Problem 7
Question
For the following exercises, find the \(x\) - or t-intercepts of the polynomial functions. $$ C(t)=3(t+2)(t-3)(t+5) $$
Step-by-Step Solution
Verified Answer
The \( t \)-intercepts are \( -2, 3, \) and \( -5 \).
1Step 1: Identify the Equation
We start with the polynomial function given by \( C(t) = 3(t+2)(t-3)(t+5) \). Here, \( t \) represents the variable, similar to \( x \) in other contexts.
2Step 2: Understanding Intercepts
The \( t \)-intercepts occur where the polynomial is equal to zero, \( C(t) = 0 \). This means finding values of \( t \) that make the equation \( C(t) = 3(t+2)(t-3)(t+5) \) equal to zero.
3Step 3: Set the Equation to Zero
To find the intercepts, we set the polynomial equal to zero: \[ 3(t+2)(t-3)(t+5) = 0 \] Since 3 is a nonzero constant, we can ignore it to focus on the factors involving \( t \).
4Step 4: Solve for Each Factor
Set each factor equal to zero and solve for \( t \): 1. \( t+2=0 \) leads to \( t=-2 \)2. \( t-3=0 \) leads to \( t=3 \)3. \( t+5=0 \) leads to \( t=-5 \)
5Step 5: List the Intercepts
The \( t \)-intercepts of the polynomial are the values of \( t \) calculated in the previous step: \( -2, 3, \) and \( -5 \). These are the points where the function crosses the \( t \)-axis.
Key Concepts
X-InterceptsT-InterceptsFactoring Polynomials
X-Intercepts
Understanding x-intercepts is key to analyzing polynomial functions. In simple terms, x-intercepts are the points where the graph of a polynomial crosses the x-axis. Since the y-coordinate at any x-intercept is zero, the x-intercepts are the roots of the equation when the polynomial is set to zero.
To find x-intercepts, follow these steps:
To find x-intercepts, follow these steps:
- Set the polynomial equation equal to zero.
- Solve for the variable, typically x. This involves finding the values of x that satisfy the equation.
T-Intercepts
The concept of t-intercepts is closely related to x-intercepts, but applies when the variable in the polynomial is t instead of x. The t-intercepts occur where the graph of the polynomial crosses the t-axis, meaning the value of the function is zero at these points.
For the function provided, the intercepts can be found by examining where the polynomial equals zero: \( C(t) = 3(t+2)(t-3)(t+5) = 0 \). When this is set to zero, each factor of the polynomial must be zero individually.
For the function provided, the intercepts can be found by examining where the polynomial equals zero: \( C(t) = 3(t+2)(t-3)(t+5) = 0 \). When this is set to zero, each factor of the polynomial must be zero individually.
- Solving \( t+2=0 \) gives \( t=-2 \)
- Solving \( t-3=0 \) gives \( t=3 \)
- Solving \( t+5=0 \) gives \( t=-5 \)
Factoring Polynomials
Factoring polynomials is a fundamental skill in finding intercepts and simplifying complex equations. It involves breaking down a polynomial into simpler terms (factors), which, when multiplied together, give the original polynomial.
The provided function \( C(t) = 3(t+2)(t-3)(t+5) \) is a perfect illustration of factoring. Here is how factoring helps:
The provided function \( C(t) = 3(t+2)(t-3)(t+5) \) is a perfect illustration of factoring. Here is how factoring helps:
- When the polynomial is completely factored, as in \( 3(t+2)(t-3)(t+5) \), each binomial factor like \( (t+2) \), \( (t-3) \), and \( (t+5) \) represents potential solutions or zeros.
- If each factor is set to zero, solving these simpler equations quickly yields the roots or intercepts of the polynomial.
Other exercises in this chapter
Problem 7
For the following exercises, use the Remainder Theorem to find the remainder. $$ \left(3 x^{3}-2 x^{2}+x-4\right) \div(x+3) $$
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For the following exercises, use long division to divide. Specify the quotient and the remainder. $$ \left(6 x^{2}-25 x-25\right) \div(6 x+5) $$
View solution Problem 7
For the following exercises, identify the function as a power function, a polynomial function, or neither. $$ f(x)=\left(x^{2}\right)^{3} $$
View solution Problem 7
For the following exercises, rewrite the quadratic functions in standard form and give the vertex. $$ g(x)=x^{2}+2 x-3 $$
View solution