Problem 7
Question
A calculator has a built-in \(\sinh ^{-1} x\) function, but no \(\operatorname{csch}^{-1} x\) function. How do you evaluate \(\operatorname{csch}^{-1} 5\) on such a calculator?
Step-by-Step Solution
Verified Answer
Answer: To find the value of \(\operatorname{csch}^{-1}(5)\), use the formula \(\operatorname{csch}^{-1}(x) = \sinh^{-1}\left(\frac{1}{x}\right)\) and input into the calculator as follows:
$$\operatorname{csch}^{-1}(5) = \sinh^{-1}\left(\frac{1}{5}\right) = \sinh^{-1}(0.2)$$
Calculate the value using the calculator's built-in \(\sinh^{-1}(x)\) function to obtain the result.
1Step 1: Find the relationship between csch and sinh
Recall that the hyperbolic cosecant function, \(\operatorname{csch}(x)\), is defined as the reciprocal of the hyperbolic sine function, \(\sinh(x)\):
$$\operatorname{csch}(x) = \frac{1}{\sinh(x)}$$
Since we want to find \(\operatorname{csch}^{-1}x\), we can rewrite this equation in terms of the inverse functions:
$$x = \frac{1}{\sinh(\operatorname{csch}^{-1}(x))}$$
2Step 2: Solve for csch^(-1)(x) in terms of sinh^(-1)(x)
We now want to isolate \(\operatorname{csch}^{-1}(x)\) in the above equation. Firstly, take the reciprocal of both sides:
$$\frac{1}{x} = \sinh(\operatorname{csch}^{-1}(x))$$
Now, apply the inverse hyperbolic sine function, \(\sinh^{-1}(x)\), to both sides of the equation:
$$\sinh^{-1}\left(\frac{1}{x}\right) = \sinh^{-1}\left(\sinh(\operatorname{csch}^{-1}(x))\right)$$
Since applying the inverse function to the original function will cancel them out, we'll have:
$$\sinh^{-1}\left(\frac{1}{x}\right) = \operatorname{csch}^{-1}(x)$$
3Step 3: Evaluate csch^(-1)(5) using the obtained formula
Using the formula derived in Step 2, we can now evaluate \(\operatorname{csch}^{-1} 5\) using the calculator's built-in \(\sinh^{-1} x\) function:
$$\operatorname{csch}^{-1}(5) = \sinh^{-1}\left(\frac{1}{5}\right)$$
Now, simply input into the calculator:
$$\sinh^{-1}(0.2)$$
This will give the value of \(\operatorname{csch}^{-1}(5)\).
Key Concepts
Hyperbolic FunctionsCalculator UsageInverse Functions
Hyperbolic Functions
Hyperbolic functions are analogs of the trigonometric functions we often use but are based on hyperbolas rather than circles. The main hyperbolic functions are similar in behavior and properties to their trigonometric counterparts. The set includes functions like hyperbolic sine (\(\sinh(x)\)), hyperbolic cosine (\(\cosh(x)\)), and hyperbolic tangent (\(\tanh(x)\)).But there's more to them beyond just these core functions. Just like we have cosecant, secant, and cotangent in trigonometry, we have hyperbolic counterparts:
- Hyperbolic cosecant (\(\operatorname{csch}(x)\))
- Hyperbolic secant (\(\operatorname{sech}(x)\))
- Hyperbolic cotangent (\(\operatorname{coth}(x)\))
Calculator Usage
Using a calculator effectively can simplify the process of dealing with inverse hyperbolic functions. Calculators often come equipped with various functions to make complex calculations simpler but may lack some specific buttons. For example, most calculators have a \(\sinh^{-1}(x)\) button but might not directly provide a \(\operatorname{csch}^{-1}(x)\) feature.To use your calculator to find \(\operatorname{csch}^{-1}(5)\), you can use a trick with the available function \(\sinh^{-1}(x)\):
- First, find the reciprocal of 5, which is 0.2.
- Use the calculator's \(\sinh^{-1}(x)\) function to find \(\sinh^{-1}(0.2)\).
- The result will provide you with the answer for \(\operatorname{csch}^{-1}(5)\).
Inverse Functions
Inverse functions are a crucial concept in mathematics that allows us to 'reverse' a process. With trigonometric or hyperbolic functions, they serve to undo the effects of those original functions. For example, if \(f(x) = y\), an inverse function \(f^{-1}(y) = x\) will essentially retrieve the initial input, provided \(f(x)\) was one-to-one and onto.With hyperbolic functions, the inverse hyperbolic functions include:
- Inverse hyperbolic sine (\(\sinh^{-1}(x)\))
- Inverse hyperbolic cosine (\(\cosh^{-1}(x)\))
- Inverse hyperbolic tangent (\(\tanh^{-1}(x)\))
Other exercises in this chapter
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