Problem 7
Question
Multiply. $$ \sqrt{5} \sqrt{7} $$
Step-by-Step Solution
Verified Answer
\(\sqrt{5} \sqrt{7} = \sqrt{35}\)
1Step 1: Understand the Multiplication of Radicals
When multiplying two square roots, the product is the square root of the product of the radicands (the numbers inside the square roots).
2Step 2: Multiply the Radicands
Multiply the numbers inside the square roots: \(5 \times 7 = 35\).
3Step 3: Take the Square Root of the Product
The result of multiplying \( \sqrt{5} \times \sqrt{7} \) is \sqrt{35}\.
Key Concepts
square rootsradicandsproduct of radicals
square roots
Square roots are one of the basic operations in mathematics. A square root removes the square from a number. For example, the square root of 9 is 3, because 3 squared (3×3) equals 9.
Square roots are commonly denoted by the radical symbol (√). So, \(\sqrt{16} = 4\).
That is because 4 times 4 equals 16.
Remember: A square root takes us back to the number that was squared.
Square roots are commonly denoted by the radical symbol (√). So, \(\sqrt{16} = 4\).
That is because 4 times 4 equals 16.
Remember: A square root takes us back to the number that was squared.
radicands
The radicand is the number inside the square root symbol. When we write \(\sqrt{25}\), 25 is the radicand.
This value is what we find the square root of.
In our exercise, \(\sqrt{5} \text{ and } \sqrt{7}\), the numbers 5 and 7 are the radicands.
During multiplication, we multiply these radicands together like normal numbers. So, in our example, 5 multiplied by 7 gives us 35.
This means that our product of radicals will have 35 as its new radicand.
This value is what we find the square root of.
In our exercise, \(\sqrt{5} \text{ and } \sqrt{7}\), the numbers 5 and 7 are the radicands.
During multiplication, we multiply these radicands together like normal numbers. So, in our example, 5 multiplied by 7 gives us 35.
This means that our product of radicals will have 35 as its new radicand.
product of radicals
To multiply radicals, we must follow some easy steps:
Following the steps, we multiply 5 and 7, getting 35.
Then we place this product inside a square root, resulting in \(\sqrt{35}.\)
This product of radicals simplifies the expression and shows us the answer.
- First, multiply the radicands (numbers inside the square roots).
- Next, place the product inside a new square root symbol.
Following the steps, we multiply 5 and 7, getting 35.
Then we place this product inside a square root, resulting in \(\sqrt{35}.\)
This product of radicals simplifies the expression and shows us the answer.
Other exercises in this chapter
Problem 7
Add or subtract. Simplify by combining like radical terms, if possible. Assume that all variables and radicands represent positive real numbers. $$2 \sqrt{5}+7
View solution Problem 7
Solve. $$\sqrt{5 x+1}=4$$
View solution Problem 8
Add or subtract. Simplify by combining like radical terms, if possible. Assume that all variables and radicands represent positive real numbers. $$4 \sqrt{7}+2
View solution Problem 8
Classify each of the following statements as either true or false. The quotient of two complex numbers is always a complex number.
View solution