Problem 7
Question
Evaluate the indicated integral. $$\begin{aligned} &4\\\ &\int \frac{\sin x}{\sqrt{\cos x}} d x \end{aligned}$$
Step-by-Step Solution
Verified Answer
The integral of the given function is \(-8\sqrt{\cos x}+C\)
1Step 1: Substitute
Firstly, let \(u = \cos x\). Then, \(du = -\sin x~dx\). The negative sign can be adjusted by multiplying by -1.
2Step 2: Substitute variable u into integral and adjust the negative sign
After the substitution, the integral becomes \(-4\int \frac{1}{\sqrt{u}}~du\). Now, the integral can be simplified using the power rule.
3Step 3: Simplify using the power rule
Using the power rule, the integral now becomes \(-4(2u^\frac{1}{2})+C\).
4Step 4: Substitute u back
As the last step, substitute u back into the result. So, \(-4(2u^\frac{1}{2})+C\) becomes \(-4(2\sqrt{\cos x})+C\).\nit's simplified as \(-8\sqrt{\cos x}+C\).
Key Concepts
Integration by SubstitutionTrigonometric IntegralsPower Rule
Integration by Substitution
Integration by substitution is a crucial technique in integral calculus. Think of it as a method for simplifying complex integrals into more manageable forms. It's akin to changing the variables to a new set that simplifies the problem.
Here's how it works:
Here's how it works:
- Firstly, identify a portion of the integral that, when substituted with a new variable, simplifies the integral. In our example, we chose the substitution \( u = \cos x \).
- Next, differentiate your chosen substitution to find \( du \), which is the derivative of \( u \) with respect to \( x \). In the example, \( du = -\sin x \, dx \).
- The negative sign here is adjusted by multiplying by -1. This is important since it helps when arranging the integrand in terms of \( du \).
- Replace all instances of \( x \) in the integral with your substitution \( u \). This transforms the original integral into one in terms of \( u \), often making it simpler to integrate.
Trigonometric Integrals
Trigonometric integrals involve integrating functions that contain trigonometric expressions like \(\sin x\), \(\cos x\), \(\tan x\), and so on. They frequently require substitution and identities to simplify.Let's explore how they work:
- Many trigonometric integrals are approached by using identities to rewrite the expression in a different form. For instance, using identities like \(\sin^2 x + \cos^2 x = 1\) can be immensely helpful.
- Prior experiences hinting at patterns or familiar results often aid in transforming or simplifying trigonometric expressions.
- Substitution can further simplify these integrals, as seen previously. Here, the integral \(\int \frac{\sin x}{\sqrt{\cos x}} \, dx\) simplifies greatly with the choice \( u = \cos x \), making it ready for application of power rules.
Power Rule
The power rule in calculus is a fundamental principle for integration. It allows you to integrate expressions of the form \( x^n \), where \( n \) is any real number, by systematically following a formula.Here's how it applies:
- The generic formula for integration using the power rule is \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), where \( C \) is the constant of integration.
- When applying this rule to expressions with fractional exponents, such as those that arise in substitution, care must be taken to adjust the expression accordingly.
- In our specific problem, after substituting besides \( u = \cos x \), you simplify the expression to a form suitable for the power rule, i.e., \(-4\int u^{-1/2} \, du \). Applying the power rule then yields \(-4(2u^{1/2}) + C \).
Other exercises in this chapter
Problem 6
Write out all terms and compute the sums. $$\sum_{i=3}^{7}\left(i^{2}+i\right)$$
View solution Problem 6
Find the general antiderivative. $$\int\left(x^{3}-2\right) d x$$
View solution Problem 7
Use Part I of the Fundamental Theorem to compute each integral exactly. $$\int_{0}^{1}\left(x \sqrt{x}+x^{1 / 3}\right) d x$$
View solution Problem 7
Evaluate the integral by computing the limit of Riemann sums. $$\int_{0}^{2} x^{2} d x$$
View solution