Problem 7
Question
In \(3-8,\) find the exact solution set of each equation if \(0^{\circ} \leq \theta<360^{\circ} .\) $$ 6 \cos ^{2} \theta+5 \cos \theta-4=0 $$
Step-by-Step Solution
Verified Answer
The exact solution set is \( \theta = 60^\circ, 300^\circ \).
1Step 1: Identify the Quadratic Form
The given equation is \( 6\cos^2 \theta + 5\cos \theta - 4 = 0 \). This equation is quadratic in form with respect to \( \cos \theta \).
2Step 2: Substitute Variable for Simplicity
Let \( x = \cos \theta \). The equation becomes \( 6x^2 + 5x - 4 = 0 \).
3Step 3: Apply the Quadratic Formula
Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) with \( a = 6 \), \( b = 5 \), and \( c = -4 \).
4Step 4: Calculate the Discriminant
Compute the discriminant: \( b^2 - 4ac = 5^2 - 4 \times 6 \times (-4) = 25 + 96 = 121 \).
5Step 5: Solve for \( x
The solutions for \( x \) are given by \( x = \frac{-5 \pm \sqrt{121}}{12} \). Evaluating gives: \( x_1 = \frac{-5 + 11}{12} = \frac{6}{12} = \frac{1}{2} \) and \( x_2 = \frac{-5 - 11}{12} = \frac{-16}{12} = \frac{-4}{3} \).
6Step 6: Verify Solutions Within Domain
Since \( \cos \theta \) must be between -1 and 1, only \( x_1 = \frac{1}{2} \) is valid. \( x_2 = \frac{-4}{3} \) is outside the valid range for \( \cos \theta \).
7Step 7: Find Angles for Valid Solution
For \( \cos \theta = \frac{1}{2} \), the angles are \( \theta = 60^\circ \) and \( \theta = 300^\circ \) (since \( \cos \theta \) is positive in the first and fourth quadrants).
8Step 8: Solution Set
The solution set is \( \theta = 60^\circ, 300^\circ \). These are the values of \( \theta \) within \( 0^\circ \leq \theta < 360^\circ \).
Key Concepts
Cosine FunctionQuadratic FormulaTrigonometric Identities
Cosine Function
The cosine function is one of the fundamental trigonometric functions. It is a function that relates an angle in a right triangle to the ratio of the adjacent side over the hypotenuse. When you see \( \cos \theta \), it refers to the cosine of the angle \( \theta \).
- In unit circle terms, \( \cos \theta \) is the x-coordinate of the point where the terminal side of the angle intersects the unit circle.
- The cosine function is periodic with a period of \( 360^{\circ} \) or \( 2\pi \) radians.
Quadratic Formula
The quadratic formula is an essential tool for solving quadratic equations. A quadratic equation has the form \( ax^2 + bx + c = 0 \).
- The formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) finds the values of \( x \) that make the equation zero.
- The part under the square root, \( b^2 - 4ac \), is called the discriminant and determines the number and type of roots.
Trigonometric Identities
Trigonometric identities are essential tools that help simplify trigonometric expressions and equations. Some of the most commonly used include:
- Basic identities like \( \cos^2\theta + \sin^2\theta = 1 \) can help transform and solve equations.
- They can show relationships between different trigonometric functions, such as \( \tan\theta = \frac{\sin\theta}{\cos\theta} \).
Other exercises in this chapter
Problem 7
In \(3-14,\) find the exact values of \(\theta\) in the interval \(0^{\circ} \leq \theta
View solution Problem 7
In \(3-10,\) find the exact values of \(\theta\) in the interval \(0^{\circ} \leq \theta \leq 360^{\circ}\) that make each equation true. $$ \cos 2 \theta+2 \co
View solution Problem 8
In \(3-14\) , use the quadratic formula to find, to the nearest degree, all values of \(\theta\) in the interval \(0^{\circ} \leq \theta
View solution Problem 8
In \(3-14,\) find the exact values of \(\theta\) in the interval \(0^{\circ} \leq \theta
View solution