Problem 7
Question
For all \(z=x+\mathrm{i} y \in \mathbb{C}\) one has: (a) $$ \overline{\exp (z)}=\exp (\bar{z}), \quad \overline{\sin (z)}=\sin (\bar{z}), \quad \overline{\cos (z)}=\cos (\bar{z}) $$ (b) $$ \begin{aligned} &\cos z=\cos (x+\mathrm{i} y)=\cos x \cosh y-\mathrm{i} \sin x \sinh y \\ &\sin z=\sin (x+\mathrm{i} y)=\sin x \cosh y+\mathrm{i} \cos x \sinh y \end{aligned} $$ In the special case \(x=0, y \in \mathbb{R}\) we have $$ \cos (\mathrm{i} y)=\frac{1}{2}\left(e^{y}+e^{-y}\right)=\cosh y \quad \text { and } \quad \sin (\mathrm{i} y)=\frac{\mathrm{i}}{2}\left(e^{y}-e^{-y}\right)=\mathrm{i} \sinh y $$ Determine all the \(z \in \mathbb{C}\) with \(|\sin z| \leq 1\), and find an \(n \in \mathbb{N}\) such that $$ |\sin (\mathrm{in})|>10000. $$
Step-by-Step Solution
VerifiedKey Concepts
Complex Numbers
The real part of the complex number \(z\) is \(x\), and the imaginary part is \(y\). One of the fascinating properties of complex numbers is the ability to conjugate them. The conjugate of \(z\) is written as \(\bar{z} = x - \mathrm{i}y\). This operation flips the sign of the imaginary part, and it is handy when dealing with complex exponentials and trigonometric functions since it helps in simplifying the expressions and maintaining the equality, as seen in the exercise formulas for exponential, sine, and cosine functions for complex numbers.
Trigonometric Functions
Similarly, the cosine function takes the form \(\cos(x + \mathrm{i}y) = \cos x \cosh y - \mathrm{i} \sin x \sinh y\).
These expressions highlight the mix of real trigonometric functions with hyperbolic ones, extending their use far beyond triangles and circles.
This mixing leads to practical applications in wave equations and signal processing, illustrating how complex trigonometric functions are vastly more general than their real counterparts.
Hyperbolic Functions
For complex numbers, these functions can be described using exponentials:\(\cosh y = \frac{e^y + e^{-y}}{2}\) and \(\sinh y = \frac{e^y - e^{-y}}{2}\).
These definitions reveal how hyperbolic functions arise naturally when dealing with complex exponential functions, providing seamless interpretations even into higher dimensions.
This is particularly useful as seen in the calculations for complex numbers with the imaginary unit, where hyperbolic functions intertwine with trigonometric functions, showing their complementary nature.
Inequalities
In the given exercise, the inequality \(|\sin z| \leq 1\) poses an interesting challenge that involves understanding the boundaries within which complex numbers must lie for the condition to hold. By analyzing the trigonometric expressions of complex sine:\(\sin(x + \mathrm{i}y) = \sin x \cosh y + \mathrm{i} \cos x \sinh y\),we conclude that \(\sin^2 x + \sinh^2 y \leq 1\).This ensures the modulus, a measure similar to distance, remains within predefined limits, helping identify valid complex numbers.
Modulus of Complex Numbers
For problems involving complex functions, like sine, the modulus gives a way to understand its magnitude or absolute value. For the function \(\sin z\), since \(|\sin z| = \sqrt{(\sin x \cosh y)^2 + (\cos x \sinh y)^2}\),we notice how both trigonometric and hyperbolic functions merge.
This concept is crucial as it enables us to tackle inequalities, such as ensuring that this modulus stays within certain bounds, making it possible to determine plausible solutions to complex equations.