Problem 7
Question
Find the value of each expression. $$ y^{2}+9 y+1, \text { if } y=0. $$
Step-by-Step Solution
Verified Answer
The value of the expression is 1 when \( y = 0 \).
1Step 1: Substitute the Given Value
Since we need to evaluate the expression \( y^2 + 9y + 1 \) for \( y = 0 \), we start by substituting \( 0 \) in place of \( y \). We now have: \( 0^2 + 9(0) + 1 \).
2Step 2: Simplify Each Term
Next, simplify the expression term by term. For \( 0^2 \) we have 0, and for \( 9(0) \) we also have 0. Thus, the expression simplifies to \( 0 + 0 + 1 \).
3Step 3: Calculate the Result
Add up the simplified terms to get the result. Since both the \( y^2 \) term and the \( 9y \) term simplify to 0, we are left with \( 1 \). Therefore, the expression evaluates to 1.
Key Concepts
Substitution MethodSimplifying ExpressionsQuadratic Expressions
Substitution Method
The substitution method in algebra involves replacing variables with their given numerical values in an expression. This method is very helpful when you need to calculate the specific value of an algebraic expression, like in our example where we have the expression \(y^2 + 9y + 1\) and need to find its value when \(y = 0\).
Here's how the substitution method works:
Here's how the substitution method works:
- Identify the variable you need to replace and the value it is to be substituted with.
- Replace every instance of the variable in the expression with the given number.
Simplifying Expressions
Simplifying an expression involves performing all possible arithmetic operations to bring it to its simplest form. Once you have substituted your values in the expression, the next step is to simplify it.
Let's break down the simplification process for the expression \(0^2 + 9(0) + 1\):
Let's break down the simplification process for the expression \(0^2 + 9(0) + 1\):
- First, calculate \(0^2\), which equals 0.
- Next, multiply \(9\) by \(0\) to get 0.
- Lastly, add the remaining numbers: \(0 + 0 + 1\).
Quadratic Expressions
Quadratic expressions are a type of polynomial where the highest exponent of the variable is 2. The general form of a quadratic expression is \(ax^2 + bx + c\), where "\(a\)", "\(b\)", and "\(c\)" are constants.
In our case, the expression \(y^2 + 9y + 1\) is a quadratic expression featuring the squared term \(y^2\), the linear term \(9y\), and the constant term \(1\).
In our case, the expression \(y^2 + 9y + 1\) is a quadratic expression featuring the squared term \(y^2\), the linear term \(9y\), and the constant term \(1\).
- The term \(y^2\) indicates the quadratic nature because it involves the variable "y" raised to the power of two.
- The term \(9y\) is linear because it involves "y" raised to the first power.
- The term \(1\) is a constant as it doesn’t include "y".