Problem 7
Question
Find the periodic payment \(R\) required to amortize a loan of \(P\) dollars over \(t\) yr with interest charged at the rate of \(r \% /\) year compounded \(m\) times a year. $$ P=80,000, r=10.5, t=30, m=12 $$
Step-by-Step Solution
Verified Answer
The periodic payment (R) required to amortize the $80,000 loan over 30 years with an interest rate of 10.5% compounded 12 times a year is approximately $733.76 per month.
1Step 1: Calculate Monthly Interest Rate
We must first convert the annual interest rate (r) to a monthly interest rate (i). To do this, we will divide r by the number of times the interest is compounded in a year (m).
\(i = \frac{r}{m}\)
Now, we can plug in the given values of r and m.
\(i =\frac{10.5}{12}\)
Calculate the value of i:
\(i ≈ 0.875\% \)
2Step 2: Convert Interest Rate to Decimal Form
To make calculations easier, we will convert the monthly interest rate (i) from percentage to decimal form by dividing by 100.
\(i_{decimal} = \frac{i}{100}\)
Now, plug in the value of i.
\(i_{decimal} ≈ \frac{0.875}{100}\)
Calculate the value of \(i_{decimal}\).
\(i_{decimal} ≈ 0.00875\)
3Step 3: Calculate Total Number of Payments
Next, we need to find the total number of periodic payments required for the entire loan term. Multiply the term (t) in years by the number of payments made each year (m).
\(n = t × m\)
Now, plug in the given values of t and m.
\(n = 30 × 12\)
Calculate the value of n.
\(n = 360\)
The total number of payments is 360.
4Step 4: Calculate Periodic Payment (R)
Using the annuity formula, we can now find the periodic payment (R) required to amortize the loan.
\(R = P × \frac{i_{decimal}(1 +{i_{decimal}})^{n}}{(1 +{i_{decimal}})^{n} - 1}\)
Now, plug in the values of P, \(i_{decimal}\), and n.
\(R = 80,000 × \frac{(0.00875)(1 + 0.00875)^{360}}{(1 + 0.00875)^{360} - 1}\)
Calculate the value of R.
\(R ≈ 733.76\)
The periodic payment (R) required to amortize the loan is approximately $733.76 per month.
Key Concepts
Periodic Payment CalculationInterest Rate ConversionAnnuity Formula
Periodic Payment Calculation
When you take out a loan, you'll typically repay it with regular payments over a certain period. This is called the loan amortization process. The periodic payment is how much you pay in each period, like every month or year, to gradually pay off your loan. To calculate this payment, several factors must be examined, including:
- The loan amount, known as the principal (P). In this example, it's $80,000.
- The interest rate, which affects how much extra you pay for borrowing the money.
- The number of periods (n) over which the loan is paid off, calculated as the number of years times how often payments are made each year.
Interest Rate Conversion
Interest rates are often quoted annually, but loans can require payments at more frequent intervals. To calculate the periodic payment accurately, it's essential to convert the annual interest rate into a rate that's appropriate for the payment intervals, such as monthly.To do this, you'll need to:
- Divide the annual rate by the number of compounding periods per year. For example, if your loan is compounded monthly, you divide by 12. In our exercise, \(i = \frac{10.5}{12} \approx 0.875\%\).
- Convert this rate from a percentage to a decimal by dividing by 100, resulting in the monthly interest rate \(i_{decimal} \approx 0.00875\).
Annuity Formula
The annuity formula is key to finding the periodic payment amount for loans that are amortized over time with equal payments. It helps us to figure out what constant payment will gradually pay down the loan entirely, including both principal and interest, by the end of the loan term.The formula used for calculating this periodic payment \(R\) is: \[R = P \times \frac{i_{decimal}(1 +{i_{decimal}})^{n}}{(1 +{i_{decimal}})^{n} - 1}\]Here's what each symbol represents:
- \(R\) is the periodic payment amount you're calculating.
- \(P\) is the principal, or the initial loan amount.
- \(i_{decimal}\) is the decimal version of the periodic interest rate.
- \(n\) is the total number of payments.
Other exercises in this chapter
Problem 6
Find the amount (future value) of each ordinary annuity. $$ \$ 150 / \text { month for } 15 \text { yr at } 10 \% / \text { year compounded monthly } $$
View solution Problem 6
A bank deposit paying simple interest at the rate of \(5 \% /\) year grew to a sum of $$\$ 3100$$ in 10 mo. Find the principal.
View solution Problem 7
How many days will it take for a sum of $$\$ 1000$$ to earn $$\$ 20$$ interest if it is deposited in a bank paying ordinary simple interest at the rate of \(5 \
View solution Problem 8
How many days will it take for a sum of $$\$ 1500$$ to earn $$\$ 25$$ interest if it is deposited in a bank paying \(5 \% /\) year? (Use a 365-day year.)
View solution