Problem 7
Question
Find the number of bytes that: Contain exactly eight 0's.
Step-by-Step Solution
Verified Answer
There is only \(1\) byte that contains exactly eight 0's, and that is \(00000000\).
1Step 1: Understand Byte and Bit Structure
A byte consists of 8 bits, where each bit can be either 0 or 1. In this case, we are looking for bytes that have exactly eight 0's, which means all the bits in the byte are 0's.
2Step 2: Determine the Possible Byte Values
Since we are looking for bytes containing exactly eight 0's, there is only one possible value for the byte: 00000000. All other bytes will contain at least one 1.
3Step 3: Calculate the Number of Bytes With Eight 0's
As we determined in Step 2, there is only one possible byte value containing exactly eight 0's: 00000000. Therefore, the number of bytes containing exactly eight 0's is 1.
Key Concepts
Byte and Bit StructureCalculating Byte ValuesDiscrete Mathematics Problems
Byte and Bit Structure
In digital computing, the building blocks of data are bits and bytes. A bit is the most basic unit and can have a value of either 0 or 1. Bits are the DNA of digital data, dictating the binary language that computers understand. When we combine eight of these bits, we form what is known as a byte. The structure of a byte is significant because each bit within the byte can vary independently, leading to different possible combinations.
For example, a single byte can be structured as follows:
For example, a single byte can be structured as follows:
- 00000000
- 00000001
- 00000010
- ... all the way up to
- 11111111
Calculating Byte Values
To comprehend how byte values are calculated, one must first understand the binary number system. In binary, each bit position represents a power of 2, with the rightmost position being the zeroth power. Each bit's value is calculated as 2 to the power of its position, multiplied by the bit value (0 or 1).
Let's calculate the value of a byte:
Let's calculate the value of a byte:
- The rightmost bit (least significant bit) has a value of \(2^0 = 1\).
- The next bit to the left has a value of \(2^1 = 2\).
- This continues until the leftmost bit (most significant bit), which has a value of \(2^7 = 128\).
Discrete Mathematics Problems
Discrete mathematics explores topics and problems that involve discrete structures, rather than continuous. This branch of mathematics is particularly relevant to computer science because it deals with distinct values, much like how computers operate with binary digits. When working on discrete mathematics problems, we often use combinatorics, logic, set theory, and graph theory.
In the context of finding the number of bytes containing exactly eight 0's, we're really looking at a combinatorial problem. We have eight positions to fill with zeroes, and we're exploring all possible combinations. Since we're looking for the special case where all bits are 0, it doesn't matter how we arrange them—there is only one way. This simplifies to the problem of counting the number of ways we can arrange eight identical objects (0's), which is, of course, just one way.
In the context of finding the number of bytes containing exactly eight 0's, we're really looking at a combinatorial problem. We have eight positions to fill with zeroes, and we're exploring all possible combinations. Since we're looking for the special case where all bits are 0, it doesn't matter how we arrange them—there is only one way. This simplifies to the problem of counting the number of ways we can arrange eight identical objects (0's), which is, of course, just one way.
Other exercises in this chapter
Problem 7
Find the number of lines that can be drawn using 10 distinct points, no three being collinear.
View solution Problem 7
Find the number of terms in the expansion of each expression. $$(b+c)(d+e+f)(x+y+z)$$
View solution Problem 7
Mark each sentence as true or false, where \(n\) is an arbitrary nonnegative integer and \(0 \leq r \leq n\). $$5 \cdot 4 !=5 !$$
View solution Problem 8
Using the alternate inclusion-exclusion formula, find the number of primes not exceeding: 110
View solution