Problem 7
Question
In Problems \(1-8\), find the equation of the tangent plane to the given surface at the indicated point. $$ z=2 e^{3 y} \cos 2 x ;(\pi / 3,0,-1) $$
Step-by-Step Solution
Verified Answer
The equation of the tangent plane is \( z = 2\sqrt{3}x - 3y - \frac{2\sqrt{3}\pi}{3} - 1 \).
1Step 1: Identify the Given Surface and Point
The given surface is described by the equation \( z = 2 e^{3y} \cos 2x \). We need to find the equation of the tangent plane at the point \( (x_0, y_0, z_0) = (\pi/3, 0, -1) \).
2Step 2: Find the Partial Derivatives
To find the equation of the tangent plane, we first need the partial derivatives of the function with respect to both \( x \) and \( y \).\[ \frac{\partial z}{\partial x} = -4 e^{3y} \sin 2x \] and \[ \frac{\partial z}{\partial y} = 6 e^{3y} \cos 2x \].
3Step 3: Evaluate Partial Derivatives at the Point
Substitute the point \( (x_0, y_0) = (\pi/3, 0) \) into the partial derivatives calculated in Step 2.\[ \frac{\partial z}{\partial x} \bigg|_{(x_0, y_0)} = -4 e^{0} \sin\left(2\cdot\frac{\pi}{3}\right) = -4 (-\frac{\sqrt{3}}{2}) = 2\sqrt{3} \] and \[ \frac{\partial z}{\partial y} \bigg|_{(x_0, y_0)} = 6 e^{0} \cos\left(2\cdot\frac{\pi}{3}\right) = 6 (-\frac{1}{2}) = -3. \]
4Step 4: Write the Equation of the Tangent Plane
The general formula for the equation of the tangent plane to a surface \( z = f(x, y) \) at the point \((x_0, y_0, z_0)\) is given by: \[ z - z_0 = \frac{\partial z}{\partial x}(x - x_0) + \frac{\partial z}{\partial y}(y - y_0) \].Substitute \( x_0 = \pi/3 \), \( y_0 = 0 \), \( z_0 = -1 \), \( \frac{\partial z}{\partial x} \bigg|_{(x_0, y_0)} = 2\sqrt{3} \), and \( \frac{\partial z}{\partial y} \bigg|_{(x_0, y_0)} = -3 \).\[ z + 1 = 2\sqrt{3}(x - \frac{\pi}{3}) - 3(y - 0) \].
5Step 5: Simplify the Tangent Plane Equation
Simplify \( z + 1 = 2\sqrt{3}(x - \frac{\pi}{3}) - 3y \) to obtain the final form of the tangent plane equation.\[ z = 2\sqrt{3}x - \frac{2\sqrt{3}\pi}{3} - 3y - 1 \].Thus, the equation of the tangent plane is: \[ z = 2\sqrt{3}x - 3y - \frac{2\sqrt{3}\pi}{3} - 1 \].
Key Concepts
Partial DerivativesSurface EquationTangent Plane EquationCalculus
Partial Derivatives
Partial derivatives are a fundamental concept in calculus, especially when dealing with functions of multiple variables. When you have a function like \( z = f(x, y) \), which depends on two variables \( x \) and \( y \), a partial derivative measures how \( z \) changes as one of these variables changes while the other is kept constant. This helps us understand how the function behaves in different directions.
To find the partial derivative of \( z \) with respect to \( x \), noted as \( \frac{\partial z}{\partial x} \), you treat \( y \) as a constant and differentiate the function with respect to \( x \). Similarly, the partial derivative with respect to \( y \), \( \frac{\partial z}{\partial y} \), is found by treating \( x \) as a constant and differentiating with respect to \( y \).
To find the partial derivative of \( z \) with respect to \( x \), noted as \( \frac{\partial z}{\partial x} \), you treat \( y \) as a constant and differentiate the function with respect to \( x \). Similarly, the partial derivative with respect to \( y \), \( \frac{\partial z}{\partial y} \), is found by treating \( x \) as a constant and differentiating with respect to \( y \).
