Problem 69
Question
Smoke Detectors Americium-241, a radioisotope used in smoke detectors, is produced by bombarding plutonium-238 with neutrons to produce plutonium-240, which is bombarded with neutrons to produce plutonium-241. The plutonium-241 decays to americium-241. Write the balanced nuclear equations for each reaction.
Step-by-Step Solution
Verified Answer
The balanced nuclear equations for the production of Americium-241 are as follows:
1. \( {}^{238}Pu + {}^{1}n \rightarrow {}^{240}Pu \)
2. \( {}^{240}Pu + {}^{1}n \rightarrow {}^{241}Pu \)
3. \( {}^{241}Pu \rightarrow {}^{241}Am + β^{-} \)
1Step 1: Reaction 1: Bombardment of Plutonium-238 with neutrons to produce Plutonium-240
In this reaction, we have Plutonium-238 and a neutron as the reactants, and Plutonium-240 as the product. To balance this equation, we can represent plutonium with the symbol \(Pu\) and the neutron with the symbol \(n\). The equation is:
\[{}^{238}Pu + {}^{1}n \rightarrow {}^{240}Pu\]
The mass numbers are conserved (238 + 1 = 240).
2Step 2: Reaction 2: Bombardment of Plutonium-240 with neutrons to produce Plutonium-241
In this reaction, we have Plutonium-240 and a neutron as the reactants, and Plutonium-241 as the product. To balance this equation, we can represent plutonium with the symbol \(Pu\) and the neutron with the symbol \(n\). The equation is:
\[{}^{240}Pu + {}^{1}n \rightarrow {}^{241}Pu\]
The mass numbers are conserved (240 + 1 = 241).
3Step 3: Reaction 3: Decay of Plutonium-241 to produce Americium-241
In this reaction, we have Plutonium-241 as the reactant and Americium-241 as the product. Plutonium-241 decays through beta decay, in which a neutron is converted into a proton, releasing an electron (also known as a beta particle, represented by the symbol \(β^{-}\)). To balance this equation, we represent plutonium with the symbol \(Pu\) and americium with the symbol \(Am\). The equation is:
\[{}^{241}Pu \rightarrow {}^{241}Am + β^{-}\]
The mass numbers are conserved (241 = 241), and the atomic numbers are also conserved because a neutron is converted into a proton, increasing the atomic number by 1.
Key Concepts
RadioisotopesBeta DecayNeutron Bombardment
Radioisotopes
Radioisotopes are atoms that have an unstable combination of protons and neutrons. This instability causes them to decay over time, releasing radiation in the form of particles or energy. These are not just theoretical; they play practical roles in our daily life.
- The term "radioisotope" combines "radioactive" and "isotope," meaning isotopes that are radioactive.
- Each element can have multiple isotopes. For example, carbon has three naturally occurring isotopes: Carbon-12, Carbon-13, and the radioactive Carbon-14.
- Their decay process leads to the emission of radiation, such as alpha particles, beta particles, or gamma rays.
Beta Decay
Beta decay is a type of radioactive decay where an unstable nucleus transforms by converting a neutron into a proton. This transformation results in the emission of a beta particle, which is, in essence, an electron or a positron.
- In beta minus (\(β^{-}\)) decay, a neutron is converted into a proton, and the emitted beta particle is an electron.
- This process increases the atomic number by 1, as a neutron turns into an additional proton in the nucleus.
- Common examples of beta decay can be seen when isotopes of elements like Carbon-14 and Plutonium-241 decay.
- The equation for beta decay is often written as: \[n
ightarrow p + β^{-} + \bar{ν_e}\]
where \(\bar{ν_e}\) is an antineutrino, which is also emitted during the decay.
Neutron Bombardment
Neutron bombardment is a process where atomic nuclei are targeted and penetrated by neutrons. This results in the formation of a new isotope or even a different element.
- This method is widely used in nuclear reactors and can transmute one element into another or create new isotopes.
- Neutron bombardment is fundamental for nuclear synthesis, as seen in our earlier example where Plutonium-238 is bombarded with neutrons to produce Plutonium-240.
- When a neutron collides with a nucleus, it does not possess a charge, making it ideal for penetrating the electron cloud surrounding the nucleus without being repelled.
- This technique can create isotopes that may undergo further reactions, such as decay or further bombardment, as witnessed in subsequent transformations of Plutonium isotopes.
Other exercises in this chapter
Problem 67
Describe the current limitations of fusion as a power source.
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Why does nuclear fusion require so much heat? How is heat contained within a tokamak reactor?
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Exit signs Exit signs are coated with a paint containing phosphors. These phosphors are activated by the radioisotope tritium \(\left(\begin{array}{l}{3} \\\ {1
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Control Rods Bombarding uranium-235 with neutrons produces samarium-149, which is used in nuclear reactor control rods. What other element is produced?
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