Problem 7
Question
Exer. 3-8: Change the polar coordinates to rectangular coordinates. $$ \left(6, \arctan \frac{3}{4}\right) $$
Step-by-Step Solution
Verified Answer
The rectangular coordinates are \(\left(\frac{24}{5}, \frac{18}{5}\right)\).
1Step 1: Understand Polar Coordinates
Polar coordinates are given in the form (\(r\), \(\theta\)), where \(r\) is the radius or distance from origin, and \(\theta\) is the angle in radians from the positive x-axis.
2Step 2: Identify the Given Information
Here, \(r = 6\) and \(\theta = \arctan\left(\frac{3}{4}\right)\).
3Step 3: Relationship to Rectangular Coordinates
To convert from polar to rectangular coordinates, use the equations: \(x = r \cos \theta\)and \(y = r \sin \theta\).
4Step 4: Determine \(\theta\) Using Tangent
Since \(\theta = \arctan\left(\frac{3}{4}\right)\), we know that \(\tan \theta = \frac{3}{4}\). We need to find \(\cos \theta\) and \(\sin \theta\) that satisfy this ratio.
5Step 5: Use Pythagorean Theorem
Create a right triangle where the opposite side is 3 and the adjacent side is 4. Since \(\tan \theta = \frac{3}{4}\), the hypotenuse \(h\) can be found using:\[h = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5\].Thus, \(\cos \theta = \frac{4}{5}, \sin \theta = \frac{3}{5}\).
6Step 6: Calculate \(x\) and \(y\)
Using the relationships:\(x = r \cos \theta = 6 \times \frac{4}{5} = \frac{24}{5}\)and \(y = r \sin \theta = 6 \times \frac{3}{5} = \frac{18}{5}\).
7Step 7: Final Rectangular Coordinates
Thus, the rectangular coordinates are:\(x = \frac{24}{5}\)and \(y = \frac{18}{5}\).Hence, the rectangular coordinates are \(\left(\frac{24}{5}, \frac{18}{5}\right)\).
Key Concepts
Polar CoordinatesRectangular CoordinatesTrigonometric FunctionsPythagorean Theorem
Polar Coordinates
Polar coordinates are an alternative way of representing points in a plane using a radial distance and an angle. Think of it as describing a point by saying how far it is and in which direction you need to go. This system is especially useful in scenarios known for their circular symmetry, such as in physics dealing with orbits.
In polar coordinates, a point is denoted as \((r, \theta)\). Here, \(r\) is the distance from the origin, and \(\theta\) is the angle measured from the positive x-axis in the counter-clockwise direction.
Key points to remember:
In polar coordinates, a point is denoted as \((r, \theta)\). Here, \(r\) is the distance from the origin, and \(\theta\) is the angle measured from the positive x-axis in the counter-clockwise direction.
Key points to remember:
- \(r\) can be any non-negative number, representing the radius.
- \(\theta\) is usually expressed in radians but can also be in degrees.
- The origin itself can have a coordinate of \((0, \theta)\), where \(\theta\) can be any angle because radius is zero.
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, represent points in a plane using the familiar \((x, y)\) format. This system is named after the philosopher and mathematician René Descartes.
In this system: - The \(x\)-coordinate specifies horizontal position; it can be positive, negative, or zero.- The \(y\)-coordinate specifies vertical position; similarly, it can be positive, negative, or zero.
These coordinates are used mostly in straightforward, everyday geometry and algebra tasks:
In this system: - The \(x\)-coordinate specifies horizontal position; it can be positive, negative, or zero.- The \(y\)-coordinate specifies vertical position; similarly, it can be positive, negative, or zero.
These coordinates are used mostly in straightforward, everyday geometry and algebra tasks:
- It's easy to plot points and graph equations.
- They allow simple derivation of straight-line equations using y-intercepts and slopes.
- They are the default when dealing with linear relationships in the plane.
Trigonometric Functions
Trigonometric functions are fundamental in linking angular and linear dimensions. They enable the transition between polar and rectangular coordinates.
Important functions include:
Important functions include:
- Sine (\(\sin\)): It relates an angle in a right triangle to the ratio of the opposite side to the hypotenuse. \(\sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}\).
- Cosine (\(\cos\)): It defines the ratio of the adjacent side to the hypotenuse. \(\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}\).
- Tangent (\(\tan\)): Relates an angle to the ratio of the opposite side to the adjacent side. \(\tan \theta = \frac{\text{opposite}}{\text{adjacent}}\).
- \(x = r \cos \theta\)
- \(y = r \sin \theta\)
Pythagorean Theorem
The Pythagorean Theorem is a fundamental principle in geometry relating the sides of a right triangle. According to this theorem, in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides: \[ a^2 + b^2 = c^2 \]In the context of converting coordinates, you use this theorem to discover relationships between trigonometric ratios.
For instance, in our exercise:
For instance, in our exercise:
- Given \(\tan \theta = \frac{3}{4}\), create sides with lengths 3 and 4.
- Determine the hypotenuse as 5 by applying the theorem: \(\sqrt{3^2 + 4^2} = \sqrt{25} = 5\).
- \(\cos \theta = \frac{4}{5}\)
- \(\sin \theta = \frac{3}{5}\)
Other exercises in this chapter
Problem 6
Exer. 1-14: Find the vertices and foci of the ellipse. Sketch its graph, showing the foci. $$ y^{2}+9 x^{2}=9 $$
View solution Problem 7
Exer. 1-12: Find the eccentricity, and classify the conic. Sketch the graph, and label the vertices. $$ r=\frac{4}{\cos \theta-2} $$
View solution Problem 7
Find the vertices, the foci, and the equations of the asymptotes of the hyperbola. Sketch its graph, showing the asymptotes and the foci. $$y^{2}-4 x^{2}=16$$
View solution Problem 7
Exer. 1-12: Find the vertex, focus, and directrix of the parabola. Sketch its graph, showing the focus and the directrix. $$ (y-2)^{2}=\frac{1}{4}(x-3) $$
View solution