Problem 7
Question
Exer. 3-10: Find the \(n\)th term, the fifth term, and the tenth term of the arithmetic sequence. $$ -7,-3.9,-0.8,2.3, \ldots $$
Step-by-Step Solution
Verified Answer
The nth term is \(3.1n - 10.1\). The 5th term is \(5.4\), and the 10th term is \(20.9\).
1Step 1: Identify the common difference
In an arithmetic sequence, the difference between each pair of consecutive terms (known as the common difference \(d\)) is constant. The first two terms in this sequence are \(-7\) and \(-3.9\). Calculate \(d\) by subtracting the first term from the second term: \((-3.9) - (-7) = 3.1\). Hence, \(d = 3.1\).
2Step 2: Write the general formula for the n-th term
The formula for the \(n\)th term \(a_n\) in an arithmetic sequence is given by \(a_n = a_1 + (n-1) \, d\), where \(a_1\) is the first term and \(d\) is the common difference. For this sequence, \(a_1 = -7\) and \(d = 3.1\).
3Step 3: Find the n-th term formula
Substitute \(a_1 = -7\) and \(d = 3.1\) into the formula: \(a_n = -7 + (n-1) \, 3.1\). Simplify: \(a_n = -7 + 3.1n - 3.1 = 3.1n - 10.1\). Thus, the formula for the \(n\)th term is \(a_n = 3.1n - 10.1\).
4Step 4: Calculate the 5th term
To find the 5th term, substitute \(n=5\) into the formula: \(a_5 = 3.1 \times 5 - 10.1\). Calculate: \(a_5 = 15.5 - 10.1 = 5.4\). Therefore, the 5th term is \(5.4\).
5Step 5: Calculate the 10th term
To find the 10th term, substitute \(n=10\) into the formula: \(a_{10} = 3.1 \times 10 - 10.1\). Calculate: \(a_{10} = 31 - 10.1 = 20.9\). Therefore, the 10th term is \(20.9\).
Key Concepts
Common Differencen-th Term FormulaSequence Calculation
Common Difference
In an arithmetic sequence, each term after the first is formed by adding a constant value, known as the "common difference." This difference, often denoted by \(d\), is what sets arithmetic sequences apart from other types of sequences. For instance, in the sequence \(-7, -3.9, -0.8, 2.3, \ldots\), the common difference is the change between any two consecutive terms.
To calculate this, subtract the first term from the second:
This value is added repeatedly to get from one term to the next in the sequence.
Understanding the common difference is essential because it directly influences how the sequence progresses and it's a key part of finding any term in the sequence using an arithmetic method.
To calculate this, subtract the first term from the second:
- \((-3.9) - (-7) = 3.1\).
This value is added repeatedly to get from one term to the next in the sequence.
Understanding the common difference is essential because it directly influences how the sequence progresses and it's a key part of finding any term in the sequence using an arithmetic method.
n-th Term Formula
The n-th term formula is a powerful tool in arithmetic sequences. It helps you find any term in the sequence without listing all the previous terms. The general formula for the n-th term, \(a_n\), is:
For our given sequence, \(a_1 = -7\) and \(d = 3.1\). Substituting these into our generic formula provides us a specific formula for this sequence:
- \(a_n = a_1 + (n-1) \cdot d\)
For our given sequence, \(a_1 = -7\) and \(d = 3.1\). Substituting these into our generic formula provides us a specific formula for this sequence:
- \(a_n = -7 + (n-1) \cdot 3.1\)
- \(a_n = 3.1n - 10.1\).
Sequence Calculation
Sequence calculation is about using the tools and formulas we've discussed to find specific terms in an arithmetic sequence. Using the n-th term formula, \(a_n = 3.1n - 10.1\), you can find terms such as the 5th or the 10th term by substituting the term number \(n\) directly.
For example, to calculate the 5th term:
Similarly, for the 10th term:
This method is straightforward and efficient for finding terms in an arithmetic sequence without needing to add the common difference repeatedly.
For example, to calculate the 5th term:
- Substitute \(n = 5\) into the formula: \(a_5 = 3.1 \times 5 - 10.1\).
- Do the arithmetic: \(a_5 = 15.5 - 10.1 = 5.4\).
Similarly, for the 10th term:
- Substitute \(n = 10\) into the formula: \(a_{10} = 3.1 \times 10 - 10.1\).
- Calculate: \(a_{10} = 31 - 10.1 = 20.9\).
This method is straightforward and efficient for finding terms in an arithmetic sequence without needing to add the common difference repeatedly.
Other exercises in this chapter
Problem 7
\(P(6,1)\)
View solution Problem 7
Exer. 1-26: Prove that the statement is true for every positive integer \(n\). $$ 1+2 \cdot 2+3 \cdot 2^{2}+\cdots+n \cdot 2^{n-1}=1+(n-1) \cdot 2^{n} $$
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Find the \(n\)th term, the fifth term, and the eighth term of the geometric sequence. $$2,6,18,54, \ldots$$
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Exer. 1-8: Find the number. $$ C(5,5) $$
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