Problem 7
Question
Find the domain of each rational expression. $$\frac{3 x+7}{(4 x+2)(x-1)}$$
Step-by-Step Solution
Verified Answer
The domain is all real numbers except \\( x = -\frac{1}{2} \\\) and \\( x = 1 \\\).
1Step 1: Identifying Problematic Denominators
Rational expressions are undefined when their denominator is equal to zero. Thus, finding the domain involves identifying values of the variable that cause the denominator to be zero.
2Step 2: Setting Denominator to Zero
To find these values, set the denominator \( (4x + 2)(x - 1) \) equal to zero. This gives us two separate equations: \( 4x + 2 = 0 \) and \( x - 1 = 0 \).
3Step 3: Solving First Equation
Solve \( 4x + 2 = 0 \) for \( x \). Subtract 2 from both sides: \( 4x = -2 \). Then divide by 4: \( x = -\frac{1}{2} \).
4Step 4: Solving Second Equation
Solve \( x - 1 = 0 \) for \( x \). Add 1 to both sides: \( x = 1 \).
5Step 5: Determining the Domain
The domain is all real numbers except for the values that make the denominator zero, which are \( x = -\frac{1}{2} \) and \( x = 1 \). Thus, the domain is \({x \mid x eq -\frac{1}{2}, x eq 1}\).
Key Concepts
Rational ExpressionsUndefined DenominatorSolving Equations
Rational Expressions
Rational expressions are mathematical fractions where both the numerator and the denominator are polynomials. They resemble fractions you might be familiar with, but instead of just numbers, they include variables. For example, in the expression \( \frac{3x+7}{(4x+2)(x-1)} \), \( 3x+7 \) is the numerator, and \( (4x+2)(x-1) \) is the denominator.
Working with rational expressions is similar to dealing with regular fractions:
Working with rational expressions is similar to dealing with regular fractions:
- All the typical fraction rules apply, such as simplifying where possible, multiplying, and adding them.
- Always remember that the denominator should never be zero. This principle is crucial because division by zero is undefined in mathematics.
Undefined Denominator
In mathematics, a fraction becomes undefined when its denominator equals zero. This is because dividing by zero is not permissible. For rational expressions, it's crucial to determine their domain by identifying any values that make their denominator zero.
For instance, if we consider the rational expression \( \frac{3x+7}{(4x+2)(x-1)} \):
For instance, if we consider the rational expression \( \frac{3x+7}{(4x+2)(x-1)} \):
- The denominator \((4x+2)(x-1)\) can be zero at certain values of \(x\).
- Specifically, we set \(4x+2\) and \(x-1\) each equal to zero to find these points.
Solving Equations
To find the values that make the denominator zero, you need to solve simple equations. This is an essential step in determining the domain of a rational expression.
Let's explore these steps using our previous expression \( \frac{3x+7}{(4x+2)(x-1)} \):
Let's explore these steps using our previous expression \( \frac{3x+7}{(4x+2)(x-1)} \):
- First, solve the equation \( 4x + 2 = 0 \). Subtract 2 from both sides which gives \( 4x = -2 \). Then divide by 4, resulting in \( x = -\frac{1}{2} \).
- Next, solve \( x - 1 = 0 \). Adding 1 to both sides results in \( x = 1 \).
Other exercises in this chapter
Problem 7
Concept Check Match each expression from Group I with the correct choice from Group II. Choices may be used once, more than once, or not at all. (II) \(\begin{a
View solution Problem 7
Factor the greatest common factor from each polynomial. $$(2 y-3)(y+2)+(y+5)(y+2)$$
View solution Problem 7
Simplify each expression. Leave answers with exponents. $$\left(2^{2}\right)^{5}$$
View solution Problem 8
Concept Check Match each expression from Group I with the correct choice from Group II. Choices may be used once, more than once, or not at all. (II) \(\begin{a
View solution