Problem 69
Question
Evaluate the function for \(x=0,1,2,3,\) and 4. $$f(x)=-x+9 \quad$$
Step-by-Step Solution
Verified Answer
The function \(f(x) = -x + 9\) evaluates to 9, 8, 7, 6, and 5 for \(x = 0, 1, 2, 3, 4\) respectively.
1Step 1: Initialization
The function is given by \(f(x) = -x + 9\). We will evaluate this function for \(x = 0, 1, 2, 3, 4\).
2Step 2: Evaluate \(f(x)\) at \(x=0\)
Replace \(x\) in \(f(x) = -x + 9\) with 0 to find \(f(0) = -(0) + 9 = 9\). So, when \(x = 0\), \(f(x) = 9\).
3Step 3: Evaluate \(f(x)\) at \(x=1\)
Replace \(x\) in \(f(x) = -x + 9\) with 1 to find \(f(1) = -(1) + 9 = 8\). So, when \(x = 1\), \(f(x) = 8\).
4Step 4: Evaluate \(f(x)\) at \(x=2\)
Replace \(x\) in \(f(x) = -x + 9\) with 2 to find \(f(2) = -(2) + 9 = 7\). So, when \(x = 2\), \(f(x) = 7\).
5Step 5: Evaluate \(f(x)\) at \(x=3\)
Replace \(x\) in \(f(x) = -x + 9\) with 3 to find \(f(3) = -(3) + 9 = 6\). So, when \(x = 3\), \(f(x) = 6\).
6Step 6: Evaluate \(f(x)\) at \(x=4\)
Replace \(x\) in \(f(x) = -x + 9\) with 4 to find \(f(4) = -(4) + 9 = 5\). So, when \(x = 4\), \(f(x) = 5\).
Key Concepts
Linear FunctionsEvaluation StepsAlgebraic Expressions
Linear Functions
A linear function is a type of algebraic expression where the highest power of the variable is one. In simple terms, it forms a straight line when graphed on a coordinate plane. Linear functions can be written in the form of \( f(x) = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
- The slope \( m \) determines the steepness or tilt of the line. For example, in the function \( f(x) = -x + 9 \), the slope is \(-1\), indicating the line decreases at a constant rate.
- The y-intercept is the point where the line crosses the y-axis. Here, it is \(9\), meaning the line crosses the y-axis at the point \((0, 9)\).
Evaluation Steps
To evaluate a function, you substitute specific values for the variable \( x \) into the given algebraic expression and then compute the result. Let's look at evaluating the function \( f(x) = -x + 9 \):
- Start by replacing \( x \) with the first value. For example, when \( x = 0 \), you'll have \( f(0) = -0 + 9 = 9 \).
- Continue this process by inserting each subsequent value for \( x \) into the function. When \( x = 1 \), you evaluate it to get \( f(1) = -1 + 9 = 8 \).
- Repeat these steps for \( x = 2, 3, \text{ and } 4 \), which yields \( f(2) = 7 \), \( f(3) = 6 \), \( f(4) = 5 \).
Algebraic Expressions
An algebraic expression is a combination of numbers, variables (like \( x \)), and arithmetic operations such as addition, subtraction, multiplication, and division.
- In \( f(x) = -x + 9 \), the expression consists of the variable \( x \) with a coefficient of \(-1\), and a constant term of \( 9 \).
- To simplify or solve algebraic expressions, you apply arithmetic rules and substitute variables with numbers as needed in evaluation processes.
- These expressions can represent real-world situations, such as calculating distances, costs, or other measurements by inputting the necessary data.
Other exercises in this chapter
Problem 68
Solve the proportion. Check for extraneous solutions. $$\frac{8 b^{2}+4 b}{4 b}=\frac{2 b-5}{3}$$
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Identify the leading coefficient, and classify the polynomial by degree and by number of terms. $$16-4 x+3 x^{2}$$
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Completely factor the expression. $$3 x^{3}+21 x^{2}+30 x$$
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Solve the proportion. Check for extraneous solutions. $$\frac{5 p^{2}-9}{5}=\frac{2 p^{2}+3 p}{2}$$
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