Problem 7
Question
Solve each equation for solutions over the interval \([0,2 \pi)\) by first solving for the trigonometric finction. Do not use a calculator. $$2 \cos x+5=6$$
Step-by-Step Solution
Verified Answer
The solutions are \(x = \frac{\pi}{3}\) and \(x = \frac{5\pi}{3}\).
1Step 1: Isolate the Trigonometric Function
We start with the equation: \[ 2 \cos x + 5 = 6 \]First, subtract 5 from both sides to isolate the term with cosine:\[ 2 \cos x = 6 - 5 \]This simplifies to:\[ 2 \cos x = 1 \]
2Step 2: Solve for Cosine Value
Next, divide both sides by 2 to solve for \(\cos x\):\[ \cos x = \frac{1}{2} \]
3Step 3: Find General Solutions
We need to determine the values of \(x\) in the range \([0, 2\pi)\) that make \(\cos x = \frac{1}{2}\).\The cosine function equals \(\frac{1}{2}\) at specific standard angles in radians: \(\frac{\pi}{3}\) and \(\frac{5\pi}{3}\).
4Step 4: Verify Solutions in Interval
Ensure the solutions found in Step 3 lie within the interval \([0, 2\pi)\).\Both \(\frac{\pi}{3}\) and \(\frac{5\pi}{3}\) are in this interval, so these are both valid solutions.
Key Concepts
Interval NotationRadiansCosine FunctionGeneral Solutions
Interval Notation
Interval notation is a way to describe a set of numbers between two endpoints. It uses brackets [ ] and parentheses ( ) to indicate whether the endpoints are included or not. For example:
This is important because trigonometric functions are periodic, meaning they repeat their values over certain intervals.
- "[a, b]" means all numbers between a and b, including both a and b.
- "(a, b)" means all numbers between a and b, but not including a or b.
- When using "[a, b)", it includes a but not b, making it a half-open interval.
This is important because trigonometric functions are periodic, meaning they repeat their values over certain intervals.
Radians
Radians are a unit of angular measurement used in trigonometry. Unlike degrees, which divide a full circle into 360 parts, radians relate to the π constant, where a full circle is 2π radians.
- One full circle = 2π radians
- Half a circle or a semicircle is π radians
- A right angle is \( \frac{\pi}{2} \) radians
Cosine Function
The cosine function is a fundamental trigonometric function represented as \( \cos x \). It takes an angle as input and returns a ratio, which is the adjacent side over the hypotenuse in a right triangle.
- The function is periodic with a period of \( 2\pi \), meaning it repeats every \( 2\pi \).
- It ranges between -1 and 1 for all input values.
- Important values occur at standard angles like \( \frac{\pi}{3} \) where \( \cos(\frac{\pi}{3}) = \frac{1}{2} \).
General Solutions
General solutions refer to the complete set of solutions to a trigonometric equation over all possible intervals. Since trigonometric functions are periodic, they repeat their values, meaning a solution will occur in multiple periods unless restricted to a certain interval.
- When you find a solution to \( \cos x = \frac{1}{2} \), it initially leads you to solutions like \( \frac{\pi}{3} \) and \( \frac{5\pi}{3} \) within \([0, 2\pi)\).
- Using these, general solutions are represented as: \( x = \frac{\pi}{3} + 2k\pi \) and \( x = \frac{5\pi}{3} + 2k\pi \) for any integer \( k \).
- These equations indicate that every full cycle ( \( 2\pi \)) repeats the solutions found.
Other exercises in this chapter
Problem 6
Use identities to find the exact value of each expression. Do not use a calculator. $$\tan \frac{\pi}{12}$$
View solution Problem 7
Solve each equation over the interval \([0,2 \pi)\) $$\sin 2 x=2 \cos ^{2} x$$
View solution Problem 7
Write short answers and fill in the blanks. Consider the inverse sine function \(y=\sin ^{-1} x,\) or \(y=\arcsin x\) (a) What is its domain? (b) What is its ra
View solution Problem 7
Use the even-odd identities to write of the following expressions as a trigonometric function of a positive number $$\cos (-4.38)$$
View solution