Problem 69
Question
Multiply as indicated. Write each product in standard form. $$3 i(2-i)^{2}$$
Step-by-Step Solution
Verified Answer
The product in standard form is \(12 + 9i\).
1Step 1: Expand the Exponent
First, let's expand the square of the binomial \((2-i)^2\). This can be done by using the formula for squaring a binomial, which is \((a-b)^2 = a^2 - 2ab + b^2\).For \(a = 2\) and \(b = i\), we have:\[(2-i)^2 = 2^2 - 2 \cdot 2 \cdot i + i^2\] \[= 4 - 4i + i^2\]Since \(i^2 = -1\), substitute \(i^2\) with \(-1\):\[= 4 - 4i - 1\]Simplify the expression:\[= 3 - 4i\]
2Step 2: Multiply by the Scalar
Now, we need to multiply the result from Step 1 by \(3i\), as indicated in the original expression. Thus, we are multiplying:\[3i(3 - 4i)\]Distribute \(3i\) across each term inside the parentheses:\(3i \times 3 = 9i\)\(3i \times (- 4i) = -12i^2\)Since \(i^2 = -1\), this becomes:\(-12i^2 = -12(-1) = 12\)Thus, the product is:\[= 12 + 9i\]
3Step 3: Write in Standard Form
The standard form for complex numbers is \(a + bi\), where \(a\) is the real part and \(bi\) is the imaginary part.From Step 2, we have:\[12 + 9i\]This is already in standard form with the real part \(12\) and the imaginary part \(9i\).
Key Concepts
Binomial ExpansionStandard FormImaginary Unit
Binomial Expansion
The Binomial Expansion is a powerful mathematical tool, allowing us to expand expressions raised to a power. It is super helpful in solving polynomial equations. In our exercise, we focused on squaring a binomial, which involves using the formula
- \((a-b)^2 = a^2 - 2ab + b^2\)
- \(a = 2\)
- \(b = i\)
- \((2-i)^2 = 2^2 - 2 imes 2 imes i + i^2\)
- \(= 4 - 4i + i^2\)
- \(= 4 - 4i - 1 = 3 - 4i\)
Standard Form
Writing complex numbers in Standard Form, \(a + bi\), is essential for easy readability and comparison.
This form has two parts:
This form has two parts:
- \(a\) is the real part.
- \(bi\) is the imaginary part.
- \(= 12 + 9i\)
- \(12\) is the real part.
- \(9i\) is the imaginary part.
Imaginary Unit
The Imaginary Unit, represented as \(i\), is a fundamental concept in complex numbers. It is defined with the property:
For example, in our exercise, when expanding and simplifying \((2-i)^2\), the term \(i^2 = -1\) allowed us to simplify the expression.
When multiplying with \(3i\), using \(i^2 = -1\) turned \(-12i^2\) into \(12\).
This transformation is crucial in finding the solution in a form that is easy to understand and work with further.
Understanding \(i\) is key to mastering complex numbers, as it forms the foundation of many advanced topics.
- \(i^2 = -1\)
For example, in our exercise, when expanding and simplifying \((2-i)^2\), the term \(i^2 = -1\) allowed us to simplify the expression.
When multiplying with \(3i\), using \(i^2 = -1\) turned \(-12i^2\) into \(12\).
This transformation is crucial in finding the solution in a form that is easy to understand and work with further.
Understanding \(i\) is key to mastering complex numbers, as it forms the foundation of many advanced topics.
Other exercises in this chapter
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