Problem 7
Question
An expression for \(f(x)\) is given. Compute the first, second, and third derivatives of \(f(x)\) with respect to \(x\). \(\sqrt{6 x+5}\)
Step-by-Step Solution
Verified Answer
The first derivative is \( \frac{3}{\sqrt{6x+5}} \), the second is \( -\frac{9}{(6x+5)^{3/2}} \), and the third is \( \frac{81}{(6x+5)^{5/2}} \).
1Step 1: Rewrite the Expression
The function given is \( f(x) = \sqrt{6x + 5} \). It is helpful to rewrite the square root in terms of an exponent. Recall that \( \sqrt{a} = a^{1/2} \). Therefore, \( f(x) = (6x + 5)^{1/2} \).
2Step 2: Find the First Derivative
To find the first derivative, use the chain rule. The chain rule states that if you have a composite function \( g(h(x)) \), then \( \frac{d}{dx}[g(h(x))] = g'(h(x)) \cdot h'(x) \). Here, \( g(u) = u^{1/2} \) and \( h(x) = 6x + 5 \).Taking the derivative of the outside function, \( g(u) \), we get \( \frac{1}{2}u^{-1/2} \). This leads to:\[ f'(x) = \frac{1}{2} (6x + 5)^{-1/2} \cdot 6 \]Thus:\[ f'(x) = \frac{6}{2(6x + 5)^{1/2}} = \frac{3}{\sqrt{6x+5}} \]
3Step 3: Compute the Second Derivative
To find the second derivative, differentiate \( f'(x) = \frac{3}{\sqrt{6x+5}} \). Rewrite \( f'(x) \) as \( 3(6x + 5)^{-1/2} \) and apply the chain rule again:\( u = 6x + 5 \), so \( \frac{d}{dx} u^{-1/2} = -\frac{1}{2} u^{-3/2} \cdot 6 \).Differentiating gives:\[ f''(x) = 3 \cdot -\frac{1}{2} (6x+5)^{-3/2} \cdot 6 \] Simplifying, we find:\[ f''(x) = -\frac{9}{(6x+5)^{3/2}} \]
4Step 4: Derive the Third Derivative
For the third derivative, differentiate \( f''(x) = -\frac{9}{(6x+5)^{3/2}} \) again:Rewrite \( f''(x) \) as \( -9(6x+5)^{-3/2} \) and apply the chain rule:\( u = 6x + 5 \), so \( \frac{d}{dx} u^{-3/2} = -\frac{3}{2} u^{-5/2} \cdot 6 \).Thus:\[ f'''(x) = -9 \cdot -\frac{3}{2} (6x+5)^{-5/2} \cdot 6 \] Simplify:\[ f'''(x) = \frac{81}{(6x+5)^{5/2}} \]
Key Concepts
Chain RuleFirst DerivativeSecond DerivativeThird Derivative
Chain Rule
The chain rule is a useful technique when dealing with composite functions, where one function is nested inside another. In essence, the chain rule helps us differentiate a function that has another function inside it.
For example, if we have a function of the form \( g(h(x)) \), the chain rule teaches us to take the derivative of the outer function \( g \) with respect to the inner function \( h \), and then multiply this by the derivative of \( h(x) \) itself:
For example, if we have a function of the form \( g(h(x)) \), the chain rule teaches us to take the derivative of the outer function \( g \) with respect to the inner function \( h \), and then multiply this by the derivative of \( h(x) \) itself:
- Differentiate \( g \) with respect to \( h \).
- Multiply by the derivative of \( h(x) \).
First Derivative
The first derivative of a function is essentially the rate of change or the slope of the function at any given point. When differentiating \( f(x) = (6x + 5)^{1/2} \), we apply the chain rule as discussed. This involves differentiating the outer function \((u^{1/2})\) and adjusting with the derivative of the inner function \((6x + 5)\).
This results in:
This results in:
- Differentiate the outer: yields \( \frac{1}{2}u^{-1/2} \).
- Derivate the inner: yields \(6\).
Second Derivative
Finding the second derivative involves differentiating the first derivative. In this context, we analyze the second derivative to understand how the function's rate of change is itself changing over time.
For \( f'(x) = \frac{3}{\sqrt{6x+5}} \), rewrite it as \(3(6x + 5)^{-1/2} \) and apply the chain rule again:
For \( f'(x) = \frac{3}{\sqrt{6x+5}} \), rewrite it as \(3(6x + 5)^{-1/2} \) and apply the chain rule again:
- Differentiate using \( u^{-1/2} \).
- Account for the inside \(6x + 5\).
Third Derivative
Proceeding to the third derivative, we differentiate the second derivative \( f''(x) = -\frac{9}{(6x+5)^{3/2}} \). This helps in assessing the change in the function's concavity further. Applying the chain rule as before:
- Start from \( u^{-3/2} \).
- Include \(6x + 5\) effect.
Other exercises in this chapter
Problem 7
Calculate the value of the given inverse trigonometric function at the given point. $$ \arccos (\sqrt{2} / 2) $$
View solution Problem 7
Use the method of implicit differentiation to calculate \(d y / d x\) at the point \(P_{0}\) \(x y^{2}+y x^{2}=6\) \(P_{0}=(1,2)\)
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Assume that \(f: \mathbb{R} \rightarrow \mathbb{R}\) is invertible and differentiable. Compute \(\left(f^{-1}\right)^{\prime}(4)\) from the given information. $
View solution Problem 7
Calculate the derivative of the given expression with respect to \(x\). $$ \sin \left(x^{2}+3 x\right) $$
View solution