Problem 7
Question
Fill in the blank to complete the trigonometric identity. \( \sin \left(\dfrac{\pi}{2} - u\right) \)= ________
Step-by-Step Solution
Verified Answer
\(\cos u\)
1Step 1: Identifying Trigonometric Identity
The task requires to complete the trigonometric identity. The identity given is of the form \( \sin \left(\dfrac{\pi}{2} - u\right) \). This form is recognized as a standard co-function identity in trigonometry, where the sin of (90 degrees - angle) or in this case \( \dfrac{\pi}{2} - u \) is equal to cos of the same angle.
2Step 2: Applying Trigonometric Identity
Applying the co-function identity to the given problem, the fill in the blank is \( \cos u \). Therefore, the completed trigonometric identity is \( \sin \left(\dfrac{\pi}{2} - u\right) = \cos u\).
Key Concepts
Trigonometric IdentitySine FunctionCosine Function
Trigonometric Identity
Trigonometric identities are like mathematical rules that relate different trigonometric functions to one another. These identities hold true for any angle and are crucial tools in simplifying complex expressions and solving trigonometry problems.
Some of the most common trigonometric identities include the Pythagorean identities, reciprocal identities, and co-function identities. Co-function identities, specifically, describe the relationship between complementary angles.
In this particular exercise, we are looking at a co-function identity:
Some of the most common trigonometric identities include the Pythagorean identities, reciprocal identities, and co-function identities. Co-function identities, specifically, describe the relationship between complementary angles.
In this particular exercise, we are looking at a co-function identity:
- For any angle \( u \), the co-function identity states that \( \sin \left(\frac{\pi}{2} - u\right) = \cos u \).
Sine Function
The sine function, often represented as \( \sin \theta \), is a fundamental concept in trigonometry. It measures the ratio of the length of the side of a right triangle opposite the angle to the length of the hypotenuse.
The sine of an angle in a right triangle is a very useful function in a variety of contexts, ranging from theoretical mathematics to practical applications such as physics and engineering.
Key properties of the sine function include:
The sine of an angle in a right triangle is a very useful function in a variety of contexts, ranging from theoretical mathematics to practical applications such as physics and engineering.
Key properties of the sine function include:
- It's a periodic function, repeating its values every \( 2\pi \) radians or 360 degrees.
- Its range is between -1 and 1, inclusive.
- Sine is an odd function, meaning that \( \sin(-\theta) = -\sin \theta \).
Cosine Function
The cosine function, denoted by \( \cos \theta \), also plays a central role in trigonometry, similar to the sine function. It's defined as the ratio of the length of the adjacent side of a right triangle to the length of the hypotenuse.
This function helps in modeling a wide range of phenomena, from calculating the trajectory of objects to analyzing electrical circuits.
Here are a few important properties of the cosine function:
This function helps in modeling a wide range of phenomena, from calculating the trajectory of objects to analyzing electrical circuits.
Here are a few important properties of the cosine function:
- It is periodic, like sine, with a period of \( 2\pi \) radians or 360 degrees.
- The cosine function is even, which means \( \cos(-\theta) = \cos \theta \).
- Its value ranges from -1 to 1.
Other exercises in this chapter
Problem 7
In Exercises 7 - 12, find the exact value of each expression. (a) \( \cos\left(\dfrac{\pi}{4} + \dfrac{\pi}{3}\right) \) (b) \( \cos\dfrac{\pi}{4} + \cos \dfrac
View solution Problem 7
In Exercises 5-10, verify that the \( x \)-values are solutions of the equation. \( 3 \tan^2 2x - 1 = 0 \) (a) \( x = \dfrac{\pi}{12} \) (b) \( x = \dfrac{5\pi}
View solution Problem 8
In Exercises 7 - 12, find the exact value of each expression. (a) \( \sin\left(\dfrac{3\pi}{4} + \dfrac{5\pi}{6}\right) \) (b) \( \sin \dfrac{3\pi}{4} + \sin \d
View solution Problem 8
In Exercises 5-10, verify that the \( x \)-values are solutions of the equation. \( 2 \cos^2 4x - 1 = 0 \) (a) \( x = \dfrac{\pi}{16} \) (b) \( x = \dfrac{3\pi}
View solution