- The partial derivative with respect to \( x \) gives the slope of the tangent line to the curve showing how \( z \) increases or decreases as \( x \) changes.
- The partial derivative with respect to \( y \) does the same for changes in \( y \).
Surface Equation
A surface equation is a mathematical representation that describes a 3D surface in space. For example, \( z = 2 e^{3y} \cos 2x \) defines a surface where the height \( z \) above each \( (x, y) \) point is calculated using this formula. It combines both exponential and trigonometric functions, depicting a surface that varies in complex ways over different values of \( x \) and \( y \).
Studying such equations helps in understanding the topography of surfaces, i.e., their peaks, valleys, slopes, and other features. Each part of this equation affects the surface's shape:
Studying such equations helps in understanding the topography of surfaces, i.e., their peaks, valleys, slopes, and other features. Each part of this equation affects the surface's shape:
- \( 2 e^{3y} \) suggests a rapid increase in one direction, influenced strongly by \( y \).
- \( \cos 2x \) introduces oscillation in the \( x \) direction, creating waves or peaks and troughs.
Tangent Plane Equation
A tangent plane is like a flat sheet that just touches a surface at a particular point and gives us a way to approximate the surface near that point. Think of it as a snapshot of the surface's slope and tilt in all directions at that single point. The equation for a tangent plane can be derived using partial derivatives, as they give us the rates of change in different directions.
The general formula for a tangent plane to a surface \( z = f(x, y) \) at a point \((x_0, y_0, z_0)\) is:\[ z - z_0 = \frac{\partial z}{\partial x}(x - x_0) + \frac{\partial z}{\partial y}(y - y_0).\]This equation allows us to determine how changes in \( x \) and \( y \) affect \( z \), giving us an approximation of the surface near our point of interest.
The general formula for a tangent plane to a surface \( z = f(x, y) \) at a point \((x_0, y_0, z_0)\) is:\[ z - z_0 = \frac{\partial z}{\partial x}(x - x_0) + \frac{\partial z}{\partial y}(y - y_0).\]This equation allows us to determine how changes in \( x \) and \( y \) affect \( z \), giving us an approximation of the surface near our point of interest.
- \( \frac{\partial z}{\partial x} \) shows the surface's slope along the \( x \) direction.
- \( \frac{\partial z}{\partial y} \) shows the slope along the \( y \) direction.
Calculus
Calculus is a branch of mathematics focused on change. It includes finding how things vary, optimally represented through derivatives and integrals. When dealing with surfaces, calculus allows us to understand how variables interact to shape the surface.
In our scenario, calculus revealed the tangent plane equation which helps approximate a complex surface using straight lines. This simplification is powerful in many real-world applications like physics, engineering, economics, and more.
In our scenario, calculus revealed the tangent plane equation which helps approximate a complex surface using straight lines. This simplification is powerful in many real-world applications like physics, engineering, economics, and more.
- Derivatives help us calculate slopes and curves efficiently.
- Partial derivatives extend this to functions with multiple inputs, critical for understanding surfaces.
Other exercises in this chapter
Problem 6
$$ \text { In Problems 1-10, find the gradient } \nabla f \text {. } $$ $$ f(x, y)=\sin ^{3}\left(x^{2} y\right) $$
View solution Problem 6
Find the minimum of \(f(x, y, z)=4 x-2 y+3 z\) subject to the constraint \(2 x^{2}+y^{2}-3 z=0\).
View solution Problem 7
In Problems 1-8, find the directional derivative of \(f\) at the point \(\mathbf{p}\) in the direction of \(\mathbf{a}\). \(f(x, y, z)=x^{3} y-y^{2} z^{2} ; \ma
View solution Problem 7
In Problems 7-12, find \(\partial w / \partial t\) by using the Chain Rule. Express your final answer in terms of \(s\) and \(t\). $$ w=x^{2} y ; x=s t, y=s-t $
View solution