Problem 7
Question
The reaction gives $$ \mathrm{CH}_{3} \mathrm{CONH}_{2} \frac{\mathrm{NaOBr}}{\mathrm{H}_{2} \mathrm{O}} $$ (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (b) \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{CN}\) (d) \(\mathrm{CH}_{1} \mathrm{Br}\)
Step-by-Step Solution
Verified Answer
(b) \(\mathrm{CH}_{3}\mathrm{NH}_{2}\)
1Step 1: Identify the Reaction Type
The given reaction involves the use of NaOBr and water, which indicates a Hofmann rearrangement. This is a well-known reaction in organic chemistry where an amide is converted into an amine with one fewer carbon atom.
2Step 2: Predict the Reaction Outcome
In a Hofmann rearrangement, the carbonyl group in the amide \(\mathrm{CH}_{3}\mathrm{CONH}_{2}\) is removed, leading to the formation of a primary amine with one less carbon. This typically transforms the molecule from acetylamide (1 carbon) to methylamine (1 carbon).
3Step 3: Determine the Product
For the given amide \(\mathrm{CH}_{3}\mathrm{CONH}_{2}\), the application of the Hofmann rearrangement will break the C-N bond, lose a carbon as CO2, and produce a primary amine. The expected product is \(\mathrm{CH}_{3}\mathrm{NH}_{2}\).
4Step 4: Select the Correct Option
The product of the reaction is \(\mathrm{CH}_{3}\mathrm{NH}_{2}\), which corresponds to option (b) in the given list of products.
Key Concepts
Organic ChemistryAmide to Amine ConversionMechanism of Hofmann Rearrangement
Organic Chemistry
Organic chemistry is a branch of chemistry focused on the structure, properties, composition, reactions, and synthesis of carbon-containing compounds. It encompasses a vast variety of compounds, including those that derive from living matter as well as synthetic ones. One important facet of organic chemistry is understanding the mechanisms of how molecules transform through chemical reactions.
Reactions such as the Hofmann rearrangement are crucial because they illustrate how certain functional groups in organic compounds can be modified or changed into other groups. These transformations are essential in the synthesis of complex molecules and have broad applications across pharmaceuticals, materials science, and biological chemistry.
The principles of organic chemistry also help us predict the types of reactions that might occur under certain conditions and the likely products that will result. In the realm of amine synthesis, understanding how an amide can transform into an amine provides insight into developing synthetic routes for creating specific compounds.
Reactions such as the Hofmann rearrangement are crucial because they illustrate how certain functional groups in organic compounds can be modified or changed into other groups. These transformations are essential in the synthesis of complex molecules and have broad applications across pharmaceuticals, materials science, and biological chemistry.
The principles of organic chemistry also help us predict the types of reactions that might occur under certain conditions and the likely products that will result. In the realm of amine synthesis, understanding how an amide can transform into an amine provides insight into developing synthetic routes for creating specific compounds.
Amide to Amine Conversion
The conversion of an amide to an amine is a key transformation in organic chemistry, especially when using the Hofmann rearrangement. Amides are general compounds with the structure RCONH2, where R is an organic group. During this conversion, amides lose a carbon group and are transformed into primary amines.
This reaction is significant due to its ability to reduce the carbon chain length by one, which can be useful in various synthetic processes where simpler amines are needed. In the Hofmann rearrangement process, the nitrogen atom is drafted into the carbon-containing chain, while a carbon atom from the original amide is expelled as carbon dioxide.
The specific reaction often used is with NaOBr, a reagent that facilitates the rearrangement and excision of the carbon atom. This is especially useful for converting substances such as acetamide into simpler amines like methylamine, thereby altering both the structure and function of the original molecule.
This reaction is significant due to its ability to reduce the carbon chain length by one, which can be useful in various synthetic processes where simpler amines are needed. In the Hofmann rearrangement process, the nitrogen atom is drafted into the carbon-containing chain, while a carbon atom from the original amide is expelled as carbon dioxide.
The specific reaction often used is with NaOBr, a reagent that facilitates the rearrangement and excision of the carbon atom. This is especially useful for converting substances such as acetamide into simpler amines like methylamine, thereby altering both the structure and function of the original molecule.
Mechanism of Hofmann Rearrangement
The Hofmann rearrangement outlines a fascinating mechanism in organic chemistry which allows for the transformation of an amide into an amine with the concurrent loss of a carbon atom. The mechanism involves several steps that result in the net loss of the carbonyl group from the amide.
1. **Initial Stage**: The amide is treated with sodium hypobromite (NaOBr), initiating the deprotonation of the amide and formation of a bromamide intermediate.
2. **Rearrangement**: An intramolecular rearrangement occurs where the nitrogen atom migrates over to the carbon previously bonded to the carbonyl group. This step is facilitated by the formation of a nitrene intermediate.
3. **Decarboxylation**: The rearranged molecule loses carbon dioxide, resulting in a negatively charged nitrogen compound that quickly rearranges into an amine with the release of one carbon less than the starting amide.
This mechanism is vital for creating simpler amine compounds and is noted for its unique ability to alter the carbon skeleton of the starting material. Understanding each step is crucial for successfully applying the Hofmann rearrangement in synthetic organic chemistry.
1. **Initial Stage**: The amide is treated with sodium hypobromite (NaOBr), initiating the deprotonation of the amide and formation of a bromamide intermediate.
2. **Rearrangement**: An intramolecular rearrangement occurs where the nitrogen atom migrates over to the carbon previously bonded to the carbonyl group. This step is facilitated by the formation of a nitrene intermediate.
3. **Decarboxylation**: The rearranged molecule loses carbon dioxide, resulting in a negatively charged nitrogen compound that quickly rearranges into an amine with the release of one carbon less than the starting amide.
This mechanism is vital for creating simpler amine compounds and is noted for its unique ability to alter the carbon skeleton of the starting material. Understanding each step is crucial for successfully applying the Hofmann rearrangement in synthetic organic chemistry.
Other exercises in this chapter
Problem 5
\(\beta\) hydroxy esters can be formed by (a) Claisen condensation (b) Tischenko condensation (c) Reformatsky reaction (d) Knoevengel reaction
View solution Problem 6
-azmgel reaction The reducing property of HCOOH is due to the following group (a) \(-\mathrm{COOH}\) (b) \(-\mathrm{OH}\) (c) \(-\mathrm{CHO}\) (d) \(-\mathrm{H
View solution Problem 8
The most apporopriate reagent for the conversion of 2 -pentanone to butanoic acid is (a) \(\mathrm{NaO}: \mathrm{H}_{3} \mathrm{O}^{+}\) (b) \(\mathrm{KMnO}_{4}
View solution Problem 10
H. Acetic acid dissolved in benzene has an apparent molecular mass of (a) 30 (b) 60 (c) 120 (d) 140
View solution