Problem 7
Question
Sketch the level curves for \(f\) when (a) \(f(x, y)=y^{2}-x\) (b) \(f(p)=|p|-1\) (c) \(f(p)=\left\\{\begin{array}{ll}1 & \text { when }|p|<1 \\ x-y & \text { when }|p| \geq 1\end{array}\right.\)
Step-by-Step Solution
Verified Answer
1. For \(f(x, y)=y^{2}-x\), the level curves are families of parabolas. 2. For \(f(p)=|p|-1\), the level curves are lines parallel to the axes. There are no curves for values of < 0. For values > 0, the level curves are a set of two lines at \(c + 1\) and \(c - 1\). 3. For the defined function, the level curves are circles with radius < 1 for \(|p| < 1\) and lines with slope 1 for \(|p| \geq 1\), not including the area inside the circle with radius 1.
1Step 1: Sketching Level Curves for \(f(x, y)=y^{2}-x\)
The level curves for \( f(x, y) = y^2 - x \) are found when we set \( f(x, y) \) equal to a constant, \( c \), which gives us \( y^2 - x = c \). Solving for \( x \), we get \( x = y^2 - c \). This equation represents a family of parabolas that open to the right if \( c \) is negative, and to the left if \( c \) is positive.
2Step 2: Sketching Level Curves for \(f(p)=|p|-1\)
Since \( p \) is not clarified, let us consider \( p \) as a one-variable input. The level curves for \( f(p) = |p| - 1 \) are lines in the 2D-plane, parallel to the axes. When determining the level curves of \( f(p) = c \), for \( c < 0 \), there is no solution, as the absolute value of any real number cannot be less than one. For \( c = 0 \), the level curve will be the line \( p = 1 \) and \( p = -1 \). For \( c > 0 \), the level curves will be \( p = c + 1 \) and \( p = -c - 1 \)
3Step 3: Sketching Level Curves for \( f(p) = \{1 \text{ when }|p|<1, \text{ and } x - y \text{ when }|p| \geq 1\} \)
For \( |p| < 1 \), the function \( f(p) \) is a constant and equal to 1. This represents level curves as circles around the origin with radius less than 1. For \( |p| \geq 1 \), the level curves of the function \( f(p) = x - y \) are lines with slope 1 in the 2D-plane. However, these lines will only exist outside the circle of radius 1 around the origin.
Key Concepts
ParabolasAbsolute Value FunctionPiecewise Functions
Parabolas
Parabolas are a type of curve found in algebra and geometry, often shaped like a 'U' or an inverted 'U'. They can be described mathematically by quadratic equations. In our exercise, parabolas emerge when analyzing the function \( f(x, y) = y^2 - x \). The reason these curves are parabolas is that they fit the equation \( y^2 = x + c \), which is a standard form for a parabola.Parabolas have distinct features including:
- Vertex: The highest or lowest point on the curve, depending on its orientation.
- Axis of Symmetry: A line that splits the parabola into two mirror-image halves.
- Focus and Directrix: Used to precisely define the shape and position of the parabola.
Absolute Value Function
The absolute value function is a fundamental piece of algebra that turns any number into its non-negative equivalent. It’s represented as \( |p| \), and acts like a mirror of sorts, reflecting negative values into positive ones. In our context, we use the absolute value function in \( f(p) = |p| - 1 \).Understanding how this function works is key:
- Symmetry: The graph of an absolute value function is V-shaped and symmetric about the y-axis.
- No Negative Outputs: Since it measures the "distance" from zero, its result is never negative.
- Cases: We often break it into cases. For \( p \geq 0 \), \( |p| = p \), and for \( p < 0 \), \( |p| = -p \).
Piecewise Functions
Piecewise functions let us describe situations where a function has different expressions based on the input value or range of the input. They are extremely useful in representing real-world scenarios or complex mathematical relationships. In the exercise, \( f(p) = \begin{cases} 1, & \text{if } |p| < 1 \ x-y, & \text{if } |p| \geq 1 \end{cases} \) is an example of a piecewise function.Here's how to understand and use these functions:
- Multiple Definitions: Define different outputs for different domains of the input.
- Graphical Implications: The graph will have disjoint sections, each reflecting its specific rule.
- Continuity: Piecewise functions can be continuous if the values meet or break at transition points smoothly.
Other exercises in this chapter
Problem 7
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