Problem 69
Question
Solve each of the equations. $$a^{2}=5 a$$
Step-by-Step Solution
Verified Answer
The solutions are \( a = 0 \) and \( a = 5 \).
1Step 1: Set the Equation to Zero
Start by moving all terms to one side of the equation to set it to zero. This gives us: \[ a^2 - 5a = 0 \]
2Step 2: Factor the Equation
Factor the equation by taking the common factor of \(a\) out of each term. The factored form of the equation is:\[ a(a - 5) = 0 \]
3Step 3: Apply the Zero Product Property
Use the zero product property, which states that if a product of two terms equals zero, then at least one of the terms must be zero. So, set each factor to zero:1. \( a = 0 \)2. \( a - 5 = 0 \)
4Step 4: Solve for 'a' from Each Factor
Solve each equation from the previous step:1. From \( a = 0 \), we have \( a = 0 \).2. From \( a - 5 = 0 \), solve for \( a \) by adding 5 to both sides, resulting in \( a = 5 \).
Key Concepts
Zero Product PropertyFactoringSetting Equations to Zero
Zero Product Property
When dealing with quadratic equations, the Zero Product Property is an essential concept. It states that if the product of two numbers is zero, then at least one of the two numbers must be zero. This property is useful in solving quadratic equations that have been factored into the form \[ (x - r)(x - s) = 0 \]Here, at least one of the factors \( (x - r) \) or \( (x - s) \) must equal zero to satisfy the equation:
- Set \( (x - r) = 0 \) to find one potential solution \( x = r \)
- Set \( (x - s) = 0 \) to find another potential solution \( x = s \)
Factoring
Factoring is a method used to simplify quadratic equations, making them easier to solve by breaking them into their component terms. Consider the equation \( a^2 - 5a = 0 \). The goal is to express this equation as the product of its factors.To factor \( a^2 - 5a \), we look for common factors among the terms:
- Both terms, \( a^2 \) and \( 5a \), have \( a \) as a common factor.
- By factoring out \( a \), we rewrite the equation as \( a(a - 5) = 0 \).
Setting Equations to Zero
To effectively use the methods of factoring and the Zero Product Property, it's crucial to first set the equation to zero. This preparation step involves rearranging the equation to have zero on one side. For example, starting with \( a^2 = 5a \), we need to collect all terms on one side, transforming it into \( a^2 - 5a = 0 \).This step is essential because it
- Allows for factoring, which simplifies the equation into more manageable components.
- Sets the stage for using the Zero Product Property to find solutions.
Other exercises in this chapter
Problem 69
Should help you pull together all of the factoring techniques of this chapter. Factor completely each polynomial, and indicate any that are not factorable using
View solution Problem 69
Find all real number solutions for each equation. $$6 x^{3}+24 x=0$$
View solution Problem 69
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(2 x+3)^{3}$$
View solution Problem 69
Find each quotient. $$\frac{-72 x^{2} y^{4}}{-8 x^{2} y^{4}}$$
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