Problem 7
Question
Six \(50.0-\mathrm{W}\) bulbs are operated for \(25.0 \mathrm{~h}\) on a \(115-\mathrm{V}\) circuit. If energy costs $$\$ 0.075$$ per $\mathrm{kWh}$$, find the cost of operating them.
Step-by-Step Solution
Verified Answer
The cost of operating them is $0.56.
1Step 1: Calculate Total Energy Consumption
First, find out how much energy the bulbs use in total. Each bulb is rated at \(50.0\) watts and runs for \(25.0\) hours, so the energy used by one bulb is \(50.0 \, \text{W} \times 25.0 \, \text{h} = 1250 \, \text{Wh} = 1.25 \, \text{kWh}\). As there are 6 bulbs, the total energy consumed is \(6 \times 1.25 \, \text{kWh} = 7.5 \, \text{kWh}\).
2Step 2: Calculate the Total Cost of Energy
Now, calculate the cost for the total energy consumed. The cost per kilowatt-hour is \(\\(0.075\). Therefore, the cost is \(7.5 \, \text{kWh} \times \\)0.075 \, \text{per kWh} = \$0.5625\).
3Step 3: Convert Calculation to Cost
To express the cost as money, round \\(0.5625 to two decimal places, which gives a final answer of \\)0.56.
Key Concepts
electricity consumptionpower and energycost per kilowatt-hour
electricity consumption
Electricity consumption refers to the amount of electric energy used by an appliance over a certain period. Understanding this concept is essential when calculating energy costs.
For our example, each bulb has a power rating of 50 watts, which means they consume energy at a rate of 50 joules per second.
If a bulb operates for 25 hours, the total electricity consumption becomes 1,250 watt-hours (Wh), which we convert to kilowatt-hours (kWh) by dividing by 1,000.
Thus, one bulb uses 1.25 kWh, and for six bulbs the total electricity consumption is 7.5 kWh. This calculation is an essential first step in figuring out energy costs.
For our example, each bulb has a power rating of 50 watts, which means they consume energy at a rate of 50 joules per second.
If a bulb operates for 25 hours, the total electricity consumption becomes 1,250 watt-hours (Wh), which we convert to kilowatt-hours (kWh) by dividing by 1,000.
Thus, one bulb uses 1.25 kWh, and for six bulbs the total electricity consumption is 7.5 kWh. This calculation is an essential first step in figuring out energy costs.
power and energy
Power and energy are closely related but distinct concepts in physics.
Power measures the rate at which energy is used or transferred and is measured in watts (W), where 1 watt equals 1 joule per second.
Energy, on the other hand, signifies the total amount of work or heat done and is commonly measured in kilowatt-hours (kWh) for electricity purposes.
Power measures the rate at which energy is used or transferred and is measured in watts (W), where 1 watt equals 1 joule per second.
Energy, on the other hand, signifies the total amount of work or heat done and is commonly measured in kilowatt-hours (kWh) for electricity purposes.
- Each 50-W bulb uses power at a constant rate, continuously consuming energy as it burns.
- The energy consumed over time is the total power multiplied by the time in hours.
cost per kilowatt-hour
The cost per kilowatt-hour (kWh) is a crucial figure in energy billing, reflecting the price at which electricity is sold.
To calculate the total cost, simply multiply the total energy consumption by the cost per kWh.
To calculate the total cost, simply multiply the total energy consumption by the cost per kWh.
- In our scenario, the energy consumption of 7.5 kWh, multiplied by the given cost of 0.075 per kWh, results in the total expense.
- This calculation indicates how much it costs to use the bulbs over the specified time period.
Other exercises in this chapter
Problem 6
An electric field of magnitude \(0.370 \mathrm{~N} / \mathrm{C}\) exerts a force of \(6.20 \times 10^{-4} \mathrm{~N}\) on a test charge placed in the field. Wh
View solution Problem 6
How far apart are two identical charges of \(+6.00 \mu \mathrm{C}\) if the force between them is \(25.0 \mathrm{~N} ?\)
View solution Problem 7
Using the formulas for series and parallel circuits, fill in the blanks in the tables shown opposite each circuit. In the blanks across from Battery under \(V\)
View solution Problem 7
A heater operates on \(22 \overline{0} \mathrm{~V}\). If it draws \(12.5 \mathrm{~A}\), what is its resistance?
View solution