Problem 7
Question
Differentiate the functions given in Problems with respect to the independent variable. $$ g(s)=5 s^{7}+2 s^{3}-5 s $$
Step-by-Step Solution
Verified Answer
The derivative is \( g'(s) = 35s^6 + 6s^2 - 5 \).
1Step 1: Apply the Power Rule
The function to differentiate is \( g(s) = 5s^7 + 2s^3 - 5s \). For each term, apply the power rule for differentiation: the derivative of \( s^n \) is \( n \cdot s^{n-1} \).
2Step 2: Differentiate Each Term
Differentiate each term separately:- The derivative of \( 5s^7 \) is \( 35s^6 \).- The derivative of \( 2s^3 \) is \( 6s^2 \).- The derivative of \( -5s \) is \( -5 \).
3Step 3: Combine the Derivatives
Add up all the individual derivatives to get the final derivative of the function:\[ g'(s) = 35s^6 + 6s^2 - 5 \].
Key Concepts
Power RuleDerivativePolynomial Functions
Power Rule
The power rule is a fundamental tool in calculus differentiation. It's often the very first technique taught to differentiate polynomial functions.
This rule states that for any term of the form \( s^n \), the derivative is \( n \cdot s^{n-1} \). Here’s how it works:
This consistent methodical approach makes the power rule easy to use for differentiating terms in a polynomial.
This rule states that for any term of the form \( s^n \), the derivative is \( n \cdot s^{n-1} \). Here’s how it works:
- Identify the exponent \( n \) of the variable \( s \).
- Multiply the entire term by the exponent \( n \).
- Reduce the exponent by one to get the new power of \( s \).
This consistent methodical approach makes the power rule easy to use for differentiating terms in a polynomial.
Derivative
A derivative represents the rate at which a function is changing at any given point. It's the foundation of calculus and an essential concept in understanding changes in mathematical models.
When finding the derivative of a polynomial function, you calculate the derivative of each term individually, using rules like the power rule.
This expression tells you exactly how the original function \( g(s) \) behaves when changing \( s \).
When finding the derivative of a polynomial function, you calculate the derivative of each term individually, using rules like the power rule.
- The derivative is often denoted with a prime symbol, as in \( g'(s) \).
- It helps evaluate the slope or steepness of the curve at every point.
- This slope can illustrate how rapidly a function is increasing or decreasing.
This expression tells you exactly how the original function \( g(s) \) behaves when changing \( s \).
Polynomial Functions
Polynomial functions are expressions made up of variables raised to whole number powers, combined using addition, subtraction, and multiplication.
These functions form the building blocks of many mathematical equations and appear frequently in calculus problems.
Differentiating polynomials involves reducing the degree of each term by one, transforming curves into straighter lines at specific intervals.
These functions form the building blocks of many mathematical equations and appear frequently in calculus problems.
- Terms in a polynomial generally appear in the format \( a_n s^n + a_{n-1} s^{n-1} + ... + a_1 s + a_0 \).
- The highest degree of \( s \) determines the degree of the polynomial.
- Polynomials can describe various curves and shapes, depending on their coefficients and degrees.
Differentiating polynomials involves reducing the degree of each term by one, transforming curves into straighter lines at specific intervals.
Other exercises in this chapter
Problem 7
Differentiate the functions in Problems 1-52 with respect to the independent variable. $$ f(x)=e^{7\left(x^{2}+1\right)^{2}} $$
View solution Problem 7
Use the product rule to find the derivative with respect to the independent variable. $$ f(x)=\frac{1}{5}\left(x^{2}-1\right)\left(x^{2}+1\right) $$
View solution Problem 8
Use the formula $$f(x) \approx f(a)+f^{\prime}(a)(x-a)$$ to approximate the value of the given function. Then compare your result with the value you get from a
View solution Problem 8
Find the derivative at the indicated point from the graph of each function. $$ f(x)=\sin x ; x=\frac{\pi}{2} $$
View solution