Problem 69
Question
Describe how to locate the foci of the graph of \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\) Describe one similarity and one difference between the graphs of \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\) and \(\frac{y^{2}}{9}-\frac{x^{2}}{1}=1\)
Step-by-Step Solution
Verified Answer
The foci of the given hyperbola \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\) are located at (\(\pm \sqrt{10},0\)). The two hyperbolas are similar in that they both have the same absolute values for a and b, that determine the x and y intercepts, but they differ in the way they are oriented. The first hyperbola is horizontal, while the second one is vertical.
1Step 1: Identifying the hyperbola
Given \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\), it's clear that the equation is that of a hyperbola since one term is subtracted from the other. Here the x-term is positive so it's a horizontal hyperbola.
2Step 2: Locating the foci of the hyperbola
For a hyperbola, the distance from the center to each focus is given by \(c=\sqrt{a^{2}+b^{2}}\). Here, \(a^2 = 9\) and \(b^2=1\), so \(c = \sqrt{9+1} = \sqrt{10}\). Hence the foci of the hyperbola \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\) are located at (\(\pm \sqrt{10},0\)).
3Step 3: Comparing the two hyperbolas
The equation \(\frac{y^{2}}{9}-\frac{x^{2}}{1}=1\) is also a hyperbola, but with the y-term being positive, hence it's a vertical hyperbola. The similarity lies in the fact that both are hyperbolas and have the same absolute values for a and b (which determine the x and y intercepts respectively). The difference is simply the orientation of these hyperbolas - the first hyperbola is oriented horizontally while the second is oriented vertically.
Key Concepts
Understanding Foci of a HyperbolaDefining a Horizontal HyperbolaRecognizing a Vertical HyperbolaExploring the Distance Formula in Hyperbolas
Understanding Foci of a Hyperbola
The foci (plural of focus) are special points located along the axis of a hyperbola. These points play a critical role in defining the shape and properties of the hyperbola itself. In mathematics, for a given hyperbola, the distance from the center to each focus is calculated using the formula: \[ c = \sqrt{a^{2} + b^{2}} \]
- The variable \(a\) is associated with the squared term of the variable that has a positive coefficient.
- The variable \(b\) is associated with the squared term of the variable that has a negative coefficient.
Defining a Horizontal Hyperbola
A horizontal hyperbola is characterized by the placement of its transverse axis along the x-axis. In technical terms, if the x-term is positive in the hyperbola's equation, the hyperbola opens horizontally.
Consider the equation: \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \). Here:
Consider the equation: \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \). Here:
- The positive \(x^2\) term indicates a horizontal orientation.
- The foci are positioned on a horizontal line parallel to the x-axis at \( \pm c \).
Recognizing a Vertical Hyperbola
A vertical hyperbola has its transverse axis positioned along the y-axis, distinguishing it from the horizontal orientation. If the y-term is positive in the hyperbola's equation, the hyperbola is vertical.
Consider the equation: \( \frac{y^{2}}{a^{2}} - \frac{x^{2}}{b^{2}} = 1 \). Here:
Consider the equation: \( \frac{y^{2}}{a^{2}} - \frac{x^{2}}{b^{2}} = 1 \). Here:
- The positive \(y^2\) term dictates a vertical orientation.
- The vertices and foci are located along the vertical y-axis, positioned vertically at \( \pm c \).
Exploring the Distance Formula in Hyperbolas
The distance formula is essential to finding the positions of the foci in a hyperbola. It provides a method to calculate the exact distance from the center to each focus, ensuring the correct geometry is maintained. The formula used is: \[ c = \sqrt{a^{2} + b^{2}} \]
- \(a\) and \(b\) are derived from the denominators in the hyperbola equation \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \).
- \(a^{2} = 9\) represents the larger axis, while \(b^{2} = 1\) relates to the minor axis.
Other exercises in this chapter
Problem 69
What is a parabola?
View solution Problem 69
What is an ellipse?
View solution Problem 70
Explain how to use \(y^{2}=8 x\) to find the parabola's focus and directrix.
View solution Problem 70
Describe how to graph \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1\)
View solution