Problem 7
Question
If \(B=120^{\circ}, C=20^{\circ}\), and \(c=28\) inches, find \(b\).
Step-by-Step Solution
Verified Answer
The length of side \( b \) is approximately 70.53 inches.
1Step 1: Understanding Given Values
We are given two angles of a triangle, namely \( B = 120^{\circ} \) and \( C = 20^{\circ} \), and one side \( c = 28 \) inches, opposite to angle \( C \). We need to find the length of side \( b \), which is opposite to angle \( B \).
2Step 2: Calculate the Third Angle
Use the sum of angles in a triangle to find the third angle \( A \). The sum of angles in a triangle is \( 180^{\circ} \). Hence,\( A = 180^{\circ} - B - C \). Substitute the known values: \( A = 180^{\circ} - 120^{\circ} - 20^{\circ} = 40^{\circ} \).
3Step 3: Apply the Law of Sines
The Law of Sines states \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \). We only need to use parts of this formula involving \( b \) and \( c \): \( \frac{b}{\sin B} = \frac{c}{\sin C} \).
4Step 4: Solve for \( b \)
Rearrange the equation to solve for \( b \): \( b = \frac{c \cdot \sin B}{\sin C} \). Substitute the known values: \( b = \frac{28 \cdot \sin(120^{\circ})}{\sin(20^{\circ})} \).
5Step 5: Calculate Sine Values
Compute \( \sin(120^{\circ}) \) and \( \sin(20^{\circ}) \). \( \sin(120^{\circ}) = \sin(180^{\circ} - 60^{\circ}) = \sin(60^{\circ}) = \frac{\sqrt{3}}{2} \). Use a calculator for \( \sin(20^{\circ}) \): it is approximately \( 0.342 \).
6Step 6: Final Calculation
Substitute the sine values into the equation for \( b \): \( b = \frac{28 \cdot \frac{\sqrt{3}}{2}}{0.342} \). Simplify the expression by calculating the numerical approximation to find \( b \) approximately equals \( 70.53 \) inches.
Key Concepts
Understanding Triangle AnglesSolving Triangles Using the Law of SinesDeep Dive into the Sine Function
Understanding Triangle Angles
In a triangle, the angles have a special relationship, which is essential for solving numerous geometry problems. The sum of the interior angles of any triangle is always 180 degrees. This fact is crucial when we need to determine a missing angle if two angles are known.
- For the given problem, angles B and C are 120° and 20° respectively.
- To find the missing angle A, you subtract the sum of the known angles from 180°: \[ A = 180^{\circ} - B - C = 180^{\circ} - 120^{\circ} - 20^{\circ} = 40^{\circ} \]
Solving Triangles Using the Law of Sines
Solving triangles often entails finding the unknown angles or sides using known dimensions. One effective method for solving oblique triangles, which are non-right triangles, is the Law of Sines. This law is expressed as:\[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\]In our scenario, the focus is on finding side \( b \), with angle \( B \) already known. We can set up the equation:
- \( \frac{b}{\sin B} = \frac{c}{\sin C} \)
- Substitute the known values and rearrange to solve for \( b \):\[ b = \frac{c \cdot \sin B}{\sin C} \]
Deep Dive into the Sine Function
The sine function is part of trigonometry and plays a pivotal role in solving various geometric problems, including those involving triangles. It represents the ratio of the opposite side to the hypotenuse in a right triangle. However, it is also applicable to non-right triangles via the Law of Sines.
- The sine function helps us link angles and sides effectively, thus calculating unknown elements of a triangle.
- For instance, calculate the sine values for given angles, like in our problem:
- \( \sin(120^{\circ}) = \sin(180^{\circ} - 60^{\circ}) = \sin(60^{\circ}) = \frac{\sqrt{3}}{2} \)
- Approximating \( \sin(20^{\circ}) \) with a calculator gives about 0.342.
Other exercises in this chapter
Problem 6
The opposite of a vector is a vector with the ______ magnitude and __________ direction. To obtain the opposite of a vector, multiply the vector by ____.
View solution Problem 6
For each of the following triangles, solve for \(B\) and use the results to explain why the triangle has the given number of solutions. \(A=30^{\circ}, b=40 \ma
View solution Problem 7
For Questions 1 through 8, fill in the blank with an appropriate word. The component of a force F that is oriented in the same direction as another vector d is
View solution Problem 7
Find the semi perimeter of triangle \(A B C\). \(a=3 \mathrm{ft}, b=4 \mathrm{ft}, c=5 \mathrm{ft}\)
View solution