Problem 7
Question
For the following exercises, write an equation describing the relationship of the given variables. \(y\) varies directly as the cube of \(x\) and when \(x=36, \quad y=24\).
Step-by-Step Solution
Verified Answer
The equation is \(y = \frac{1}{1944}x^3\).
1Step 1: Understanding Direct Variation
The statement "\(y\) varies directly as the cube of \(x\)" means that \(y\) is proportional to \(x^3\). The mathematical expression for this direct variation is: \( y = kx^3 \), where \(k\) is the constant of proportionality.
2Step 2: Substitute Known Values
We are given that when \(x = 36, y = 24\). To find \(k\), substitute \(x = 36\) and \(y = 24\) into the equation. This gives us: \(24 = k(36^3)\).
3Step 3: Calculate \(36^3\)
Calculate the cube of 36: \(36^3 = 36 \times 36 \times 36 = 46656\).
4Step 4: Solve for the Constant \(k\)
Substitute \(36^3 = 46656\) back into the equation: \(24 = k \cdot 46656\). Simplify to solve for \(k\): \(k = \frac{24}{46656}\).
5Step 5: Simplify the Constant \(k\)
Simplify the fraction: \( \frac{24}{46656} = \frac{1}{1944} \). Thus, \(k = \frac{1}{1944}\).
6Step 6: Write the Final Equation
Now we have the constant \(k\), substitute \(k\) back into the original equation: \(y = \frac{1}{1944}x^3\). This is the equation describing the relationship between \(y\) and \(x\).
Key Concepts
Constant of ProportionalityCube FunctionProportional Relationships
Constant of Proportionality
The constant of proportionality, often represented by \( k \), is a fundamental concept in understanding proportional relationships in mathematics. It represents the factor by which one variable changes in relation to another.
In the context of direct variation, if \( y \) varies directly with the cube of \( x \), the relationship can be expressed as \( y = kx^3 \). Here, \( k \) determines the rate at which \( y \) changes as \( x \) changes.
In the context of direct variation, if \( y \) varies directly with the cube of \( x \), the relationship can be expressed as \( y = kx^3 \). Here, \( k \) determines the rate at which \( y \) changes as \( x \) changes.
- The equation \( y = kx^3 \) tells us that for every increase or decrease in \( x \), \( y \) changes proportionally based on the cube of \( x \) multiplied by \( k \).
- Without the constant, a simple, scalar relationship wouldn't exist between the variables.
Cube Function
A cube function is a polynomial of the form \( x^3 \). It's important in mathematics because it naturally extends linear relationships to three dimensions.
In the context of direct variation, cubing introduces a non-linear relationship between variables. For example, if \( y \) depends directly on \( x^3 \), it means any change in \( x \) has an exponentially greater effect on \( y \) due to the cubic form.
In the context of direct variation, cubing introduces a non-linear relationship between variables. For example, if \( y \) depends directly on \( x^3 \), it means any change in \( x \) has an exponentially greater effect on \( y \) due to the cubic form.
- When you cube a number \( x \), you are multiplying \( x \) by itself three times: \( x \times x \times x \).
- This operation significantly increases the result, which highlights why the cube function causes \( y \) to grow much faster as \( x \) increases.
Proportional Relationships
Proportional relationships in mathematics explain how two quantities change in relation to each other. When two quantities are in a direct relationship, one is a constant multiple of the other.
Key characteristics of proportional relationships include:
Key characteristics of proportional relationships include:
- A constant ratio, or constant of proportionality, exists between the two variables.
- Their graph is a straight line that passes through the origin when dealing with linear forms.
- In direct variation, as one quantity increases, the other increases at a constant rate defined by the constant \( k \).
Other exercises in this chapter
Problem 6
For the following exercises, identify the function as a power function, a polynomial function, or neither. $$ f(x)=x^{5} $$
View solution Problem 6
For the following exercises, rewrite the quadratic functions in standard form and give the vertex. $$ f(x)=x^{2}-12 x+32 $$
View solution Problem 7
For the following exercises, find the inverse of the function on the given domain. $$ f(x)=(x+1)^{2}-3,[-1, \infty) $$
View solution Problem 7
For the following exercises, find the domain of the rational functions. $$ f(x)=\frac{x+1}{x^{2}-1} $$
View solution