Problem 7
Question
Let \(G\) be a group, \(H \triangleleft G, \phi \in \operatorname{Aut}(G)\). Show that \(\phi(H) \triangleleft G\).
Step-by-Step Solution
Verified Answer
\(\phi(H) \triangleleft G\) since \(\phi\) is an automorphism and \(H\) is normal in \(G\).
1Step 1: Understand Normal Subgroups
A subgroup \(H\) of a group \(G\) is normal, denoted \(H \triangleleft G\), if for all elements \(g \in G\) and \(h \in H\), the element \(g h g^{-1} \in H\). This property needs to be preserved under the automorphism \(\phi\).
2Step 2: Apply the Automorphism
An automorphism \(\phi\) is a bijective homomorphism from \(G\) to itself. This means \(\phi(gh) = \phi(g)\phi(h)\) and \(\phi(g^{-1}) = \phi(g)^{-1}\) for all \(g, h \in G\). We will use these properties to show that \(\phi(H)\) is normal in \(G\).
3Step 3: Show \(\phi(H)\) is a Subgroup of \(G\)
Since \(\phi\) is an automorphism, it maps \(H\) to another subgroup \(\phi(H)\) of \(G\). As \(H\) is a subgroup, and automorphisms preserve group operations, \(\phi(H)\) retains subgroup properties.
4Step 4: Demonstrate Normality Condition
For \(\phi(H)\) to be normal in \(G\), for any \(g \in G\) and \(h' \in \phi(H)\), we must have \(g h' g^{-1} \in \phi(H)\). Since \(h' = \phi(h)\) for some \(h \in H\), consider \(g \phi(h) g^{-1} = \phi(\phi^{-1}(g) h \phi^{-1}(g)^{-1})\). Since \(H\) is normal in \(G\), \(\phi^{-1}(g) h \phi^{-1}(g)^{-1} \in H\), and thus \(g \phi(h) g^{-1} \in \phi(H)\).
5Step 5: Conclude That \(\phi(H) \triangleleft G\)
Given that \(g h' g^{-1} \in \phi(H)\) for any \(g \in G\) and \(h' \in \phi(H)\), the condition for normality is satisfied. Therefore, we can conclude that \(\phi(H)\) is normal in \(G\), or \(\phi(H) \triangleleft G\).
Key Concepts
Group TheoryAutomorphismSubgroup PropertiesBijective Homomorphism
Group Theory
In mathematics, group theory plays a vital role in understanding the algebraic structures known as groups. A **group** is a set combined with an operation that satisfies certain conditions—closure, associativity, identity, and invertibility. These properties ensure that the operation within the set behaves predictably.
Here's what each property means:
Here's what each property means:
- Closure: If you take any two elements in your set and apply the operation, the result is still within your set.
- Associativity: When you have three elements, the order in which you apply the operation doesn't matter.
- Identity element: There exists an element in the set such that when it's combined with any element, it does not change the result.
- Inverse element: For every element in the set, there exists another element that when combined with the first under the operation results in the identity element.
Automorphism
An automorphism is essentially a transformation of a group that maps the group onto itself, preserving its structure. In other words, it's a map from a group, say, \(G\), back to itself that retains the original group's properties.
There are key characteristics of an automorphism:
There are key characteristics of an automorphism:
- Bijective: An automorphism must be both injective (one-to-one) and surjective (onto), meaning every element in the group is matched with a unique element and vice versa.
- Homomorphism: It respects the group operation, meaning if you take any two elements \(g\) and \(h\) in the group, \(\phi(gh) = \phi(g)\phi(h)\).
Subgroup Properties
A subgroup is a smaller group within a larger group, preserving the group operation and maintaining the same structural integrity. If \(H\) is a subgroup of \(G\), every operation in \(H\) must obey the same rules as those in \(G\).
There are several properties that a subgroup must have:
There are several properties that a subgroup must have:
- It contains the identity element of \(G\).
- It is closed under the group operation.
- Each element must have its inverse also in the subgroup.
Bijective Homomorphism
A bijective homomorphism is a special kind of homomorphism that is both injective and surjective, essentially forming an isomorphism between groups. When we talk about a bijective homomorphism from a group to itself, we're often referring to an automorphism.
Here’s how it breaks down:
Here’s how it breaks down:
- Injective (One-to-One): Every element of the domain is mapped to a distinct element in the codomain.
- Surjective (Onto): Every element in the codomain is mapped by some element of the domain.
- Respect the operation: It ensures that the group structure is retained through \(\phi(gh) = \phi(g)\phi(h)\).
Other exercises in this chapter
Problem 7
Determine whether the indicated subgroup is normal in the indicated group. $$ K=\left\\{\rho_{0},(12)(34),(13)(24),(14)(23)\right\\} \text { in } S_{4} $$
View solution Problem 7
Find the order of the indicated element in the indicated quotient group. $$ 3+\langle 8\rangle \text { in } \mathbb{Z}_{12} /\langle 8\rangle $$
View solution Problem 8
Determine whether the indicated subgroup is normal in the indicated group. $$ \langle(123)\rangle \text { in } S_{4} $$
View solution Problem 8
Find the order of the indicated element in the indicated quotient group. $$ 3+\langle 6\rangle \text { in } \mathbb{Z}_{15} /\langle 6\rangle $$
View solution