Problem 7
Question
A parallel beam of light in air makes an angle of 47.5\(^\circ\) with the surface of a glass plate having a refractive index of 1.66. (a) What is the angle between the reflected part of the beam and the surface of the glass? (b) What is the angle between the refracted beam and the surface of the glass?
Step-by-Step Solution
Verified Answer
(a) The angle between the reflected beam and the glass surface is 47.5°. (b) The angle between the refracted beam and the glass surface is 65.4°.
1Step 1: Understanding the Problem
We have a parallel beam of light incident on a glass surface at an angle of 47.5° to the surface normal. The refractive index of the glass is 1.66. We are to find the angles of the reflected and refracted beams in relation to the glass surface.
2Step 1: Calculating the Angle of Reflection
According to the law of reflection, the angle of incidence is equal to the angle of reflection. The angle of incidence is the angle relative to the normal, which is 90° minus the angle with the surface. Therefore, the angle of incidence is 90° - 47.5° = 42.5°. The angle of reflection is also 42.5° from the normal, so the angle between the reflected beam and the surface is 47.5°, same as the angle of incidence with the surface.
3Step 2: Applying Snell's Law for Refraction
Snell's Law describes the refraction of light as it passes through different media. The formula is \( n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \), where \( n_1 \) and \( n_2 \) are the refractive indices of air and glass respectively, and \( \theta_1 \) and \( \theta_2 \) are the angles of incidence and refraction from the normal. Here, \( n_1 = 1 \), \( \theta_1 = 42.5° \), and \( n_2 = 1.66 \).
4Step 3: Calculating the Angle of Refraction
Using Snell's law, substitute the known values: \( 1 \cdot \sin(42.5°) = 1.66 \cdot \sin(\theta_2) \). Solve for \( \sin(\theta_2) \):\[ \sin(\theta_2) = \frac{\sin(42.5°)}{1.66} \approx 0.4163.\]This gives \( \theta_2 \approx \arcsin(0.4163) \approx 24.6° \). This angle is with respect to the normal line.
5Step 4: Finding the Angle with the Surface for Refracted Beam
The refracted beam's angle from the normal is \( 24.6° \), so the angle with the surface is \( 90° - 24.6° = 65.4° \).
Key Concepts
Law of ReflectionRefractive IndexAngle of Incidence
Law of Reflection
The law of reflection is a fundamental principle of optics that applies when light reflects off a surface. It states that the angle of incidence is equal to the angle of reflection.
This means when a light beam hits a surface, the angle at which it arrives (the incidence angle) is the same as the angle at which it leaves the surface (the reflection angle).
Imagine a mirror: if a beam of light hits it at 30°, it reflects away at 30° on the opposite side of the normal line, which is an imaginary line perpendicular to the surface.
This means when a light beam hits a surface, the angle at which it arrives (the incidence angle) is the same as the angle at which it leaves the surface (the reflection angle).
Imagine a mirror: if a beam of light hits it at 30°, it reflects away at 30° on the opposite side of the normal line, which is an imaginary line perpendicular to the surface.
- **Critical in design:** This principle is crucial in optical technologies like telescopes and cameras.
- **Simple understanding:** Think of playing pool; the angle you hit the ball against the side rail is how it will bounce off.
Refractive Index
The refractive index is a measure of how much a ray of light bends, or refracts, as it passes between different media.
Every material has a unique refractive index, which tells you how slower light travels in that medium compared to a vacuum.
The refractive index is a ratio given by the speed of light in a vacuum divided by the speed of light in the material.
For example, a refractive index of 1.66 means light travels 1.66 times slower in the glass than in a vacuum.
Every material has a unique refractive index, which tells you how slower light travels in that medium compared to a vacuum.
The refractive index is a ratio given by the speed of light in a vacuum divided by the speed of light in the material.
For example, a refractive index of 1.66 means light travels 1.66 times slower in the glass than in a vacuum.
- **Material property:** This number changes based on the substance, like water (1.33), glass (around 1.5–1.9), or diamond (2.42).
- **Key in lens crafting:** Knowing these values helps engineers design lenses that correct vision or focus light properly.
Angle of Incidence
The angle of incidence is a crucial aspect whenever light interacts with surfaces. It is defined as the angle between the incoming light ray and the normal line of the surface.
To find this angle, use the surface angle and subtract it from 90°, the angle of the normal.
In our scenario, the light beam hits the glass at 47.5° to the surface, meaning its incidence angle is 42.5° from the normal line.
To find this angle, use the surface angle and subtract it from 90°, the angle of the normal.
In our scenario, the light beam hits the glass at 47.5° to the surface, meaning its incidence angle is 42.5° from the normal line.
- **Design importance:** Understanding and calculating this angle helps in creating devices like reflective coatings and solar panels.
- **Everyday application:** If sunlight streams through a window and forms a rectangle on the floor, the angle of incidence dictates the size and position of that light patch.
Other exercises in this chapter
Problem 4
Light with a frequency of \(5.80 \times 10^{14}\) Hz travels in a block of glass that has an index of refraction of 1.52. What is the wavelength of the light (a
View solution Problem 5
A light beam travels at \(1.94 \times 10^8\) m/s in quartz. The wavelength of the light in quartz is 355 nm. (a) What is the index of refraction of quartz at th
View solution Problem 9
Light traveling in air is incident on the surface of a block of plastic at an angle of 62.7\(^\circ\) to the normal and is bent so that it makes a 48.1\(^\circ\
View solution Problem 10
(a) A tank containing methanol has walls 2.50 cm thick made of glass of refractive index 1.550. Light from the outside air strikes the glass at a 41.3\(^\circ\)
View solution