Problem 69
Question
Interference Two identical tuning forks are struck, one a fraction of a second after the other. The sounds produced are modeled by \(f_{1}(t)=C \sin \omega t\) and \(f_{2}(t)=C \sin (\omega t+\alpha) .\) The two sound waves interfere to produce a single sound modeled by the sum of these functions $$ f(t)=C \sin \omega t+C \sin (\omega t+\alpha) $$ (a) Use the Addition Formula for Sine to show that \(f\) can be written in the form \(f(t)=A \sin \omega t+B \cos \omega t,\) where \(A\) and \(B\) are constants that depend on \(\alpha\) . (b) Suppose that \(C=10\) and \(\alpha=\pi / 3 .\) Find constants \(k\) and \(\phi\) so that \(f(t)=k \sin (\omega t+\phi)\)
Step-by-Step Solution
Verified Answer
a) A = C(1 + \cos\alpha), B = C\sin\alpha. b) f(t) = 10\sqrt{3}\sin (\omega t + \frac{\pi}{6}).
1Step 1: Expand second sine term
Let's begin by expanding the second sine term using the sine addition formula: \( \sin(A + B) = \sin A \cos B + \cos A \sin B \). Here, our expression is \( f_2(t) = C \sin (\omega t + \alpha) \). Applying the formula, we have: \[ C \sin (\omega t + \alpha) = C(\sin \omega t \cos \alpha + \cos \omega t \sin \alpha) \]
2Step 2: Write f(t) as a single function
Now, substitute the expanded form of \( f_2(t) \) back into the original function: \[ f(t) = C \sin \omega t + C(\sin \omega t \cos \alpha + \cos \omega t \sin \alpha) \] Simplifying it gives: \[ f(t) = C \sin \omega t + C \sin \omega t \cos \alpha + C \cos \omega t \sin \alpha \] Combine the sine terms to get: \[ f(t) = C \sin \omega t(1 + \cos \alpha) + C \sin \alpha \cos \omega t \]
3Step 3: Identify constants A and B
We can now identify the constants \( A \) and \( B \) from the equation. By comparing with \ \( f(t) = A \sin \omega t + B \cos \omega t \): \[ A = C(1 + \cos \alpha), \quad B = C \sin \alpha \] So, the function \( f(t) = A \sin \omega t + B \cos \omega t \) is confirmed.
4Step 4: Substitute given values for C and \( \alpha \)
Next, we use the given values \( C = 10 \) and \( \alpha = \frac{\pi}{3} \): \[ A = 10(1 + \cos \frac{\pi}{3}), \quad B = 10 \sin \frac{\pi}{3} \] Knowing that \( \cos \frac{\pi}{3} = \frac{1}{2} \) and \( \sin \frac{\pi}{3} = \frac{\sqrt{3}}{2} \), we substitute: \[ A = 10(1 + \frac{1}{2}) = 15, \quad B = 10 \frac{\sqrt{3}}{2} = 5\sqrt{3} \]
5Step 5: Convert form to k \( \sin (\omega t + \phi) \)
We use the identity \( A \sin \omega t + B \cos \omega t = k \sin(\omega t + \phi) \) where \( k = \sqrt{A^2 + B^2} \) and \( \tan \phi = \frac{B}{A} \). Calculate \( k \): \[ k = \sqrt{15^2 + (5\sqrt{3})^2} = \sqrt{225 + 75} = \sqrt{300} = 10\sqrt{3} \] Calculate \( \phi \): \[ \tan \phi = \frac{5\sqrt{3}}{15} = \frac{\sqrt{3}}{3}\] Thus, \( \phi = \tan^{-1}(\frac{\sqrt{3}}{3}) \), which equals \( \frac{\pi}{6} \).
6Step 6: Final Answer
The rewritten function is \( f(t) = 10\sqrt{3} \sin (\omega t + \frac{\pi}{6}) \).
Key Concepts
Addition Formula for SineTrigonometric IdentitiesAmplitude and Phase Shift
Addition Formula for Sine
The addition formula for sine is a fundamental trigonometric identity that simplifies expressions involving the sum of angles in sine terms. In its basic form, it is expressed as \( \sin(A + B) = \sin A \cos B + \cos A \sin B \). This formula is particularly useful when you need to break down complex trigonometric expressions into more manageable components.
In the context of wave interference, using the addition formula allows us to expand a sine function of the form \( C \sin(\omega t + \alpha) \). This means we can express it as \( C(\sin \omega t \cos \alpha + \cos \omega t \sin \alpha) \).
In the context of wave interference, using the addition formula allows us to expand a sine function of the form \( C \sin(\omega t + \alpha) \). This means we can express it as \( C(\sin \omega t \cos \alpha + \cos \omega t \sin \alpha) \).
- \( \sin \omega t \) and \( \cos \omega t \) are the fundamental trigonometric functions representing the oscillatory nature of waves.
- \( \cos \alpha \) and \( \sin \alpha \) act as scaling factors based on the angle \( \alpha \).
Trigonometric Identities
Trigonometric identities are equations that express relationships between the trigonometric functions of an angle. These identities are extremely useful in simplifying expressions and solving problems that involve periodic components, such as waves and oscillations.
In wave interference, identities help us express a combination of sine and cosine functions in a simpler, single form. A common identity used is the linear combination of sine and cosine functions: \( A \sin \omega t + B \cos \omega t = k \sin(\omega t + \phi) \). In this expression:
In wave interference, identities help us express a combination of sine and cosine functions in a simpler, single form. A common identity used is the linear combination of sine and cosine functions: \( A \sin \omega t + B \cos \omega t = k \sin(\omega t + \phi) \). In this expression:
- \( A \) and \( B \) are constants derived from the wave equations.
- \( k \), the amplitude, is computed as \( k = \sqrt{A^2 + B^2} \).
- \( \phi \), the phase shift, is given by \( \tan \phi = \frac{B}{A} \).
Amplitude and Phase Shift
The concepts of amplitude and phase shift are crucial for understanding the behavior of periodic waveforms, especially in contexts such as sound waves, electromagnetic waves, or any system characterized by oscillations.
- Amplitude (\( k \)): In the context of wave functions, the amplitude is the peak value of the wave, indicating how "strong" or "intense" the wave is. It is calculated using the formula \( k = \sqrt{A^2 + B^2} \) where \( A \) and \( B \) come from the coefficients of sine and cosine terms.
- Phase Shift (\( \phi \)): This parameter indicates how much the wave is shifted horizontally from a reference point. The phase shift can be found using \( \tan \phi = \frac{B}{A} \), and provides insights into the synchrony or out-of-phaseness of waves interacting with each other.
Other exercises in this chapter
Problem 68
\(67-72\). Find the value of the product or sum. $$ 3 \cos 37.5^{\circ} \cos 7.5^{\circ} $$
View solution Problem 68
Verify the identity. $$ \frac{1-\cos x}{\sin x}+\frac{\sin x}{1-\cos x}=2 \csc x $$
View solution Problem 69
\(67-72\). Find the value of the product or sum. $$ \cos 37.5^{\circ} \sin 7.5^{\circ} $$
View solution Problem 69
Verify the identity. $$ \frac{\csc x-\cot x}{\sec x-1}=\cot x $$
View solution