Problem 69
Question
The pair of which salts is expected to have the same colour in their freshly prepared aqueous solutions. (a) \(\mathrm{VOCl}_{2}, \mathrm{CuCl}_{2}\) (b) \(\mathrm{CuCl}_{2}, \mathrm{FeCl}_{2}\) (c) \(\mathrm{FeCl}_{2}, \mathrm{VOCl}_{2}\) (d) \(\mathrm{MnCl}_{2}, \mathrm{FeCl}_{2}\)
Step-by-Step Solution
Verified Answer
The pair aVOCl_{2}
and aCuCl_{2}
(option a) will have the same color.
1Step 1: Understanding the Query
We need to determine which pair of salts forms aqueous solutions with the same color. Transition metal ions typically impart a characteristic color to their solutions, depending on the metal and its oxidation state.
2Step 2: Determining Color of CuCl_{2} and FeCl_{2}
The solution of
CuCl_{2}, which contains
Cu^{2+}
ions, is typically blue or green. aFeCl_{2}
contains aFe^{2+}
ions and usually forms a pale green solution.
3Step 3: Analyzing aVOCl_{2}
aVOCl_{2}
contains aVO^{2+}
ions, which generally give a purple or blue-colored solution, resembling the expected color for aCuCl_{2} aqueous solutions.
4Step 4: Comparing aFeCl_{2} Against Other Salts
Given the color of aFeCl_{2}
(pale green), compare it with others. Notably, aMnCl_{2}
forms a faint pink solution, different from aFeCl_{2}.
5Step 5: Conclusion Based on Observations
Comparing the solutions of aVOCl_{2}
and aCuCl_{2}
reveals they both can form solutions with a blue hue, unlike the other pairs examined.
Key Concepts
Aqueous Solution ColoringOxidation StatesTransition Metal IonsColoration of Metal Salts
Aqueous Solution Coloring
In the world of chemistry, particularly when studying transition metals, one of the fascinating phenomena is the coloring of aqueous solutions. This coloration occurs because transition metal ions absorb visible light, promoting electrons to higher energy levels. The color we perceive is the complementary color of the absorbed light.
For instance, a solution of copper(II) chloride, \( \text{CuCl}_2 \), is typically blue or green because it absorbs light in the red to yellow part of the spectrum. Vanadium(II) chloride, \( \text{VOCl}_2 \), in aqueous solution, also shows a blue or purple color caused by similar absorption properties in slightly different spectral regions.
To distinguish these colors in solutions, it is essential to understand the behavior of electrons in various oxidation states and how they interact with light.
For instance, a solution of copper(II) chloride, \( \text{CuCl}_2 \), is typically blue or green because it absorbs light in the red to yellow part of the spectrum. Vanadium(II) chloride, \( \text{VOCl}_2 \), in aqueous solution, also shows a blue or purple color caused by similar absorption properties in slightly different spectral regions.
To distinguish these colors in solutions, it is essential to understand the behavior of electrons in various oxidation states and how they interact with light.
Oxidation States
The concept of oxidation states is crucial when analyzing the color of solutions containing transition metal ions. Oxidation states refer to the degree of oxidation of an element, represented by integers. These states profoundly affect the electronic structure and, consequently, the physical properties such as color.
For transition metals like copper and iron, their common oxidation states, \( \text{Cu}^{2+} \) and \( \text{Fe}^{2+} \), result in them having distinct colors in solution. Copper chloride \( \text{CuCl}_2 \) in the +2 oxidation state exhibits a characteristic blue-green color. On the other hand, iron chloride \( \text{FeCl}_2 \) with \( \text{Fe}^{2+} \) ions, appears pale green.
For transition metals like copper and iron, their common oxidation states, \( \text{Cu}^{2+} \) and \( \text{Fe}^{2+} \), result in them having distinct colors in solution. Copper chloride \( \text{CuCl}_2 \) in the +2 oxidation state exhibits a characteristic blue-green color. On the other hand, iron chloride \( \text{FeCl}_2 \) with \( \text{Fe}^{2+} \) ions, appears pale green.
- The electron configuration of the metal ion is affected by its oxidation state, thus influencing the color.
- Different oxidation states can shift the wavelengths of absorbed light, leading to varied perceptions of color.
Transition Metal Ions
Transition metal ions are unique due to their d-orbital electrons, which are primarily responsible for their distinct characteristics. Due to their partially filled d-subshells, transition metals display variable oxidation states and colorful compounds.
The ions in solution interact with surrounding water molecules via their electric fields. This interaction, known as complex formation, affects the energy levels of the d-orbitals. For example:
The ions in solution interact with surrounding water molecules via their electric fields. This interaction, known as complex formation, affects the energy levels of the d-orbitals. For example:
- \( \text{Cu}^{2+} \) ions in water lead to blue-colored solutions due to d-d electron transitions.
- \( \text{VO}^{2+} \) ions create blue or purple solutions, depending on conditions like pH.
Coloration of Metal Salts
The coloration observed in metal salts dissolved in water is a direct consequence of the transition metal present and its associated ions. Different metal salts offer various hues, which arise from specific electron transitions within the metal's d-orbitals.
Examples of such coloration include:
Examples of such coloration include:
- Cupric chloride \( \text{CuCl}_2 \), offering a vivid blue or green.
- Ferrous chloride \( \text{FeCl}_2 \) giving a subtle pale green.
- Manganese chloride \( \text{MnCl}_2 \) revealing a faint pink.
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