Problem 7
Question
Name the conic or limiting form represented by the given equation. Usually you will need to use the process of completing the square (see Examples \(3-5) .\) y^{2}-5 x-4 y-6=0
Step-by-Step Solution
Verified Answer
Parabola.
1Step 1: Rearrange the equation
Start by moving the constant term to the other side of the equation. The given equation is \( y^2 - 5x - 4y - 6 = 0 \). Add 6 to both sides to get \( y^2 - 5x - 4y = 6 \).
2Step 2: Group variable terms
To complete the square, group the \( y \) terms together. Your equation now is: \( y^2 - 4y = 5x + 6 \).
3Step 3: Complete the square for the \( y \)-terms
Take the coefficient of \( y \), which is \(-4\), take half of it to get \(-2\), and then square it to get \(4\). Add and subtract \(4\) inside the equation to complete the square: \( (y^2 - 4y + 4) - 4 = 5x + 6 \).
4Step 4: Simplify the completed square
The left side of the equation can be rewritten as a squared term: \( (y - 2)^2 - 4 = 5x + 6 \).
5Step 5: Isolate the squared term
Move \( -4 \) to the other side of the equation: \( (y - 2)^2 = 5x + 10 \).
6Step 6: Write in standard form
Divide everything by \(5\) to match the standard form of a parabola: \( \left( y - 2 \right)^2 = 5(x + 2) \).
7Step 7: Identify the conic section
The given equation is in the standard form of a parabola \( (y - k)^2 = 4p(x - h) \). Therefore, the conic section represented by this equation is a parabola.
Key Concepts
Completing the SquareParabolasEquation Rearrangement
Completing the Square
Completing the square is a technique used to simplify quadratic expressions, making them easier to solve or manipulate. In this case, it's used to rewrite an equation into a recognizable form, such as the standard form of a parabola.The process involves creating a perfect square trinomial from a quadratic expression. Here's how it works step by step:
- Identify the quadratic and linear terms you need to complete the square. For instance, if you start with something like \(y^2 - 4y\), your goal is to turn this into a perfect square trinomial.
- Take the coefficient of the linear term, halve it, and square the result. With \(-4\) as the coefficient, the calculation becomes \((-4/2)^2 = 4\).
- Add and subtract this square within the expression. What this does is create an expression like \((y - 2)^2 - 4\), which is a perfect square minus a constant.
Parabolas
Parabolas are a type of conic section characterized by a distinct U-shaped curve. They have a few key properties and elements like the vertex, the axis of symmetry, and the focus.In this exercise, the equation is manipulated to reveal that it represents a parabola. Here's what makes an equation a parabola and the basic elements to pay attention to:
- The equation of a parabola can often be written in the form \((y-k)^2 = 4p(x-h)\) or \((x-h)^2 = 4p(y-k)\). This shows if it opens horizontally or vertically.
- The parameters \(h\) and \(k\) represent the coordinates of the vertex, the highest or lowest point (for vertical parabolas), or the furthest left or right point (for horizontal parabolas).
- The distance \(p\) is crucial as it indicates how far the focus and directrix are from the vertex.
Equation Rearrangement
Rearranging equations is a fundamental skill in solving and understanding algebraic expressions. It involves manipulating an equation to achieve a desired form or isolate particular variables.Here’s how and why rearranging an equation works:
- This process often begins by moving constants and like terms to one side of the equation. With the original problem \(y^2 - 5x - 4y - 6 = 0\), moving \(-6\) to the right-hand side helped simplify the equation to \(y^2 - 4y = 5x + 6\).
- Grouping like terms is crucial for processes like completing the square or factoring. For example, we need the \(y\) terms together when completing the square.
- Equations are often rearranged into standard forms to easily identify what conic section or geometric shape they represent. In this context, rearranging identified the equation as a parabola.
Other exercises in this chapter
Problem 6
Find the coordinates of the focus and the equation of the directrix for each parabola. Make a sketch showing the parabola, its focus, and its directrix. $$ y^{2
View solution Problem 7
Sketch the graph of the given equation and find the area of the region bounded by it. $$ r=a(1+\cos \theta), a>0 $$
View solution Problem 7
a parametric representation of a curve is given. $$ x=\frac{1}{s}, y=s ; 1 \leq s
View solution Problem 7
Name the conic (horizontal ellipse, vertical hyperbola, and so on) corresponding to the given equation. $$ 9 x^{2}+4 y^{2}=9 $$
View solution