Problem 69
Question
The given function \(f\) is one-to-one. Find \(f^{-1}(x)\). $$f(x)=\frac{1-2 x}{3 x}$$
Step-by-Step Solution
Verified Answer
The inverse function is \(f^{-1}(x) = \frac{1}{3x + 2}\).
1Step 1: Swap Function and Variable
Since we are finding the inverse of the function, we start by rewriting the function equation with the dependent \(y\) and independent \(x\) variables interchanged. The equation is \(y = \frac{1-2x}{3x}\). For the inverse, replace \(f(x)\) with \(y\) and \(x\) with \(y\), giving us \(x = \frac{1-2y}{3y}\).
2Step 2: Clear the Fraction
To eliminate the fraction, multiply both sides by \(3y\): \(3xy = 1 - 2y\). This expression helps us to isolate \(y\).
3Step 3: Rearrange Equation
Reorganize the expression to isolate terms with \(y\) on one side: \(3xy + 2y = 1\).
4Step 4: Factor Out \\(y\\)
Factor \(y\) from the terms on the left: \(y(3x + 2) = 1\). This simplification helps us solve for \(y\).
5Step 5: Solve for \\(y\\)
Divide both sides by \(3x + 2\) to isolate \(y\): \(y = \frac{1}{3x + 2}\). This is our inverse function: \(f^{-1}(x) = \frac{1}{3x + 2}\).
Key Concepts
One-to-One FunctionsSolving EquationsAlgebraic Manipulation
One-to-One Functions
Understanding one-to-one functions is crucial for working with inverse functions. A one-to-one function is a special type of function where each element of the domain is paired with a unique element of the range. This means no two different input values produce the same output value.
This unique pairing is significant because it guarantees that the function has an inverse. If a function is not one-to-one, it may not be possible to reverse the pairing and define a function that "undoes" the original function.
This unique pairing is significant because it guarantees that the function has an inverse. If a function is not one-to-one, it may not be possible to reverse the pairing and define a function that "undoes" the original function.
- A simple way to test if a function is one-to-one is using the Horizontal Line Test. If any horizontal line crosses the graph of the function at most once, then the function is one-to-one.
- Knowing a function is one-to-one gives confidence that we can safely find and work with its inverse.
Solving Equations
Solving equations is a fundamental skill in finding inverse functions, as it involves manipulating an equation until we isolate one variable in terms of another. In finding the inverse, you start by swapping the dependent and independent variables, then solve for the new output variable.
Here’s the step-by-step process reflected in the example function:
Here’s the step-by-step process reflected in the example function:
- Start by replacing the function notation with algebraic variables, i.e., replace \(f(x)\) with \(y\).
- Switch the roles of \(x\) and \(y\) to begin finding the inverse, which essentially means writing the output as an input.
- Next, solve the resulting equation for \(y\) by performing algebraic operations to isolate \(y\).
Algebraic Manipulation
Algebraic manipulation is the process of rearranging equations to isolate specific variables using operations like addition, subtraction, multiplication, division, and factorization.
In our example, the goal is to solve for \(y\) (which will become the inverse function). Here's a recap of critical algebraic steps:
In our example, the goal is to solve for \(y\) (which will become the inverse function). Here's a recap of critical algebraic steps:
- Start by eliminating fractions by multiplying both sides by a common denominator, simplifying the equation into a more workable form.
- Reorder terms to gather similar or related terms which help in simplifying and solving equations.
- Factor out necessary terms to isolate the variable of interest conveniently. This uses distribution in reverse.
- Finally, divide by remaining coefficients to completely isolate \(y\).
Other exercises in this chapter
Problem 68
Use a graphing calculator to find the solution of each equation. Round your result to the nearest thousandth. $$1.5^{\ln x}=10^{0.5}$$
View solution Problem 68
The graph of \(y=e^{x-3}\) can be obtained by translating the graph of \(y=e^{x}\) to the right 3 units. Find a constant \(C\) such that the graph of \(y=C e^{x
View solution Problem 69
Use the properties of logarithms to rewrite each logarithm if possible. Assume that all variables represent positive real numbers. $$\log _{5} \frac{5 \sqrt{7}}
View solution Problem 69
Solve each formula for the indicated variable. $$r=p-k \ln t, \text { for } t$$
View solution