Problem 7
Question
\(\bullet\) In the photoelectric effect, what is the relationship between the threshold frequency \(f_{0}\) and the work function \(\phi ?\)
Step-by-Step Solution
Verified Answer
The relationship is \(\phi = hf_0\).
1Step 1: Understanding Key Concepts
The photoelectric effect involves the ejection of electrons from a metal surface when light shines on it. Two important concepts here are the threshold frequency \(f_{0}\) and the work function \(\phi\). The threshold frequency \(f_0\) is the minimum frequency of light required to eject an electron. The work function \(\phi\) is the minimum energy needed to remove an electron from the surface of the metal.
2Step 2: Relating Energy and Frequency
According to the formula for the energy of a photon, \(E = hf\), where \(h\) is Planck's constant and \(f\) is the frequency. For the photoelectric effect to occur, the energy of the incoming photon \(hf\) must be at least equal to the work function \(\phi\). At the threshold frequency \(f_0\), the energy of the photon is exactly the work function, so \(hf_0 = \phi\).
3Step 3: Formulating the Relationship
Given that the energy of a photon at the threshold frequency is equal to the work function, we can write the equation \(\phi = hf_0\). Thus, the work function is directly proportional to the threshold frequency and can be expressed as the product of Planck's constant and the threshold frequency.
Key Concepts
Work FunctionThreshold FrequencyPlanck's Constant
Work Function
The work function, denoted by \( \phi \), is a crucial concept in understanding the photoelectric effect. It represents the minimum energy required to eject an electron from the surface of a metal. This energy
- is unique to each material, meaning different metals will have different work functions,
- depends on the nature of the material and its surface properties,
- dictates how easily the material can emit electrons when exposed to light.
Threshold Frequency
The threshold frequency \( f_0 \) is the minimum frequency of light that can cause electrons to be emitted from a metal surface. It is intrinsic to the metal and directly linked to its work function. The relationship between the threshold frequency and the energy is given by
- the equation \( E = hf_0 \), with \( E \) being the energy of the photon and \( h \) being Planck's constant.
- If the frequency of the incoming light is below this threshold, no electrons will be emitted, regardless of the light's intensity,
- showing that energy and frequency, not intensity, determine electron emission.
Planck's Constant
Planck's constant \( h \) is a fundamental constant in physics, essential for quantifying the relationship between energy and frequency in quantum theory. It appears in the equation \( E = hf \), which is central to the understanding of the photoelectric effect. Planck's constant has a value of approximately \( 6.626 \times 10^{-34} \text{ Js} \), and it:
- connects the energy of photons (quantum of light) to their frequency,
- plays a pivotal role in the field of quantum mechanics, influencing how we understand the behavior of particles on a small scale.
Other exercises in this chapter
Problem 5
\(\bullet\) The predominant wavelength emitted by an ultraviolet lamp is 248 nm. If the total power emitted at this wavelength is \(12.0 \mathrm{W},\) how many
View solution Problem 6
A photon has momentum of magnitude \(8.24 \times 10^{-28} \mathrm{kg} \cdot \mathrm{m} / \mathrm{s}\) . (a) What is the energy of this photon? Give your answer
View solution Problem 9
\(\bullet\) The photoelectric threshold wavelength of a tungsten surface is 272 \(\mathrm{nm}\) . (a) What are the threshold frequency and work function (in eV)
View solution Problem 10
\(\bullet\) What would the minimum work function for a metal have to be for visible light (having wavelengths between 400 \(\mathrm{nm}\) and 700 \(\mathrm{nm}
View solution