Problem 7
Question
For the functions \(f\) and \(g\), find a. \((f+g)(x)\), b. \((f-g)(x), c .(f \cdot g)(x)\), and d. \(\left(\frac{f}{g}\right)(x)\). $$ f(x)=-3 x ; g(x)=5 x^{2} $$
Step-by-Step Solution
Verified Answer
a. \((f+g)(x) = 5x^2 - 3x\); b. \((f-g)(x) = -5x^2 - 3x\); c. \((f \cdot g)(x) = -15x^3\); d. \(\left(\frac{f}{g}\right)(x) = \frac{-3}{5x}\).
1Step 1: Find \((f+g)(x)\)
To find \((f+g)(x)\), add the expressions for \(f(x)\) and \(g(x)\). Here, \(f(x) = -3x\) and \(g(x) = 5x^2\). So, \((f+g)(x) = f(x) + g(x) = -3x + 5x^2\). Write this in a standard polynomial form: \((f+g)(x) = 5x^2 - 3x\).
2Step 2: Find \((f-g)(x)\)
To find \((f-g)(x)\), subtract \(g(x)\) from \(f(x)\). So, \((f-g)(x) = f(x) - g(x) = -3x - 5x^2\). Rearranging, we have \((f-g)(x) = -5x^2 - 3x\).
3Step 3: Find \((f \cdot g)(x)\)
To find \((f \cdot g)(x)\), multiply \(f(x)\) by \(g(x)\). So, \((f \cdot g)(x) = (-3x)(5x^2) = -15x^3\).
4Step 4: Find \(\left(\frac{f}{g}\right)(x)\)
To find \(\left(\frac{f}{g}\right)(x)\), divide \(f(x)\) by \(g(x)\). So, \(\left(\frac{f}{g}\right)(x) = \frac{-3x}{5x^2}\). Simplifying, divide the numerator and the denominator by \(x\), which gives \(\left(\frac{f}{g}\right)(x) = \frac{-3}{5x}\).
Key Concepts
Function AdditionFunction SubtractionFunction MultiplicationFunction Division
Function Addition
Function addition is simply the process of combining two functions by adding their respective outputs. In our exercise, we have the functions:
It's important to write the resulting function in standard polynomial form, which prioritizes descending powers of \(x\). So, \((f+g)(x) = 5x^2 - 3x\).
This combination reveals a new polynomial function showcasing the traits of both \(f\) and \(g\). Function addition helps understand how individual functions contribute to a resultant function.
- \( f(x) = -3x \)
- \( g(x) = 5x^2 \)
It's important to write the resulting function in standard polynomial form, which prioritizes descending powers of \(x\). So, \((f+g)(x) = 5x^2 - 3x\).
This combination reveals a new polynomial function showcasing the traits of both \(f\) and \(g\). Function addition helps understand how individual functions contribute to a resultant function.
Function Subtraction
Function subtraction involves subtracting one function's output from another function's output. In this exercise, we subtract the function \(g(x)\) from \(f(x)\):
Function subtraction can expose differences between two functions and how one function might offset or enhance certain values of the other.
- \( (f-g)(x) = f(x) - g(x) = -3x - 5x^2 \)
Function subtraction can expose differences between two functions and how one function might offset or enhance certain values of the other.
Function Multiplication
To understand function multiplication, it's key to realize that multiplying two functions' formulas combines their effects multiplicatively. Here, we multiply \(f(x)\) and \(g(x)\):
This further answers how the rate of change of one function affects the other, producing a more complex result. Function multiplication yields insight into how multiplicative interactions between functions transform their outputs.
- \( (f \cdot g)(x) = (-3x)(5x^2) = -15x^3 \)
This further answers how the rate of change of one function affects the other, producing a more complex result. Function multiplication yields insight into how multiplicative interactions between functions transform their outputs.
Function Division
Function division involves dividing the output of one function by another. For the functions given, we need to divide \(f(x)\) by \(g(x)\):
Function division is beneficial in understanding the relative behaviors of two functions, especially revealing the scaling and inversely proportional aspects influenced by division.
Considerations include ensuring \(g(x)\) doesn't equal zero, as this would make the division undefined.
- \( \left(\frac{f}{g}\right)(x) = \frac{-3x}{5x^2} \)
Function division is beneficial in understanding the relative behaviors of two functions, especially revealing the scaling and inversely proportional aspects influenced by division.
Considerations include ensuring \(g(x)\) doesn't equal zero, as this would make the division undefined.
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