Problem 7
Question
Is the relationship between the values in each table a direct variation, an inverse variation, or neither? Write equations to model the direct and inverse variations. $$ \begin{array}{|c|c|c|c|c|}\hline x & {3} & {8} & {10} & {22} \\ \hline y & {15} & {40} & {50} & {110} \\ \hline\end{array} $$
Step-by-Step Solution
Verified Answer
The relationship between values in the given table are neither in direct variation nor inverse variation because the quotient of y/x and the product of x*y is not constant for all pairs. Therefore, no equations can be modelled for direct or inverse variation with this data set.
1Step 1: Test for direct variation
To verify if there is a direct variation, divide each y-value by its corresponding x-value. If the quotient is constant for all pairs, then it is a direct variation. For the given pair (3,15), the quotient is 15/3=5. Apply this calculation to other pairs and see if the quotient is constant.
2Step 2: Test for inverse variation
To determine if it's an inverse variation, multiply each x-value by its corresponding y-value. For inverse variation, the product should be constant. Let's check this for provided pairs, for instance (3,15), the product is 3*15=45. Repeat this calculation for the remaining pairs and see if the product remains constant.
3Step 3: Formulate the equations
After determining whether it is a direct or inverse variation, we must formulate the respective equation. For direct variation, the equation will be in the form \(y=kx\) where k is the constant of variation. If it is an inverse variation, the equation will be in the form \(xy=k\) where k is the constant of variation.
Key Concepts
Direct VariationConstant of VariationEquationsMathematical Modeling
Direct Variation
Direct variation occurs when two variables are related in such a way that when one variable increases, the other also increases proportionally. This relationship can be expressed as \( y = kx \), where \( y \) and \( x \) are the variables and \( k \) is the constant of variation. In simple terms, the value of \( y \) changes directly as you change \( x \) and by the factor of \( k \).
To determine if you're working with direct variation, divide each \( y \)-value by its corresponding \( x \)-value. If the result is constant across all pairs, you have a direct variation.
For example, suppose we have the pairs (3,15), (8,40), (10,50), and (22,110). Calculating \( 15/3 = 5 \), \( 40/8 = 5 \), \( 50/10 = 5 \), and \( 110/22 = 5 \) shows a consistent result, confirming direct variation with \( k = 5 \).
To determine if you're working with direct variation, divide each \( y \)-value by its corresponding \( x \)-value. If the result is constant across all pairs, you have a direct variation.
For example, suppose we have the pairs (3,15), (8,40), (10,50), and (22,110). Calculating \( 15/3 = 5 \), \( 40/8 = 5 \), \( 50/10 = 5 \), and \( 110/22 = 5 \) shows a consistent result, confirming direct variation with \( k = 5 \).
Constant of Variation
The constant of variation is a crucial part of understanding both direct and inverse variations. It's the factor that relates two variables in either type of variation relationship. For direct variation, as explained earlier, \( k \) is the consistent ratio of \( y \) divided by \( x \). This remains unchanged as the variables change, demonstrating their proportional relationship.
In inverse variation, however, \( k \) represents the product of \( x \) and \( y \). Instead of a constant ratio, it is a constant product. The equation is expressed as \( xy = k \), indicating that as one variable increases, the other must decrease proportionally to keep \( k \) constant.
In inverse variation, however, \( k \) represents the product of \( x \) and \( y \). Instead of a constant ratio, it is a constant product. The equation is expressed as \( xy = k \), indicating that as one variable increases, the other must decrease proportionally to keep \( k \) constant.
- Direct variation: \( k = \frac{y}{x} \)
- Inverse variation: \( k = xy \)
Equations
Equations are the mathematical sentences that express relationships between variables. In the context of variations, equations help describe how two variables are related.
For **direct variation**, the equation \( y = kx \) is used. It signifies that \( y \) changes at a constant rate of \( k \) every time \( x \) changes. This equation is linear and often appears graphically as a straight line passing through the origin.
For **inverse variation**, the equation \( xy = k \) is utilized. Instead of a linear graph, you'll observe a hyperbola, as one variable diminishes while the other grows so that their product remains the same.
Both types of equations are essential tools in mathematical modeling, providing a precise way to represent variable relationships.
For **direct variation**, the equation \( y = kx \) is used. It signifies that \( y \) changes at a constant rate of \( k \) every time \( x \) changes. This equation is linear and often appears graphically as a straight line passing through the origin.
For **inverse variation**, the equation \( xy = k \) is utilized. Instead of a linear graph, you'll observe a hyperbola, as one variable diminishes while the other grows so that their product remains the same.
Both types of equations are essential tools in mathematical modeling, providing a precise way to represent variable relationships.
Mathematical Modeling
Mathematical modeling is the process of creating a mathematical representation of a real-world situation. This process is critical in understanding and predicting behaviors using mathematics. Variations, both direct and inverse, are fundamental concepts that help in simplifying complex relationships into understandable equations.
By converting a set of data or observations into mathematical models like \( y = kx \) or \( xy = k \), we can explore and predict outcomes effectively. These models allow us to analyze patterns, make forecasts, and understand systems more deeply.
Modeling is a bridge between theoretical math and practical applications. Whether exploring economic trends or physical phenomena, mathematical models are invaluable tools for problem-solving and innovation.
By converting a set of data or observations into mathematical models like \( y = kx \) or \( xy = k \), we can explore and predict outcomes effectively. These models allow us to analyze patterns, make forecasts, and understand systems more deeply.
Modeling is a bridge between theoretical math and practical applications. Whether exploring economic trends or physical phenomena, mathematical models are invaluable tools for problem-solving and innovation.
Other exercises in this chapter
Problem 7
Find the least common multiple of each pair of polynomials. \(12 x^{2}-6 x-126\) and \(18 x-63\)
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Draw a graph of each function. Describe properties of the graph. \(y=\frac{-5}{x}\)
View solution Problem 8
\(\boldsymbol{Q}\) and \(\boldsymbol{R}\) are independent events. Find \(\boldsymbol{P}(\boldsymbol{Q} \text { and } \boldsymbol{R})\) $$ P(Q)=\frac{1}{3}, P(R)
View solution Problem 8
Solve each equation. Check each solution. $$ \frac{10}{6 x+7}=\frac{6}{2 x+9} $$
View solution