Problem 7
Question
Solve each of the following word problems by translating the statement into a proportion. Be sure to show the proportion used in each case. [Examples \(1-4]\) Map Reading The scale on a map indicates that 1 inch corresponds to an actual distance of 95 miles. Two cities are 4.5 inches apart on the map. What is the actual distance between the two cities?
Step-by-Step Solution
Verified Answer
The actual distance is 427.5 miles.
1Step 1: Understand the problem
We need to find the actual distance between two cities using the scale given on a map. The map indicates that 1 inch corresponds to 95 miles.
2Step 2: Set up the known proportion
We have a scale of 1 inch to 95 miles. This can be expressed as the proportion \( \frac{1 \text{ inch}}{95 \text{ miles}} \).
3Step 3: Set up the unknown proportion
We know the distance between the cities on the map is 4.5 inches, but we need to find the actual distance in miles. This is expressed as the proportion \( \frac{4.5 \text{ inches}}{x \text{ miles}} \), where \( x \) is the unknown actual distance.
4Step 4: Write the proportion equation
Using the known proportion and the unknown proportion, set up the equation: \( \frac{1}{95} = \frac{4.5}{x} \).
5Step 5: Solve the proportion equation
Cross-multiply to solve for \( x \). This gives us \( 1 \cdot x = 95 \cdot 4.5 \). Simplify to get \( x = 427.5 \text{ miles} \).
6Step 6: Conclude the solution
We've found that the actual distance between the two cities is 427.5 miles based on the map scale.
Key Concepts
Map ReadingDistance CalculationCross-Multiplication
Map Reading
When you look at a map, you are actually looking at a scaled-down representation of a much larger area.
Maps are incredibly useful tools for understanding geography, planning routes, and solving problems like the one in the exercise. One important aspect of map reading is understanding and correctly interpreting the scale.
- Scale Information: The scale on a map tells you about the relationship between a certain distance on the map and the actual distance in real life. For example, a scale of 1 inch to 95 miles indicates that for every inch you measure on the map, the real-world distance is 95 miles.
- Interpreting Distances: To find out how far two locations are apart in reality, you measure the distance between them on the map and then use the scale to convert that measurement into an actual distance.
Distance Calculation
Calculating distances using map scales involves some straightforward math. Once you understand the scale, you can easily convert map measurements into real-world distances by applying that scale.
- Measuring Distance on the Map: Use a ruler to measure the distance between the two points you're interested in. Record this measurement carefully.
- Applying the Scale: With the scale known, multiply the map distance by the scale factor to find the real-world distance. In our exercise, 4.5 inches on the map equals 4.5 times 95 miles in reality.
Cross-Multiplication
Cross-multiplication is a key technique in solving proportion problems, like finding actual distances on maps. It helps you find an unknown value in a proportion by multiplying across the equals sign.
- Proportion Setup: A proportion is an equation that states two ratios are equal. For the map problem, the ratios are the map scale and the measured distance.
- Cross-Multiplying: To solve for the unknown, cross-multiply the terms. For instance, with the equation \( \frac{1}{95} = \frac{4.5}{x} \), multiply 1 by \( x \) and 95 by 4.5 to get \( 1 \cdot x = 95 \cdot 4.5 \).
- Solving for the Variable: After cross-multiplying, solve for the variable by performing any necessary division or simplification. In this case, \( x = 427.5 \).
Other exercises in this chapter
Problem 6
For each of the following proportions, name the means, name the extremes, and show that the product of the means is equal to the product of the extremes. $$\fra
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Write each of the following ratios as a fraction in lowest terms. None of the answers should contain decimals. $$13 \quad to\quad 26$$
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Express each of the following rates as a ratio with the given units. Liters/Minute It takes 4 minutes to fill a 56 -liter gas tank. What is the rate in liters p
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For each of the following proportions, name the means, name the extremes, and show that the product of the means is equal to the product of the extremes. $$\fra
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