Problem 7
Question
The starship Enterprise, of television and movie fame, is powered by combining matter and antimatter. If the entire \(400-\mathrm{kg}\)\ antimatter fuel supply of the Enterprise combines with matter how much energy is released? How does this compare to the U.S. yearly energy use, which is roughly 1.0 \(\times 10^{20} \mathrm{J} ?\)
Step-by-Step Solution
Verified Answer
The energy released is \(7.2 \times 10^{19} \ \text{J}\), 72% of U.S. yearly energy use.
1Step 1: Understanding Matter-Antimatter Annihilation
Matter and antimatter annihilation converts their mass into energy, following the mass-energy equivalence principle which is given by Einstein's equation: \(E=mc^2\). Here, \(m\) is the mass and \(c\) is the speed of light (\(c = 3.0 \times 10^8 \ \text{m/s}\)).
2Step 2: Calculating Total Mass Involved
The total mass involved in the reaction is the sum of the matter and antimatter mass. The antimatter mass is \(400\ \text{kg}\), and it combines with an equal mass of matter, so total mass \(m = 400 \ \text{kg} + 400 \ \text{kg} = 800 \ \text{kg}\).
3Step 3: Calculating Released Energy
Apply the formula \(E = mc^2\) to find the energy released. Substitute \(m = 800\ \text{kg}\) and \(c = 3.0 \times 10^8 \ \text{m/s}\): \[E = 800 \ \text{kg} \times (3.0 \times 10^8 \ \text{m/s})^2 = 7.2 \times 10^{19} \ \text{J}\].
4Step 4: Comparison with U.S. Yearly Energy Use
The energy released \(7.2 \times 10^{19} \ \text{J}\) can be compared with the U.S. yearly energy use. Calculate the ratio of released energy to U.S. energy use: \[\frac{7.2 \times 10^{19}}{1.0 \times 10^{20}} = 0.72\]. This means the released energy is 72% of the U.S. yearly energy consumption.
Key Concepts
Mass-Energy EquivalenceRelativistic PhysicsEnergy Calculation
Mass-Energy Equivalence
In the realm of physics, understanding how mass translates into energy is crucial. This idea is beautifully encapsulated in Einstein's famous equation, \(E=mc^2\).
- \(E\) represents the energy produced.
- \(m\) is the mass undergoing transformation.
- \(c\) is the speed of light, approximately \(3.0 \times 10^8 \, \text{m/s}\).
Relativistic Physics
Relativistic physics extends classical mechanics to include what happens when objects move close to the speed of light.
- In such scenarios, we need to account for increases in mass and the time-slowing effects described by Einstein.
- In our case, we're considering mass as a form of energy storage.
Energy Calculation
Calculating the energy released from matter-antimatter annihilation involves straightforward application of \(E = mc^2\). Here's a step-by-step breakdown:
- First, identify the total mass involved, which is the sum of the masses of matter and antimatter. In this example, it's \(400 \, \text{kg} + 400 \, \text{kg} = 800 \, \text{kg}\).
- Next, substitute this mass and the speed of light into the equation: \[E = 800 \, \text{kg} \times (3.0 \times 10^8 \, \text{m/s})^2\]
Other exercises in this chapter
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