Problem 69
Question
Differentiate each function. \(f(x)=\frac{(x-1)\left(x^{2}+x+1\right)}{x^{4}-3 x^{3}-5}\)
Step-by-Step Solution
Verified Answer
The derivative is \( f'(x) = \frac{-x^6 + 4x^3 - 24x^2}{(x^4 - 3x^3 - 5)^2} \).
1Step 1: Identify the derivative rule to use
The given function is a fraction or rational function of polynomials. To differentiate it, we'll use the quotient rule which states:\[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \]where \( u \) is the numerator \( (x-1)(x^2+x+1) \) and \( v \) is the denominator \( x^4-3x^3-5 \).
2Step 2: Differentiate the Numerator
First, expand the numerator function \( u=(x-1)(x^2+x+1) \) into a polynomial:\[ u = x^3 + x^2 + x - x^2 - x - 1 = x^3 - 1 \]Now, find the derivative of \( u \):\[ u' = \frac{d}{dx}(x^3 - 1) = 3x^2 \].
3Step 3: Differentiate the Denominator
Differentiate the denominator function \( v = x^4 - 3x^3 - 5 \):\[ v' = \frac{d}{dx}(x^4 - 3x^3 - 5) = 4x^3 - 9x^2 \].
4Step 4: Apply the Quotient Rule
Substitute \( u \), \( u' \), \( v \), and \( v' \) into the quotient rule formula:\[ f'(x) = \frac{(3x^2)(x^4 - 3x^3 - 5) - (x^3 - 1)(4x^3 - 9x^2)}{(x^4 - 3x^3 - 5)^2} \].
5Step 5: Simplify the Derivative Expression
Expand and simplify the expression. Calculate the terms:1. \( 3x^2(x^4 - 3x^3 - 5) = 3x^6 - 9x^5 - 15x^2 \)2. \( (x^3 - 1)(4x^3 - 9x^2) = 4x^6 - 9x^5 - 4x^3 + 9x^2 \)Now combine:\[ f'(x) = \frac{3x^6 - 9x^5 - 15x^2 - 4x^6 + 9x^5 + 4x^3 - 9x^2}{(x^4 - 3x^3 - 5)^2} \]Simplify the expression:\[ f'(x) = \frac{-x^6 + 4x^3 - 24x^2}{(x^4 - 3x^3 - 5)^2} \].
Key Concepts
Derivative of Rational FunctionsPolynomial DifferentiationSimplifying Derivatives
Derivative of Rational Functions
Rational functions are quotients where both the numerator and the denominator are polynomials. The process of finding their derivatives requires special rules beyond basic differentiation. The quotient rule is specifically designed to deal with such situations. It simplifies the process by providing a structured formula:
- For a given function \( f(x) = \frac{u}{v} \), the derivative \( f'(x) \) is calculated using the formula \( f'(x) = \frac{u'v - uv'}{v^2} \).
- Here, \( u \) and \( v \) represent the numerator and the denominator, respectively.
- Differentiating the numerator \( u \) to get \( u' \).
- Differentiating the denominator \( v \) to get \( v' \).
- Then substitute \( u \), \( u' \), \( v \), and \( v' \) into the quotient rule formula.
Polynomial Differentiation
Polynomials are expressions consisting of variables raised to whole number powers and their constant coefficients. The differentiation of polynomials is foundational, involving rules such as the power rule. The process is fairly straightforward:
- For a term \( ax^n \), its derivative is found using the power rule: \( \frac{d}{dx}(ax^n) = nax^{n-1} \).
- Each term in the polynomial is differentiated individually, and then they're combined together again.
- First, it is expanded to a single polynomial \( x^3 - 1 \).
- Then differentiated term by term, here yielding \( 3x^2 \) for the derivative.
Simplifying Derivatives
After applying the quotient rule, simplifying the resulting expression can often be the most challenging yet crucial step. Simplification involves systematically reducing the expression to its simplest form:
- Begin by carefully expanding products using the distributive property. In our example: \( 3x^2(x^4 - 3x^3 - 5) \) becomes \( 3x^6 - 9x^5 - 15x^2 \).
- Follow similarly for the other expansion \((x^3 - 1)(4x^3 - 9x^2)\).
- Combine like terms from these expansions to finalize the numerator.
Other exercises in this chapter
Problem 69
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