Problem 7
Question
In \(3-14\) , use the quadratic formula to find the roots of each equation. Irrational roots should be written in simplest radical form. $$ x^{2}+5 x-2=0 $$
Step-by-Step Solution
Verified Answer
The roots are \(\frac{-5 + \sqrt{33}}{2}\) and \(\frac{-5 - \sqrt{33}}{2}\).
1Step 1: Identify the coefficients
To use the quadratic formula, we need to identify the coefficients of the quadratic equation. From the equation \(x^2 + 5x - 2 = 0\), we have: \(a = 1\), \(b = 5\), and \(c = -2\).
2Step 2: Write down the quadratic formula
The quadratic formula is given by:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]We will use this formula to solve for the roots of the equation.
3Step 3: Calculate the discriminant
The discriminant is \(b^2 - 4ac\). Let's calculate this value using our coefficients:\[ b^2 - 4ac = 5^2 - 4 \times 1 \times (-2) = 25 + 8 = 33 \]Since the discriminant is positive and not a perfect square, we'll have two irrational roots.
4Step 4: Substitute into the quadratic formula
Substitute the values of \(a\), \(b\), and the discriminant into the quadratic formula:\[ x = \frac{-5 \pm \sqrt{33}}{2 \times 1} \]
5Step 5: Simplify the expression
We simplify the expression for the two possible roots:- First root: \[ x = \frac{-5 + \sqrt{33}}{2} \]- Second root: \[ x = \frac{-5 - \sqrt{33}}{2} \]These are the simplest radical form for the irrational roots of the equation.
Key Concepts
Understanding Quadratic EquationsThe Role of the DiscriminantExploring Irrational Roots
Understanding Quadratic Equations
Quadratic equations are a fundamental part of algebra and mathematics in general. A quadratic equation is typically expressed in the form \( ax^2 + bx + c = 0 \), where:
- \( a \), \( b \), and \( c \) are constants
- \( a eq 0 \) (if \( a = 0 \), it becomes a linear equation, not quadratic)
The Role of the Discriminant
The discriminant is a crucial element in understanding the nature of the solutions of quadratic equations. It is derived from the coefficients of the quadratic equation \( ax^2+bx+c=0 \) and is calculated as:\[ b^2 - 4ac \]The value of the discriminant gives us insight into the type of roots the equation will have:
- If the discriminant is positive and a perfect square, the roots are real and rational.
- If the discriminant is positive but not a perfect square, the roots are real and irrational.
- If the discriminant is zero, there is exactly one real rational root (a repeated root).
- If the discriminant is negative, there are two complex conjugate roots.
Exploring Irrational Roots
Irrational roots are types of roots that cannot be expressed as a simple fraction or integer. They often occur under a square root sign due to a discriminant that is positive but not a perfect square. When quadratic equations have irrational roots, they usually involve radicals. For instance, the roots of the equation\( x^2 + 5x - 2 = 0 \)were found using the quadratic formula with a discriminant of 33. The resulting roots are:
- \( \frac{-5 + \sqrt{33}}{2} \)
- \( \frac{-5 - \sqrt{33}}{2} \)
Other exercises in this chapter
Problem 7
In \(3-17,\) find each sum or difference of the complex numbers in \(a+b i\) form. $$ (2-8 i)-(2+8 i) $$
View solution Problem 7
In \(3-18,\) write each number in terms of \(i\) $$ -\sqrt{-121} $$
View solution Problem 7
In \(3-8,\) complete the square of the quadratic expression. $$ 2 x^{2}-4 x $$
View solution Problem 8
In \(3-14,\) use the quadratic formula to find the imaginary roots of each equation. $$ x^{2}+8 x+17=0 $$
View solution