Problem 69
Question
Solve each equation. \(|-2 x-3|=|x+1|\)
Step-by-Step Solution
Verified Answer
Solutions: \(x = -\frac{4}{3}\) and \(x = -2\).
1Step 1: Understand the Absolute Value Equation
The equation is \[|-2x - 3| = |x + 1|\].Absolute value equations such as this one require considering both the positive and negative cases for each side of the equation. We will solve it by considering different scenarios for the expressions inside the absolute values.
2Step 2: Consider the Positive Case
In this case, both expressions are positive, which gives the equation:\[-2x - 3 = x + 1\]. To solve for x, add 2x to both sides:\[-3 = 3x + 1\]. Subtract 1 from both sides:\[-4 = 3x\]. Finally, divide each side by 3 to isolate x:\[x = -\frac{4}{3}\].
3Step 3: Consider the Negative Case of the Left Expression
In this scenario, the left-hand side is the negative of the right, giving:\[-(-2x - 3) = x + 1\], which simplifies to:\[2x + 3 = x + 1\]. Subtract x from both sides:\[x + 3 = 1\]. Then subtract 3 from both sides:\[x = -2\].
4Step 4: Consider the Negative Case of the Right Expression
Here, the right expression is negative, leading to:\[-2x - 3 = -(x + 1)\], which simplifies to:\[-2x - 3 = -x - 1\]. Add x to both sides:\[-x - 3 = -1\]. Then add 3 to both sides:\[-x = 2\]. Multiply both sides by -1 to solve for x:\[x = -2\]. Note that this yields the same solution as the previous scenario, which is consistent due to overlapping regions of inequality.
5Step 5: Verify Solutions and Write Conclusion
We found two potential solutions: \[x = -\frac{4}{3}\] and \[x = -2\]. Substitute these back into the original equation to verify. For \[x = -\frac{4}{3}\], both sides evaluate to \[\frac{5}{3}\]. For \[x = -2\], both sides evaluate to \[1\]. Thus, both values satisfy the original equation, confirming our solutions.
Key Concepts
Solving EquationsAlgebra ConceptsCollege AlgebraEquation Verification
Solving Equations
Equations are mathematical statements that show that two expressions are equal. Solving equations is about finding the value of the variable that makes this statement true. In the case of absolute value equations, like \(|-2x - 3| = |x + 1|\), solving involves considering different scenarios due to the nature of absolute values. Absolute value measures the distance of a number from zero on the number line, regardless of direction. Hence, both positive and negative cases must be evaluated.
- For the positive case, assume both expressions equal their positive forms.
- Switching to the negative scenarios helps disclose all potential solutions.
Algebra Concepts
Algebra is more than just manipulating symbols. It involves understanding how numbers and variables relate within an equation. In the given exercise, recognizing that the symbols |...| represent absolute values is crucial. It leads to forming different cases, which ultimately helps in solving the equation.
- Understand the role of equal expressions formed by the absolute values.
- Break the equation into simpler parts to solve step by step.
- Utilize inverse operations like addition, subtraction, multiplication, and division.
College Algebra
College algebra pulls together different mathematical concepts that are well beyond basic high school algebra. It requires a deeper understanding of relations and functions. When tasked with solving an equation involving absolute values like our example, students in college algebra must recognize that it extends beyond routine arithmetic and algebraic procedures.
- Develop skills for abstract thinking and equation manipulation.
- Ability to dissect an equation into manageable pieces.
- Confidence in evaluating different scenarios to find all possible solutions.
Equation Verification
Solving an equation does not end when you find potential solutions. Equation verification is essential to ensure your solutions are correct. It involves substituting the solutions back into the original equation to check their validity.
- Insert each solution individually into the original equation.
- Ensure that both sides of the equation equate upon substitution.
- Dismiss any solutions that do not fulfill the original equation.
Other exercises in this chapter
Problem 68
Solve each inequality and express the solution set using interval notation. \(-3(2 x+1)>-2(x+4)\)
View solution Problem 68
Use an algebraic approach to solve each problem. Are the equations \(7=9 x-4\) and \(9 x-4=7\) equivalent equations? Defend your answer.
View solution Problem 69
Solve each problem by setting up and solving an appropriate inequality. How do you know by inspection that the solution set of the inequality \(x+3>x+2\) is the
View solution Problem 69
Solve each inequality and express the solution set using interval notation. \(-3(x+2)>2(x-6)\)
View solution