Problem 7
Question
For the following exercises, find the determinant. \(\left|\begin{array}{rr}2 & -5 \\ -1 & 6\end{array}\right|\)
Step-by-Step Solution
Verified Answer
The determinant of the matrix is 7.
1Step 1: Identify the matrix
The given matrix is a 2x2 matrix: \[ A = \begin{pmatrix} 2 & -5 \ -1 & 6 \end{pmatrix} \]. A 2x2 matrix has the form \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \) where \( a=2 \), \( b=-5 \), \( c=-1 \), and \( d=6 \).
2Step 2: Apply the determinant formula for a 2x2 matrix
The formula to find the determinant of a 2x2 matrix \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \) is \( ad - bc \). For matrix \( A \), substitute the values: \( a=2 \), \( b=-5 \), \( c=-1 \), and \( d=6 \).
3Step 3: Calculate the products
Calculate the product \( ad \), which is \( 2 \times 6 = 12 \), and the product \( bc \), which is \( -5 \times -1 = 5 \).
4Step 4: Compute the determinant
Subtract the second product from the first: \( 12 - 5 = 7 \). Thus, the determinant of the matrix is 7.
Key Concepts
2x2 MatrixMatrix OperationsLinear Algebra
2x2 Matrix
A 2x2 matrix is one of the simplest forms of matrices, having only two rows and two columns. This makes it a square matrix that is relatively easy to work with. Each entry in this type of matrix can be identified with a specific position. In general, a 2x2 matrix looks like this: \[\begin{pmatrix} a & b \ c & d \end{pmatrix} \]where:
- \(a\) is the element in the first row, first column
- \(b\) is the element in the first row, second column
- \(c\) is the element in the second row, first column
- \(d\) is the element in the second row, second column
Matrix Operations
Matrix operations involve various calculations and transformations that can be applied to matrices, such as addition, subtraction, multiplication, and finding determinants. In this context, we are focusing on the operation of finding the determinant of a 2x2 matrix. For a 2x2 matrix \(\begin{pmatrix} a & b \ c & d \end{pmatrix}\), the determinant is calculated using the formula \( ad - bc \). This is a straightforward operation where you:
- Multiply the elements on the main diagonal, \(a\) and \(d\), which is the product \(ad\).
- Multiply the elements on the counter-diagonal, \(b\) and \(c\), which gives \(bc\).
- Subtract the counter-diagonal product from the main diagonal product, yielding \(ad - bc\).
Linear Algebra
Linear algebra is a branch of mathematics focused on vectors, vector spaces, and linear transformations. It plays a critical role in fields such as engineering, physics, computer science, and economics. Central to linear algebra is the concept of matrices and determinants.
Determinants in particular are crucial because they help us assess matrix properties, like invertibility. Specifically, a square matrix (including 2x2 matrices) is invertible if its determinant is not zero. Here's why it matters:
- An invertible matrix corresponds to a linear transformation that is bijective, meaning it has a unique inverse operation.
- In systems of linear equations, determinants help determine whether a unique solution exists.
Other exercises in this chapter
Problem 6
For the following exercises, solve the system of nonlinear equations using substitution. $$\begin{aligned} x+y &=4 \\ x^{2}+y^{2} &=9 \end{aligned}$$
View solution Problem 6
For the following exercises, determine whether the ordered triple given is the solution to the system of equations. $$ \begin{aligned} 2 x-6 y+6 z &=-12 \\ x+4
View solution Problem 7
Write the augmented matrix for the linear system. \(\begin{aligned} 16 y &=4 \\ 9 x-y &=2 \end{aligned}\)
View solution Problem 7
In the following exercises, show that matrix \(A\) is the inverse of matrix \(B\). $$A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right], B=\left[\begin{a
View solution