times 6 + 1\) is applying the order of operations. The order of operations can be remembered by the acronym PEMDAS:
- P: Parentheses
- E: Exponents
- M: Multiplication
- D: Division
- A: Addition
- S: Subtraction
Polynomial Expressions
Polynomial expressions consist of variables and coefficients combined using addition, subtraction, and multiplication, raised to non-negative integer powers. In the polynomial \(x^2 - 2x + 1\), we see:
- The term \(x^2\) with a power of 2.
- The linear term \(-2x\) with a power of 1.
- The constant term 1.
Other exercises in this chapter
Problem 7
Simplify each polynomial by combining like terms. a. \(6 x^{2}-8 x+9 x-12\) b. \(5 x^{4}+3 a x^{2}+5 a x^{2}+3 a^{2}\)
View solution Problem 7
Simplify each polynomial, if possible. a. \(2 x^{2}+3 x^{2}\) b. \(15 m^{3}-m^{3}\) c. \(8 a^{3} b-a^{3} b\) d. \(6 c d+4 c^{2} d\)
View solution Problem 7
Simplify each expression, if possible. A. \(x^{2}+x^{2}\) B. \(x^{2} \cdot x^{2}\) C. \(x^{2}+x\) D. \(x^{2} \cdot x\)
View solution Problem 7
Complete each table. \(\begin{array}{|r|r|}\hline x & {3^{x}} \\ \hline 2 & {} \\ \hline 1 & {} \\\ \hline 0 & {} \\ \hline-1 & {} \\ \hline-2 & {} \\ \hline\en
View solution