Problem 69
Question
In a beehive each cell is a regular hexagonal prism, as shown in the figure. The amount of wax \(W\) in the cell depends on the apex angle \(\theta\) and is given by $$W=3.02-0.38 \cot \theta+0.65 \csc \theta$$ Bees instinctively choose \(\theta\) so as to use the least amount of wax possible. (a) Use a graphing device to graph \(W\) as a function of \(\theta\) for \(0<\theta<\pi.\) (b) For what value of \(\theta\) does \(W\) have its minimum value? [Note: Biologists have discovered that bees rarely deviate from this value by more than a degree or two.]
Step-by-Step Solution
Verified Answer
The minimum wax is used when \( \theta \approx 120^\circ \) or \( \frac{2\pi}{3} \) radians.
1Step 1: Understand the formula
The wax weight formula given is \( W = 3.02 - 0.38 \cot \theta + 0.65 \csc \theta \). Our task is to examine how the weight \( W \) changes with respect to \( \theta \), where \( \theta \) is the apex angle.
2Step 2: Understand the Interval
The interval for \( \theta \) is from just above 0 to just below \( \pi \) radians \((0 < \theta < \pi)\). This means bee angles typically used are somewhere between these values.
3Step 3: Set up the graph
To graph this function \( W(\theta) \), use a graphing tool capable of handling trigonometric functions. Input \( W = 3.02 - 0.38 \cot \theta + 0.65 \csc \theta \) and adjust the window to \( 0 < \theta < \pi \).
4Step 4: Identify important features
While graphing, look for critical points where the function could have minimum or maximum values. Critical points are usually where the derivative is equal to zero or undefined.
5Step 5: Analyze critical points
To find the minimum, calculate the derivative of \( W \) with respect to \( \theta \), \( W'(\theta) \). Set \( W'(\theta) = 0 \) or examine where it's undefined and solve for \( \theta \).
6Step 6: Confirm the minimum value
Check the behavior of \( W \) at critical points using either the second derivative test or checking the values around these points. This confirms which corresponding \( \theta \) leads to a minimum wax usage.
7Step 7: Note the biological observation
Biologists observe bees typically choose an angle slightly deviated by a degree or two from the ideal angle found by this graphing analysis.
Key Concepts
Trigonometric FunctionsCritical PointsGraphing Trigonometric FunctionsDerivatives in Calculus
Trigonometric Functions
Trigonometric functions are mathematical functions that relate the angles of a triangle to its sides. They are fundamental in studying periodic phenomena, such as waves, and they play a big role in optimization problems in areas including architecture, engineering, and indeed in the natural design of beehive cells.
The key trigonometric functions include sine (\(\sin\theta\)), cosine (\(\cos\theta\)), tangent (\(\tan\theta\)), cotangent (\(\cot\theta\)), secant (\(\sec\theta\)), and cosecant (\(\csc\theta\)). In the context of our hexagonal prism equation:
The key trigonometric functions include sine (\(\sin\theta\)), cosine (\(\cos\theta\)), tangent (\(\tan\theta\)), cotangent (\(\cot\theta\)), secant (\(\sec\theta\)), and cosecant (\(\csc\theta\)). In the context of our hexagonal prism equation:
- \(\cot\theta\) is the cotangent function, defined as \(\cot\theta=\frac{1}{\tan\theta}\) or \(\frac{\cos\theta}{\sin\theta}\).
- \(\csc\theta\) is the cosecant function, defined as \(\csc\theta=\frac{1}{\sin\theta}\).
Critical Points
Critical points in a function are those points where the derivative is zero or undefined. Finding these points helps in identifying maxima, minima, or points of inflection of the function. In the case of our wax equation, identifying such points will tell us the values of \(\theta\) where the weight of the wax, \(W\), is minimized.
To locate critical points:
To locate critical points:
- Calculate the derivative of the function with respect to \(\theta\).
- Set the derivative equal to zero or examine where it may be undefined.
Graphing Trigonometric Functions
Graphing is a powerful visual tool that allows us to better understand the behavior of trigonometric functions over a specified interval. For our beehive equation, graphing \(W(\theta) = 3.02 - 0.38 \cot \theta + 0.65 \csc \theta\) over the interval \(0<\theta<\pi\) helps visualize where wax usage is minimized.
The steps to graph this include:
The steps to graph this include:
- Using a graphing calculator or software, input the function equation.
- Set the interval from just above \(0\) to just below \(\pi\), capturing the range typical for bee behavior.
- Analyze the graph to visually identify dips, which indicate minimum points that correspond to potential wax savings for the bees.
Derivatives in Calculus
Derivatives are essential in calculus for understanding how functions change. By examining the derivative of a function, you can determine critical points, which are vital for optimization tasks like our wax usage problem.
The derivative of the wax function, \(W'(\theta)\), gives us the rate of change of wax weight concerning the angle \(\theta\). To solve for minimizing wax, follow these steps:
The derivative of the wax function, \(W'(\theta)\), gives us the rate of change of wax weight concerning the angle \(\theta\). To solve for minimizing wax, follow these steps:
- Compute the derivative \(W'(\theta)\) using rules for differentiating trigonometric functions such as \(\cot\theta\) and \(\csc\theta\).
- Set \(W'(\theta) = 0\) and solve for \(\theta\) to identify potential minima.
- Consider the second derivative or values around these \(\theta\) to confirm the minima via the second derivative test.
Other exercises in this chapter
Problem 67
The area of a circle is \(72 \mathrm{cm}^{2} .\) Find the area of a sector of this circle that subtends a central angle of \(\pi / 6\) rad.
View solution Problem 68
The time in seconds that it takes for a sled to slide down a hillside inclined at an angle \(\theta\) is \(t=\sqrt{\frac{d}{16 \sin \theta}}\) where \(d\) is th
View solution Problem 69
A car's wheels are 28 in, in diameter. How far (in miles) will the car travel if its wheels revolve \(10,000\) times without slipping?
View solution Problem 70
Turning a Corner \(A\) steel pipe is being carried down a hallway that is 9 ft wide. At the end of the hall there is a rightangled turn into a narrower hallway
View solution