Problem 69
Question
Find the derivative of $$ f(x)=\sin ^{2}\left(x^{2}-1\right) $$
Step-by-Step Solution
Verified Answer
The derivative is \( f'(x) = 2x \sin(2x^2 - 2) \).
1Step 1: Identify the Composite Function
The function given is a composite function of the form \( f(x) = g(h(x)) \) where \( g(x) = \sin^2(x) \) and \( h(x) = x^2-1 \). We need to find \( f'(x) \) using the chain rule.
2Step 2: Differentiate the Outer Function
The outer function \( g(x) = \sin^2(x) \) can be rewritten as \( (\sin(x))^2 \). The derivative of \( g(x) \) with respect to \( x \) using the chain rule and power rule is \( 2\sin(x)\cos(x) = \sin(2x) \).
3Step 3: Differentiate the Inner Function
The inner function \( h(x) = x^2 - 1 \) is a simple polynomial. The derivative of \( h(x) \) with respect to \( x \) is \( h'(x) = 2x \).
4Step 4: Apply the Chain Rule
The chain rule states that \( f'(x) = g'(h(x)) \times h'(x) \). Substituting the derivatives we found: \( g'(h(x)) = \sin(2(x^2-1)) \) and \( h'(x) = 2x \). Thus, \( f'(x) = \sin(2(x^2-1)) \times 2x \).
5Step 5: Simplify the Expression
Distributing and simplifying, the derivative is \( f'(x) = 2x \sin(2x^2 - 2) \).
Key Concepts
Composite FunctionChain RuleDerivativeTrigonometric Functions
Composite Function
A composite function is a combination of two functions where one function is applied to the result of another. For the given problem, the function can be expressed as \( f(x) = (\sin(x))^2 \), where \( x \) is replaced by another function, \( x^2 - 1 \). Hence, it takes the form \( f(x) = g(h(x)) \), with \( g(x) = \sin^2(x) \) and \( h(x) = x^2 - 1 \). Composite functions are like layering functions together.
- Identify the two functions separately: the outer function and the inner function.
- In this exercise, \( g(h(x)) \) shows the trigonometric function is applied to the polynomial.
Chain Rule
The chain rule is a fundamental technique in calculus used to differentiate composite functions. It allows us to find the derivative of a composition by differentiating each layer of the function. The key idea is to take the derivative of the outer function and multiply it by the derivative of the inner function.
- The rule can be expressed as: if \( f(x) = g(h(x)) \), then the derivative \( f'(x) = g'(h(x)) \times h'(x) \).
Derivative
Derivatives measure how a function changes as its input changes — essentially, the rate of change or slope of the function at any given point. For polynomials like \( h(x) = x^2 - 1 \), taking the derivative is straightforward:
- The derivative of \( x^2 \) is \( 2x \), and the derivative of a constant is 0.
Trigonometric Functions
Trigonometric functions are key in this exercise. They include functions like sine and cosine, which are periodic and describe waves. The function \( \sin(x) \) specifically describes the y-coordinate of a point on the unit circle. Here, we use the sine function raised to a power, as in \( \sin^2(x) \).
- Remember, \( \sin^2(x) \) is equivalent to \( (\sin(x))^2 \) and follows both power and trigonometric derivative rules.
- The derivative of the sine function is \( \cos(x) \).
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