Problem 69
Question
Finding the Component Form of a Vector In Exercises \(67-74\) , find the component form of \(v\) given its magnitude and the angle it makes with the positive \(x\) -axis. Sketch y. $$\begin{array}{ll}{\text { Magnitude }} & {\text { Angle }} \\\ {\|\mathbf{v}\|=\frac{7}{2}} & {\theta=150^{\circ}}\end{array}$$
Step-by-Step Solution
Verified Answer
The component form of the vector \( v \) after carrying out the steps will be your answer.
1Step 1: Conversion of Angle
First, convert the given angle from degrees to radians as trigonometric computations in calculus usually presume radians as the unit for angles. The conversion factor to move from degrees to radians is \( \frac{\pi}{180} \). So, \( \theta =150^{\circ}=150 * \frac{\pi}{180} = \frac{5\pi}{6} \) rad.
2Step 2: Compute the x-component
The x-component of the vector can be found using the magnitude of the vector and the cosine of the angle it makes with the positive x-axis. This is given by \( x = \|v\| * cos( \theta ) \). Use the given magnitude \( \|v\| = \frac{7}{2} \) and the converted angle. Therefore, \( x = \frac{7}{2} * cos( \frac{5\pi}{6} ) \). Compute this to obtain the x-component of the vector.
3Step 3: Compute the y-component
The y-component of the vector can be found using the magnitude of the vector and the sine of the angle it makes with the positive x-axis. This is given by \( y = \|v\| * sin( \theta ) \). Use the given magnitude \( \|v\| = \frac{7}{2} \) and the converted angle. Therefore, \( y = \frac{7}{2} * sin( \frac{5\pi}{6} ) \). Compute this to obtain the y-component of the vector.
4Step 4: Component Form of the Vector
The component form of vector \( v \) is given by \( v = \). Substitute the obtained x and y components into this to get the component form.
Key Concepts
Understanding Trigonometric FunctionsAngle Conversion Made EasyDefining Vector Magnitude
Understanding Trigonometric Functions
Trigonometric functions are pivotal when dealing with angles and rotations in mathematics. They help calculate relationships within triangles. In particular, sine and cosine are two core functions:
- Sine (\( \sin \)): This represents the ratio of the opposite side to the hypotenuse in a right-angled triangle.
- Cosine (\( \cos \)): This is the ratio of the adjacent side to the hypotenuse.
Angle Conversion Made Easy
Angles are usually given in degrees, especially in geometric contexts, but calculus and physics often require these angles in radians. Converting degrees to radians is straightforward with the formula:- Multiply the degree value by \( \frac{\pi}{180} \).
This step changes a degree measure into radians, which are more conducive for mathematical analysis as they simplify integral calculus applications. For example, converting \( 150^{\circ} \) involves:\[ 150^{\circ} \times \frac{\pi}{180} = \frac{5\pi}{6} \text{ radians} \].
So, understanding this conversion is crucial for smooth transitions between different mathematical contexts and solving problems accurately.
This step changes a degree measure into radians, which are more conducive for mathematical analysis as they simplify integral calculus applications. For example, converting \( 150^{\circ} \) involves:\[ 150^{\circ} \times \frac{\pi}{180} = \frac{5\pi}{6} \text{ radians} \].
So, understanding this conversion is crucial for smooth transitions between different mathematical contexts and solving problems accurately.
Defining Vector Magnitude
The vector magnitude is essentially the vector's length. Think of a vector as an arrow; the magnitude is how long that arrow is. In mathematics, it is denoted as \( \|\mathbf{v}\| \). It provides key insight into the size of the vector without considering its direction.
- Calculation: Often calculated in relation to its components, using \( \sqrt{x^2 + y^2} \) for a 2D vector.
- Usage: In exercises, magnitude helps determine the vector's reach across dimensions, influencing both the x and y components in our earlier example. Given \( \|\mathbf{v}\| = \frac{7}{2} \) means this vector has a specific half-real-number length, regardless of its direction.
Other exercises in this chapter
Problem 68
Finding a Power of a Complex Number In Exercises \(65-80\) , use DeMoivre's Theorem to find the indicated power of the complex number. Write the result in stand
View solution Problem 69
Finding Orthogonal Vectors In Exercises \(67-70\) , find two vectors in opposite directions that are orthogonal to the vector u. (There are many correct answers
View solution Problem 69
Finding a Power of a Complex Number In Exercises \(65-80\) , use DeMoivre's Theorem to find the indicated power of the complex number. Write the result in stand
View solution Problem 70
Finding Orthogonal Vectors In Exercises \(67-70\) , find two vectors in opposite directions that are orthogonal to the vector u. (There are many correct answers
View solution