Problem 7
Question
An experiment is to be designed to measure the differential cross-section for elastic pion-proton scattering at a CM scattering angle of \(70^{\circ}\) and a pion CM kinetic energy of \(490 \mathrm{keV}\). (The electron-volt \((\mathrm{eV})\) is the atomic unit of energy.) Find the angles in the Lab at which the scattered pions, and the recoiling protons, should be detected, and the required Lab kinetic energy of the pion beam. (The ratio of pion to proton mass is \(1 / 7\).)
Step-by-Step Solution
Verified Answer
Based on the given information and the calculations, determine the lab angles for scattered pions and recoiling protons, and the lab kinetic energy of the pion beam.
1Step 1: Calculate the energy and momentum in the CM system
Using the given CM kinetic energy, we can find the energy of pions and protons in the CM system:
$$E_{\pi, CM} = \frac{1}{2} m_{\pi} v_{\pi, CM}^2 \Rightarrow v_{\pi, CM} = \sqrt{\frac{2 E_{\pi, CM}}{m_{\pi}}}$$
$$E_{p, CM} = \frac{1}{2} m_{p} v_{p, CM}^2 \Rightarrow v_{p, CM} = \sqrt{\frac{2 E_{\pi, CM}}{m_{p}}}$$
Using the conservation of momentum, we have:
$$m_\pi v_{\pi, CM} = m_p v_{p, CM}$$
2Step 2: Calculate the lab frame velocity of the center of mass
We can find the lab frame velocity of the center of mass using the mass ratio and the given CM kinetic energy as:
$$v_{CM} = \frac{v_{\pi, CM} m_\pi}{m_\pi + m_p}$$
3Step 3: Find the final momentum of pions and protons in the lab frame
We have the final CM momenta of pions and protons given by:
$$\vec{p}_{\pi, CM} = m_\pi v_{\pi, CM} \hat{p}_{\pi, CM}$$
$$\vec{p}_{p, CM} = m_p v_{p, CM} \hat{p}_{p, CM}$$
We now need to change the reference frame from CM to LAB. We'll use the Galilean transformation:
$$\vec{p}_{\pi, LAB} = \vec{p}_{\pi, CM} + m_\pi \vec{v}_{CM}$$
$$\vec{p}_{p, LAB} = \vec{p}_{p, CM} + m_p \vec{v}_{CM}$$
4Step 4: Calculate the lab angles of the scattered pions and recoiling protons
Using the transformed momenta in the lab frame, we can find the angles \(\theta_{\pi, LAB}\) and \(\theta_{p, LAB}\):
$$\cos{\theta_{\pi, LAB}} = \frac{\vec{p}_{\pi, LAB} \cdot \hat{p}_0}{|\vec{p}_{\pi, LAB}|}$$
$$\cos{\theta_{p, LAB}} = \frac{\vec{p}_{p, LAB} \cdot \hat{p}_0}{|\vec{p}_{p, LAB}|}$$
where \(\hat{p}_0\) is the unit vector in the direction of the initial pion momentum.
5Step 5: Determine the required lab kinetic energy of the pion beam
Finally, using the momentum in the lab frame for the pion, we can calculate the required lab kinetic energy of the pion beam:
$$E_{\pi, LAB} = \frac{1}{2} m_\pi |\vec{p}_{\pi, LAB}|^2$$
Key Concepts
Elastic ScatteringCM FrameGalilean TransformationKinetic Energy Calculation
Elastic Scattering
In particle physics, elastic scattering refers to the process where particles collide and deflect without any change in their internal states. This means that the kinetic energy and momentum are conserved, though they may be redistributed among the particles.
Elastic scattering is an essential concept in experiments examining the fundamental interactions between particles such as pions and protons.
In elastic scattering, the particles ideally retain their total kinetic energy post-collision, although the distribution of kinetic energy among individual particles can change based on their trajectories.
Elastic scattering is an essential concept in experiments examining the fundamental interactions between particles such as pions and protons.
In elastic scattering, the particles ideally retain their total kinetic energy post-collision, although the distribution of kinetic energy among individual particles can change based on their trajectories.
- The total kinetic energy before the collision equals the total kinetic energy after.
- The internal states of the particles remain unchanged.
- Both energy and momentum are conserved properties.
CM Frame
The center of mass (CM) frame is a reference frame where the total momentum of a system is zero. In scattering experiments, analyzing collisions in the CM frame simplifies calculations since the complexities introduced by motion in other frames are minimized.
In our given problem, the calculations start with the CM frame by establishing the energy and momentum quantities for the particles involved. This is because:
In our given problem, the calculations start with the CM frame by establishing the energy and momentum quantities for the particles involved. This is because:
- It minimizes the complications arising from individual particle motions.
- In this frame, relations between kinetic energy and momentum become straightforward.
Galilean Transformation
Galilean Transformation provides the mathematical tool to switch perspectives between different inertial reference frames. When conducting experiments, observations from the laboratory frame often need translation to the CM frame for simpler analysis. Galilean transformations make this possible by adjusting for relative motion between the frames.
These transformations are based on the principle that relative velocities add up linearly."
Thus, in particle scattering experiments, if you know the velocity in the CM frame, you can determine its laboratory counterpart. This involves:
These transformations are based on the principle that relative velocities add up linearly."
Thus, in particle scattering experiments, if you know the velocity in the CM frame, you can determine its laboratory counterpart. This involves:
- Adding the velocity of the center of mass to the velocity observed in the CM frame for each particle.
Kinetic Energy Calculation
Calculating kinetic energy is fundamental in understanding how particle interactions unfold. Kinetic energy in the context of scattering experiments refers to the energy due to the particles' motion. Given by the expression \(E_k = \frac{1}{2}mv^2\), it represents a scalar quantity depicting the energy a particle possesses in motion.
Within our context, calculations involve the center of mass (CM) and laboratory (LAB) frames:
Within our context, calculations involve the center of mass (CM) and laboratory (LAB) frames:
- In the CM frame, it simplifies the individual kinetic energies of particles based on their relative motion.
- In the LAB frame, the focus lies on adjusting these values according to their velocities in the laboratory setting.
Other exercises in this chapter
Problem 4
Two particles of masses \(m_{1}\) and \(m_{2}\) are attached to the ends of a light spring. The natural length of the spring is \(l\), and its tension is \(k\)
View solution Problem 5
Prove that in an elastic scattering process the angle \(\theta+\alpha\) between the emerging particles is related to the recoil angle \(\alpha\) by $$ \frac{\ta
View solution Problem 8
An unstable particle of mass \(M=m_{1}+m_{2}\) decays into two particles of masses \(m_{1}\) and \(m_{2}\), releasing an amount of energy \(Q .\) Determine the
View solution Problem 12
Obtain the relation between the total kinetic energy in the CM and Lab frames. Discuss the limiting cases of very large and very small mass for the target.
View solution