Problem 7
Question
More generally, prove that in a lattice \((L, \leq)\) every finite nonempty subset \(S\) has a least upper bound and a greatest lower bound.
Step-by-Step Solution
Verified Answer
To prove that every finite nonempty subset \(S\) in a lattice \((L, \leq)\) has a least upper bound (lub) and greatest lower bound (glb): First, understand what lattices, lub, and glb are. Then, take two arbitrary elements 'a' and 'b' in \(S\), and prove that they have a lub and glb. Next, extend this proof for all elements in the set using mathematical induction. Thus, every finite nonempty subset \(S\) in a lattice \((L, \leq)\) has a lub and a glb.
1Step 1: Understanding Lattices
A lattice \((L, \leq)\) is a partially ordered set (poset) in which any two elements have a greatest lower bound (glb) and least upper bound (lub). The glb is the greatest element that is less than or equal to all elements in the set. The lub is the smallest element that is greater than or equal to all elements in the set.
2Step 2: Proof of Least Upper Bound and Greatest Lower Bound
To prove the existence of lub and glb, a common strategy is to take two arbitrary elements 'a' and 'b' from the set \(S\). Due to the nature of a lattice, these two elements will have a lub and a glb within the set. Prove this by first assuming otherwise, and then showing that this leads to a contradiction, which demonstrates the existence of a lub and glb for 'a' and 'b'.
3Step 3: Extending to all elements in the set
Approach the entire proof using mathematical induction for more than two elements. After proving the base case for two elements, assume that the statement holds for \(n\) elements. Consider adding one more element to the set, and prove that the new set still has a lub and glb, based on the induction hypothesis and the pairwise lub and glb existence already proven in Step 2.
Key Concepts
Partially Ordered SetLeast Upper BoundGreatest Lower BoundMathematical Induction
Partially Ordered Set
A partially ordered set, or simply a poset, is a set equipped with a relation that dictates how elements compare with each other. In a poset, not all elements need to be comparable, which is different from a totally ordered set where every two elements are comparable. The relation, often denoted as \(\leq\), must satisfy three key properties:
- Reflexivity: Every element is comparable to itself, meaning for any element \(a\), \(a \leq a\).
- Antisymmetry: If one element is comparable to another in both directions, they must be equal, i.e., if \(a \leq b\) and \(b \leq a\), then \(a = b\).
- Transitivity: If one element is comparable to a second, which is comparable to a third, the first and third elements are also comparable, i.e., if \(a \leq b\) and \(b \leq c\), then \(a \leq c\).
Least Upper Bound
The least upper bound, sometimes referred to as the supremum, is an important concept in lattice theory. Given a set \(S\), an upper bound is an element that is greater than or equal to every element in \(S\). The least upper bound (lub) is the smallest such element, ensuring that no other upper bound is lesser than it. The significance of the least upper bound lies in its ability to act as a universal constraint within a subset.
- Properties of lub: If \(u\) is a least upper bound of \(S\), then for every element \(s\) in \(S\), \(s \leq u\).
- There is no other element \(u'\) such that \(u' \lt u\) and \(u'\) is an upper bound for \(S\).
Greatest Lower Bound
The greatest lower bound, also known as the infimum, mirrors the least upper bound but works in the reverse ordering direction. For a set \(S\), a lower bound is an element that is less than or equal to every element in the set. The greatest lower bound (glb) is the largest among all lower bounds, which means no other lower bound is greater.
- Properties of glb: If \(v\) is a greatest lower bound of \(S\), then for every element \(s\) in \(S\), \(v \leq s\).
- There is no other element \(v'\) such that \(v \gt v'\) and \(v'\) is a lower bound for \(S\).
Mathematical Induction
Mathematical induction is a powerful proof technique often used to establish the truth of an infinite sequence of statements. It is particularly useful in demonstrating properties of lattices involving any number of elements. The process involves two key steps:
- Base Case: Verify that the statement holds for an initial element, often times the smallest or a straightforward case like two elements in a lattice.
- Inductive Step: Assume the statement is true for a generic case of \(n\) elements. Then demonstrate it also holds for \(n + 1\) elements by introducing another element and leveraging the previous truths.
Other exercises in this chapter
Problem 6
Show that all ultrafilters in a finite Boolean algebra are fixed.
View solution Problem 6
Find the disjunctive normal form of \(f\) and simplify it: $$ f=x^{\prime} y+x^{\prime} y^{\prime} z+x y^{\prime} z^{\prime}+x y^{\prime} z $$
View solution Problem 7
Show that sublattices, homomorphic images, and direct products of distributive lattices are again distributive.
View solution Problem 7
Show that \((\\{1,2,3,6,9,18\\}\), gcd, \(1 \mathrm{~cm}\) ) does not form a Boolean algebra for the set of positive divisors of 18 .
View solution