Problem 7
Question
Complete the table by writing the given expression in the alternate form. Also give the base and exponent for the exponential form. \begin{tabular}{|c|c|c|c|} \hline Radical form & Exponential form & Base & Exponent \\ \hline\(\sqrt[5]{25}\) & & & \\ \((\sqrt[4]{16})^{-3}\) & \((-27)^{2 / 3}\) & & \\ & & \\ \(-\sqrt{\frac{9}{64}}\) & & & \\ \hline \end{tabular}
Step-by-Step Solution
Verified Answer
Converted radicals to exponents: (\sqrt[5]{25}) = 25^{1/5}; (\sqrt[4]{16})^{-3} = 16^{-3/4}; -\sqrt{\frac{9}{64}} = -\left(\frac{9}{64}\right)^{1/2}.
1Step 1: Convert Radical Form to Exponential Form
To convert a radical expression to an exponential form, we use the property \( \sqrt[n]{a} = a^{1/n} \). For \( \sqrt[5]{25} \), the exponential form is \( 25^{1/5} \).
2Step 2: Identify Base and Exponent - First Expression
For the expression \( 25^{1/5} \), the base is 25 and the exponent is \( \frac{1}{5} \).
3Step 3: Convert Nested Radical and Power
The expression \( (\sqrt[4]{16})^{-3} \) can be converted in steps: first, \( \sqrt[4]{16} \) becomes \( 16^{1/4} \). Raise the exponent to the power of -3: \( (16^{1/4})^{-3} \), which simplifies to \( 16^{-3/4} \).
4Step 4: Identify Base and Exponent - Second Expression
For the expression \( 16^{-3/4} \), the base is 16 and the exponent is \( \frac{-3}{4} \).
5Step 5: Identify Base and Exponent - Third Expression
For the already provided expression \( (-27)^{2/3} \), the base is -27 and the exponent is \( \frac{2}{3} \).
6Step 6: Convert Square Root Form
The expression \( -\sqrt{\frac{9}{64}} \) is the same as \( -\left(\frac{9}{64}\right)^{1/2} \).
7Step 7: Identify Base and Exponent - Fourth Expression
For the expression \( -\left(\frac{9}{64}\right)^{1/2} \), the base is \( \frac{9}{64} \) and the exponent is \( \frac{1}{2} \).
8Step 8: Filling in the Table
Based on our conversions, we can fill the table as follows: \( \begin{tabular}{|c|c|c|c|} \hline Radical form & Exponential form & Base & Exponent \\hline\(\sqrt[5]{25}\) & \(25^{1/5}\) & 25 & \(\frac{1}{5}\) \\((\sqrt[4]{16})^{-3}\) & \(16^{-3/4}\) & 16 & \(\frac{-3}{4}\) \& \((-27)^{2 / 3}\) & -27 & \(\frac{2}{3}\) \\(-\sqrt{\frac{9}{64}}\) & \(-\left(\frac{9}{64}\right)^{1/2}\) & \(\frac{9}{64}\) & \(\frac{1}{2}\) \\hline\end{tabular} \)
Key Concepts
Radical expressionsBase and exponent identificationConverting radical form to exponential form
Radical expressions
Radical expressions involve roots of numbers, like square roots or cube roots. The radical symbol, \( \sqrt{} \), indicates the root we are taking. In cases where there is a number in the index position, \( n \), we refer to it as the \( n \)-th root. For instance, \( \sqrt[5]{25} \) represents the fifth root of 25. This is called a radical expression.
Radical expressions come in various forms, from simple square roots such as \( \sqrt{4} \) to more complex forms like \( \sqrt[3]{27} \) or fractional expressions like \( \frac{\sqrt{7}}{2} \). They are essential in calculus and in various practical applications, especially in engineering and physics.
Radical expressions come in various forms, from simple square roots such as \( \sqrt{4} \) to more complex forms like \( \sqrt[3]{27} \) or fractional expressions like \( \frac{\sqrt{7}}{2} \). They are essential in calculus and in various practical applications, especially in engineering and physics.
- Basic radical form: \( \sqrt{a} \)
- General form: \( \sqrt[n]{a} \)
- Complex form: negative and fractional radicands
Base and exponent identification
Identifying the base and exponent in expressions is a foundational skill in algebra. When you see something like \( a^b \), \( a \) is called the base, and \( b \) is the exponent. These components tell us how many times the base is multiplied by itself.
For example, in the expression \( 25^{1/5} \), 25 is the base and \( \frac{1}{5} \) is the exponent. This signifies the fifth root of 25.
For example, in the expression \( 25^{1/5} \), 25 is the base and \( \frac{1}{5} \) is the exponent. This signifies the fifth root of 25.
- Base: The number being raised in a power notation (here, 25).
- Exponent: The power to which the base is raised (here, \( \frac{1}{5} \)).
Converting radical form to exponential form
Converting radicals to exponentials simplifies manipulation of expressions and is crucial for calculus and algebraic operations. The property \( \sqrt[n]{a} = a^{1/n} \) lets us express radicals using exponents.
For instance, \( \sqrt[5]{25} \) translates to the exponential form \( 25^{1/5} \). This indicates that rather than taking the fifth root, we interpret it as raising 25 to the power of \( \frac{1}{5} \). Similarly, repeating the process with nested radicals, \( (\sqrt[4]{16})^{-3} \) becomes \( 16^{1/4} \) followed by raising it to \(-3\), resulting in \( 16^{-3/4} \).
For instance, \( \sqrt[5]{25} \) translates to the exponential form \( 25^{1/5} \). This indicates that rather than taking the fifth root, we interpret it as raising 25 to the power of \( \frac{1}{5} \). Similarly, repeating the process with nested radicals, \( (\sqrt[4]{16})^{-3} \) becomes \( 16^{1/4} \) followed by raising it to \(-3\), resulting in \( 16^{-3/4} \).
- Use \( a^{1/n} \) for \( \sqrt[n]{a} \)
- Combine with normal powers as \( (a^{m/n}) \) when necessary, meaning take the \( n \)-th root first, then raise to \( m \).
Other exercises in this chapter
Problem 7
Fill in the blanks. When we write \(\sqrt{b^{4}}=b^{2},\) we say that we have _____ the radical expression.
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Fill in the blanks. In an isosceles right triangle, the length of the hypotenuse is \(\square\) times the length of one leg.
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Fill in the blanks. a. The power rule for solving radical equations states that if \(x\) \(y,\) and \(n\) are real numbers and \(x=y,\) then \(x=y\) b. If \(\sq
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